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An object travels along a straight line. The function s(t)=−32t2−6t+45s(t) = -32t^2 - 6t + 45 gives the object's position, in feet, at time tt seconds.\newlineWrite a function that gives the object's velocity v(t)v(t) in feet per second.\newlinev(t) = ______

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Relate position, velocity, speed, and acceleration using derivativesright chevron icon

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Q. An object travels along a straight line. The function s(t)=−32t2−6t+45s(t) = -32t^2 - 6t + 45 gives the object's position, in feet, at time tt seconds.\newlineWrite a function that gives the object's velocity v(t)v(t) in feet per second.\newlinev(t) = ______
  1. Differentiate s(t)s(t) for v(t)v(t): To find the velocity function v(t)v(t), we need to differentiate the position function s(t)s(t) with respect to time tt.

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