s given by my friend pls solve (Im pre foundation so I dont understand shit here)ON INTEGRATION20. The acceleration a in ms−2, of a particle is given by a=3t2+2t+2, where t is the time. If the particle starts out with a velocity v=2ms−1 at t=0, then the velocity at the end of 2s is(a) 12ms−1(b) 14ms−1(c) 16ms−1(d) ms−2021. A point Initially at rest moves along X-axis. Its acceleration varies with time as ms−21. If it22. If the velocity of a particle is ms−22, Where ms−23 and ms−24 are constants, then the distance travelled by It between is and 2s is(a) ms−26(b) ms−27(c) ms−28 (d) ms−2923. The acceleration of a particle Increasing linearly with time a=3t2+2t+20. The particle starts from origin with an Initial velocity a=3t2+2t+21. The distance travelled by the particle In time t will be(a) a=3t2+2t+23(b) a=3t2+2t+24(c) a=3t2+2t+25(d) a=3t2+2t+2624. The velocity of a particle is a=3t2+2t+27. If its position a=3t2+2t+28, at t=0, then its displacement after unit time t0 is(a)t1(b) t2(c) t3(d) t425. A particle moving along x-axis has acceleration a, at time t, given by t7, here t8 and t9 are constants. The particle at t=0 has zero velocity. In the time interval between t=0 and the instant when v=2ms−12, the particle velocity v=2ms−13 is(a)v=2ms−14(b) v=2ms−15(c) v=2ms−16(d) v=2ms−1726. A particle located at v=2ms−18 at time t=0, starts moving along the positive x-direction with a velocity t=00 that varies as t=01. The displacement of the particle varies with time as(a) t=02(b) t=03(c) t=04 (d) t=0527. The velocity of particle moving in the positive direction of X-axis varies as t=06, where t=07 is a positive constant. Assuming that at moment t=0, the particle was located at the point v=2ms−18. Find (i) the time dependence of the position (ii) the time dependence of the velocity of the particle. (ii) the mean velocity of the particle averaged over the time that the particle takes to cover first 's' meters of the path [Ans: (i) 2s0 (ii) 2s1 (iii) 2s2] Get tutor helpx=v∘t+21at2The horizontal displacement, x, of an object with constant acceleration, a, initial velocity, v∘, at elapsed time, t, is given by the equation. Which of the following equations correctly shows the acceleration in terms of displacement, initial velocity, and time?Choose 1 answer:(A) a=t2x−v∘t(B) a=t2(x−v0)(C) a=t22(x−v∘t)(D) a=v0t32x Get tutor help