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An object travels along a straight line. The function v(t)=4t43t311t+3v(t) = 4t^4 - 3t^3 - 11t + 3 gives the object's velocity, in feet per hour, at time tt hours.\newlineWrite a function that gives the object's acceleration a(t)a(t) in feet per hour per hour.\newlinea(t) = ______

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Q. An object travels along a straight line. The function v(t)=4t43t311t+3v(t) = 4t^4 - 3t^3 - 11t + 3 gives the object's velocity, in feet per hour, at time tt hours.\newlineWrite a function that gives the object's acceleration a(t)a(t) in feet per hour per hour.\newlinea(t) = ______
  1. Identify Velocity Function: Identify the velocity function and the need to differentiate it to find acceleration.\newlineThe velocity function v(t)=4t43t311t+3v(t) = 4t^4 - 3t^3 - 11t + 3 needs to be differentiated to find the acceleration function a(t)a(t).\newlineDifferentiate each term of v(t)v(t) with respect to tt.
  2. Differentiate 4t44t^4: Differentiate the first term 4t44t^4. Using the power rule, the derivative of 4t44t^4 is 16t316t^3.
  3. Differentiate 3t3-3t^3: Differentiate the second term 3t3-3t^3. Using the power rule, the derivative of 3t3-3t^3 is 9t2-9t^2.
  4. Differentiate 11t-11t: Differentiate the third term 11t-11t. Using the power rule, the derivative of 11t-11t is 11-11.
  5. Differentiate Constant Term: Differentiate the constant term +3+3. The derivative of a constant is 00.
  6. Combine Differentiated Terms: Combine all the differentiated terms to form the acceleration function. \newlinea(t)=16t39t211+0a(t) = 16t^3 - 9t^2 - 11 + 0\newlineSimplify to a(t)=16t39t211a(t) = 16t^3 - 9t^2 - 11.

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