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An object travels along a straight line. The function s(t)=3t43+6t13s(t) = 3t^{\frac{4}{3}} + 6t^{\frac{1}{3}} gives the object's position, in feet, at time tt minutes.\newlineWrite a function that gives the object's velocity v(t)v(t) in feet per minute.\newlinev(t)=v(t) = ______

Full solution

Q. An object travels along a straight line. The function s(t)=3t43+6t13s(t) = 3t^{\frac{4}{3}} + 6t^{\frac{1}{3}} gives the object's position, in feet, at time tt minutes.\newlineWrite a function that gives the object's velocity v(t)v(t) in feet per minute.\newlinev(t)=v(t) = ______
  1. Differentiate position function: To find the velocity function v(t)v(t), we need to differentiate the position function s(t)s(t) with respect to time tt.
  2. Combine terms for velocity: Combine the differentiated terms to form the velocity function v(t)v(t).

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