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An object travels along a straight line. The function s(t)=4t5+10t4+7t3+t+11s(t) = -4t^5 + 10t^4 + 7t^3 + t + 11 gives the object's position, in meters, at time tt seconds.\newlineWrite a function that gives the object's velocity v(t)v(t) in meters per second.\newlinev(t)=v(t) = ______

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Q. An object travels along a straight line. The function s(t)=4t5+10t4+7t3+t+11s(t) = -4t^5 + 10t^4 + 7t^3 + t + 11 gives the object's position, in meters, at time tt seconds.\newlineWrite a function that gives the object's velocity v(t)v(t) in meters per second.\newlinev(t)=v(t) = ______
  1. Differentiate s(t)s(t): To find the velocity function v(t)v(t), we need to differentiate the position function s(t)s(t) with respect to time tt.
  2. Derivatives of terms: Differentiate each term of s(t)s(t) separately:\newline- The derivative of 4t5-4t^5 is 20t4-20t^4.\newline- The derivative of 10t410t^4 is 40t340t^3.\newline- The derivative of 7t37t^3 is 21t221t^2.\newline- The derivative of tt is 11.\newline- The derivative of 1111 is 4t5-4t^500, since it's a constant.

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