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An object travels along a straight line. The function v(t)=2t6t3v(t) = 2\sqrt{t} - 6\sqrt[3]{t} gives the object's velocity, in meters per second, at time tt seconds.\newlineWrite a function that gives the object's acceleration a(t)a(t) in meters per second per second.\newlinea(t) = ______

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Q. An object travels along a straight line. The function v(t)=2t6t3v(t) = 2\sqrt{t} - 6\sqrt[3]{t} gives the object's velocity, in meters per second, at time tt seconds.\newlineWrite a function that gives the object's acceleration a(t)a(t) in meters per second per second.\newlinea(t) = ______
  1. Identify velocity function: Identify the velocity function and recognize the need to differentiate it to find acceleration. \newlinev(t)=2t6t3v(t) = 2\sqrt{t} - 6\sqrt[3]{t}\newlineWe need to differentiate v(t)v(t) to find a(t)a(t), the acceleration function.
  2. Differentiate each term: Differentiate each term of v(t)v(t) separately.\newlineFor the first term, 2t2\sqrt{t}, the derivative is 2×(1/2)×t1/2=t1/22 \times (1/2) \times t^{-1/2} = t^{-1/2}.\newlineFor the second term, 6t3-6\sqrt[3]{t}, the derivative is 63,-6\sqrt[3]{}, since the derivative of tt with respect to tt is 11.

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