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An object travels along a straight line. The function v(t)=t15+2t2v(t) = - t^{\frac{1}{5}} + 2t^{-2} gives the object's velocity, in feet per minute, at time t>0t > 0 minutes.\newlineWrite a function that gives the object's acceleration a(t)a(t) in feet per minute per minute.\newlinea(t) = ______

Full solution

Q. An object travels along a straight line. The function v(t)=t15+2t2v(t) = - t^{\frac{1}{5}} + 2t^{-2} gives the object's velocity, in feet per minute, at time t>0t > 0 minutes.\newlineWrite a function that gives the object's acceleration a(t)a(t) in feet per minute per minute.\newlinea(t) = ______
  1. Differentiate Power Rule: To find the acceleration function a(t)a(t), we need to differentiate the velocity function v(t)v(t) with respect to time tt.
  2. Differentiate 2t22t^{-2}: Differentiate each term of v(t)v(t) separately. For the first term, t1/5-t^{1/5}, use the power rule: ddt\frac{d}{dt} of tn=ntn1t^n = n*t^{n-1}. Here, n=15n = \frac{1}{5}.
  3. Combine Derivatives: For the second term, 2t22t^{-2}, again use the power rule.
  4. Find Acceleration Function: Combine the derivatives to get the acceleration function a(t)a(t).

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