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An object travels along a straight line. The function v(t)=3t4t2+tv(t) = 3\sqrt{t} - 4t^2 + t gives the object's velocity, in feet per hour, at time tt hours.\newlineWrite a function that gives the object's acceleration a(t)a(t) in feet per hour per hour.\newlinea(t) = ______

Full solution

Q. An object travels along a straight line. The function v(t)=3t4t2+tv(t) = 3\sqrt{t} - 4t^2 + t gives the object's velocity, in feet per hour, at time tt hours.\newlineWrite a function that gives the object's acceleration a(t)a(t) in feet per hour per hour.\newlinea(t) = ______
  1. Differentiate velocity function: To find the acceleration function a(t)a(t), we need to differentiate the velocity function v(t)v(t) with respect to time tt.
  2. Combine derivatives for acceleration: Combine the derivatives to form the acceleration function a(t)a(t).

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