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Math Problems
Precalculus
Find the roots of factored polynomials
Remaining Time:
276
276
276
:
21
21
21
:
52
52
52
\newline
Solve the quadratic equation below. If the solutions are not real, enter NA.
\newline
15
x
2
−
x
−
2
=
0
15 x^{2}-x-2=0
15
x
2
−
x
−
2
=
0
\newline
The field below accepts a list of numbers or formulas separated by semicolons (e.g.
2
;
4
;
6
2 ; 4 ; 6
2
;
4
;
6
x
+
1
;
x
−
1
)
x+1 ; x-1)
x
+
1
;
x
−
1
)
. The order of the list does not matter.
\newline
To enter
a
\sqrt{a}
a
, type
sqrt
(
a
)
\operatorname{sqrt}(\mathrm{a})
sqrt
(
a
)
.
\newline
x
=
x=
x
=
Get tutor help
Consider the equation
\newline
0.75
×
1
0
(
w
3
)
=
30
0.75\times10^{\left(\frac{w}{3}\right)}=30
0.75
×
1
0
(
3
w
)
=
30
\newline
Solve the equation for
\newline
w
w
w
. Express the solution as a logarithm in base
−
10
-10
−
10
.
\newline
w
=
w=
w
=
\newline
□
\square
□
\newline
Approximate the value of
\newline
w
w
w
. Round your answer to the nearest thousandth.
\newline
w
≈
w\approx
w
≈
Get tutor help
If
x
2
−
y
2
=
24
x^{2}-y^{2}=24
x
2
−
y
2
=
24
,
x
+
y
=
8
x+y=8
x
+
y
=
8
, then
3
x
−
3
y
=
3x-3y=
3
x
−
3
y
=
Get tutor help
What value of
x
x
x
is the solution to the equation
\newline
x
−
4
2
=
x
−
13
\frac{x-4}{2}=x-13
2
x
−
4
=
x
−
13
?
\newline
Enter your answer in the space provided.
\newline
x
=
x=
x
=
□
\square
□
Get tutor help
Solve for
x
x
x
. Enter the solutions from least to greatest.
\newline
6
x
2
−
18
x
−
240
=
0
6x^{2}-18x-240=0
6
x
2
−
18
x
−
240
=
0
\newline
lesser
x
=
x=
x
=
\newline
greater
x
=
x=
x
=
Get tutor help
Solve for
x
x
x
\newline
−
56
+
x
4
=
−
8
\frac{-56+x}{4}=-8
4
−
56
+
x
=
−
8
\newline
simplify your answer as mu
\newline
x
=
x=
x
=
Get tutor help
classroom.google.com/c/NTUONTI
2
2
2
NTY
\newline
.. Apple Music
\newline
tions: Find the value of
\newline
x
=
x=
x
=
\newline
y
=
y=
y
=
Get tutor help
1
1
1
.
1.5
p
1.5 p
1.5
p
\newline
Let
f
(
x
)
=
(
x
−
3
)
−
2
f(x)=(x-3)^{-2}
f
(
x
)
=
(
x
−
3
)
−
2
. Find all values of
c
c
c
in
(
1
,
4
)
(1,4)
(
1
,
4
)
such that
f
(
4
)
−
f
(
1
)
=
f
′
(
c
)
(
4
−
1
)
f(4)-f(1)=f^{\prime}(c)(4-1)
f
(
4
)
−
f
(
1
)
=
f
′
(
c
)
(
4
−
1
)
. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.)
\newline
c
=
c=
c
=
Get tutor help
-- ixl.com/mathigrade
−
8
-8
−
8
/find-missing-side-lengths-in-propo
\newline
NWEA
\newline
math
\newline
Find
V
W
V W
VW
.
\newline
V
W
=
V W=
VW
=
Get tutor help
The polynomial
p
(
x
)
=
3
x
3
−
5
x
2
−
4
x
+
4
p(x)=3 x^{3}-5 x^{2}-4 x+4
p
(
x
)
=
3
x
3
−
5
x
2
−
4
x
+
4
has a known factor of
(
x
−
2
)
(x-2)
(
x
−
2
)
.
\newline
Rewrite
p
(
x
)
p(x)
p
(
x
)
as a product of linear factors.
\newline
p
(
x
)
=
p(x)=
p
(
x
)
=
\newline
□
\square
□
Get tutor help
Unit
7
7
7
Target
3
3
3
Writing Exponential E Algebra
1
1
1
\newline
Write the equation for the exponential
\newline
1
1
1
.
\newline
\begin{tabular}{|c|c|}
\newline
\hline
x
x
x
&
y
y
y
\\
\newline
\hline
−
2
-2
−
2
&
−
18
-18
−
18
\\
\newline
\hline
−
1
-1
−
1
&
−
6
-6
−
6
\\
\newline
\hline
0
0
0
&
−
2
-2
−
2
\\
\newline
\hline
1
1
1
&
−
2
/
3
-2 / 3
−
2/3
\\
\newline
\hline
\newline
\end{tabular}
\newline
2
2
2
.
\newline
y
=
y=
y
=
\qquad
\newline
y
=
\mathbf{y}=
y
=
\newline
4
4
4
.
\newline
5
5
5
.
Get tutor help
Complete the point-slope equation of the line through
(
−
1
,
6
)
(-1,6)
(
−
1
,
6
)
and
(
1
,
5
)
(1,5)
(
1
,
5
)
.
\newline
Use exact numbers.
\newline
y
−
6
=
y-6=
y
−
6
=
\newline
□
\square
□
Get tutor help
(
3
y
2
+
2
)
d
y
d
x
=
1
\left(3 y^{2}+2\right) \frac{d y}{d x}=1
(
3
y
2
+
2
)
d
x
d
y
=
1
and
y
(
−
1
)
=
1
y(-1)=1
y
(
−
1
)
=
1
.
\newline
What is
x
x
x
when
y
=
2
y=2
y
=
2
?
\newline
x
=
x=
x
=
Get tutor help
Determine an equation for the pictured graph. Write your answer in factored form.
\newline
Remember to start with
f
(
x
)
=
a
(
x
−
r
1
)
(
x
−
r
2
)
…
\mathrm{f}(\mathrm{x})=a\left(x-r_{1}\right)\left(x-r_{2}\right) \ldots
f
(
x
)
=
a
(
x
−
r
1
)
(
x
−
r
2
)
…
\newline
y
=
y=
y
=
Get tutor help
c. Sketch a graph that represents the function
f
f
f
and shows
f
(
0
)
,
f
(
1
)
f(0), f(1)
f
(
0
)
,
f
(
1
)
, and
f
(
2
)
f(2)
f
(
2
)
.
\newline
Use your cursor to draw on the
Get tutor help
B
→
5
B \rightarrow 5
B
→
5
\newline
2
2
2
. Arrange the following numbers in the descending order.
\newline
a)
\newline
18
>
17
>
18>17>
18
>
17
>
\newline
15
>
15>
15
>
\newline
11
11
11
\newline
b)
\newline
c)
Get tutor help
10
10
10
The mass of Earth is
5.98
×
1
0
24
k
g
5.98 \times 10^{24} \mathrm{~kg}
5.98
×
1
0
24
kg
.
\newline
a When you write this mass in full, how many zeros does it have?
\newline
b The mass of Mars is approximately
1
10
\frac{1}{10}
10
1
of the mass of Earth. Write the mass of Mars in standard form.
Get tutor help
www-awu.aleks.com
\newline
Equations and Inequalities
\newline
Solving a proportion of the form
(
x
+
a
)
/
b
=
c
/
d
(x+a) / b=c / d
(
x
+
a
)
/
b
=
c
/
d
\newline
Solve for
v
v
v
.
\newline
v
−
5
6
=
3
4
\frac{v-5}{6}=\frac{3}{4}
6
v
−
5
=
4
3
\newline
Simplify your answer as much as possible.
\newline
v
=
v=
v
=
Get tutor help
Solve the following equation for
x
x
x
. Express your answer in the simplest form.
\newline
4
+
3
(
−
6
x
+
6
)
=
9
+
4
(
8
x
−
6
)
4+3(-6 x+6)=9+4(8 x-6)
4
+
3
(
−
6
x
+
6
)
=
9
+
4
(
8
x
−
6
)
\newline
Get tutor help
Solve the following equation for
x
x
x
. Express your answer in the simplest form.
\newline
−
8
−
5
(
6
x
−
2
)
=
−
7
(
5
x
−
6
)
+
5
-8-5(6 x-2)=-7(5 x-6)+5
−
8
−
5
(
6
x
−
2
)
=
−
7
(
5
x
−
6
)
+
5
\newline
Get tutor help
Solve the following equation for
x
x
x
. Express your answer in the simplest form.
\newline
−
3
x
+
5
(
9
x
+
1
)
=
−
2
−
6
(
−
4
x
−
9
)
-3 x+5(9 x+1)=-2-6(-4 x-9)
−
3
x
+
5
(
9
x
+
1
)
=
−
2
−
6
(
−
4
x
−
9
)
\newline
Get tutor help
A curve has equation
y
=
1
60
(
3
x
+
1
)
2
y=\frac{1}{60}(3x+1)^{2}
y
=
60
1
(
3
x
+
1
)
2
and a point is moving along the curve. Find the
x
x
x
-coordinate of the point on the curve at which the
x
x
x
- and
y
y
y
-coordinates are increasing at the same rate.
\quad
Get tutor help
In circle
Q
,
Q
R
=
12
Q, Q R=12
Q
,
QR
=
12
and
m
∠
R
Q
S
=
2
0
∘
\mathrm{m} \angle R Q S=20^{\circ}
m
∠
RQS
=
2
0
∘
. Find the length of
R
S
R S
RS
. Express your answer as a fraction times
π
\pi
π
.
Get tutor help
5
5
5
. The three rectingles below are similar. Find the missing measurements (
p
t
p t
pt
.)
\newline
a
=
a=
a
=
\qquad
b
=
b=
b
=
Get tutor help
Complete the equation of the line through
(
3
,
−
8
)
(3, -8)
(
3
,
−
8
)
and
(
6
,
−
4
)
(6, -4)
(
6
,
−
4
)
. Use exact numbers.
У
=
У =
У
=
Get tutor help
If
f
(
1
)
=
9
f(1)=9
f
(
1
)
=
9
and
f
(
n
)
=
f
(
n
−
1
)
+
3
f(n)=f(n-1)+3
f
(
n
)
=
f
(
n
−
1
)
+
3
then find the value of
f
(
4
)
f(4)
f
(
4
)
.
\newline
Answer:
Get tutor help
If
f
(
1
)
=
4
f(1)=4
f
(
1
)
=
4
and
f
(
n
)
=
f
(
n
−
1
)
−
5
f(n)=f(n-1)-5
f
(
n
)
=
f
(
n
−
1
)
−
5
then find the value of
f
(
4
)
f(4)
f
(
4
)
.
\newline
Answer:
Get tutor help
If
f
(
1
)
=
4
f(1)=4
f
(
1
)
=
4
and
f
(
n
)
=
f
(
n
−
1
)
+
3
f(n)=f(n-1)+3
f
(
n
)
=
f
(
n
−
1
)
+
3
then find the value of
f
(
5
)
f(5)
f
(
5
)
.
\newline
Answer:
Get tutor help
Solve the following equation for
x
x
x
. Express your answer in the simplest form.
\newline
3
x
+
6
=
−
3
(
−
x
−
2
)
3 x+6=-3(-x-2)
3
x
+
6
=
−
3
(
−
x
−
2
)
\newline
Get tutor help
Solve the following equation for
x
x
x
. Express your answer in the simplest form.
\newline
−
2
(
3
x
−
1
)
=
−
6
x
+
2
-2(3 x-1)=-6 x+2
−
2
(
3
x
−
1
)
=
−
6
x
+
2
\newline
Get tutor help
Solve the following equation for
x
x
x
. Express your answer in the simplest form.
\newline
5
(
3
x
+
3
)
=
5
(
3
x
+
3
)
5(3 x+3)=5(3 x+3)
5
(
3
x
+
3
)
=
5
(
3
x
+
3
)
\newline
Get tutor help
Question
\newline
Watch Video
\newline
Show Examples
\newline
In the diagram below,
S
T
‾
\overline{S T}
ST
is parallel to
P
Q
‾
.
R
S
=
13.3
,
R
T
=
6.7
\overline{P Q} . R S=13.3, R T=6.7
PQ
.
RS
=
13.3
,
RT
=
6.7
, and
S
P
=
10.7
S P=10.7
SP
=
10.7
. Find the length of
T
Q
‾
\overline{T Q}
TQ
. Round your answer to the nearest tenth if necessary.
Get tutor help
Solve for
x
x
x
.\ Enter the solutions from least to greatest.
\newline
(
x
+
6
)
(
−
x
+
1
)
=
0
(x+6)(-x+1)=0
(
x
+
6
)
(
−
x
+
1
)
=
0
\newline
lesser
\newline
x=__________
\newline
greater
\newline
x=___________
Get tutor help
Complete the point-slope equation of the line through
(
−
9
,
6
)
(-9,6)
(
−
9
,
6
)
and
(
−
7
,
−
8
)
(-7,-8)
(
−
7
,
−
8
)
.
\newline
Use exact numbers.
\newline
y
−
6
=
y-6=
y
−
6
=
\newline
□
\square
□
Get tutor help
Complete the point-slope equation of the line through
(
−
5
,
4
)
(-5,4)
(
−
5
,
4
)
and
(
1
,
6
)
(1,6)
(
1
,
6
)
.
\newline
Use exact numbers.
\newline
y
−
6
=
□
y-6= \square
y
−
6
=
□
\newline
Get tutor help
Complete the point-slope equation of the line through
(
−
1
,
6
)
(-1,6)
(
−
1
,
6
)
and
(
1
,
5
)
(1,5)
(
1
,
5
)
.
\newline
Use exact numbers.
\newline
y
−
6
=
□
y - 6 = \square
y
−
6
=
□
Get tutor help
Match each rule below with its corresponding graph. Can you do this without making any tables? Explain your selections.
\newline
a.
y
=
−
x
2
−
2
y=-x^{2}-2
y
=
−
x
2
−
2
\newline
b.
y
=
x
2
−
2
y=x^{2}-2
y
=
x
2
−
2
\newline
c.
y
=
−
x
2
+
2
y=-x^{2}+2
y
=
−
x
2
+
2
\newline
1
1
1
.
\newline
2
2
2
.
\newline
3
3
3
.
Get tutor help
2
2
2
. For EACA of the problems below, write an equati
\newline
a.
\newline
\begin{tabular}{|c|c|}
\newline
\hline
x
x
x
&
y
y
y
\\
\newline
\hline
0
0
0
&
0
0
0
.
5
5
5
\\
\newline
\hline
1
1
1
&
3
3
3
\\
\newline
\hline
2
2
2
&
18
18
18
\\
\newline
\hline
3
3
3
&
108
108
108
\\
\newline
\hline
\newline
\end{tabular}
\newline
y
=
y=
y
=
\newline
Check that your equation works:
Get tutor help
Find the argument of the complex number
9
+
3
3
i
9+3 \sqrt{3} i
9
+
3
3
i
in the interval
0
≤
θ
<
2
π
0 \leq \theta<2 \pi
0
≤
θ
<
2
π
.
\newline
Express your answer in terms of
π
\pi
π
.
\newline
Answer:
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
−
6
cos
2
θ
−
5
cos
θ
=
1
-6 \cos ^{2} \theta-5 \cos \theta=1
−
6
cos
2
θ
−
5
cos
θ
=
1
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
cos
2
θ
−
cos
θ
=
0
\cos ^{2} \theta-\cos \theta=0
cos
2
θ
−
cos
θ
=
0
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
6
sin
2
θ
−
5
sin
θ
+
4
=
3
6 \sin ^{2} \theta-5 \sin \theta+4=3
6
sin
2
θ
−
5
sin
θ
+
4
=
3
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
cot
2
θ
+
4
cot
θ
+
3
=
0
\cot ^{2} \theta+4 \cot \theta+3=0
cot
2
θ
+
4
cot
θ
+
3
=
0
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
−
2
cos
2
θ
−
3
cos
θ
=
1
-2 \cos ^{2} \theta-3 \cos \theta=1
−
2
cos
2
θ
−
3
cos
θ
=
1
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
−
4
cos
2
θ
+
13
cos
θ
−
5
=
9
cos
θ
−
8
-4 \cos ^{2} \theta+13 \cos \theta-5=9 \cos \theta-8
−
4
cos
2
θ
+
13
cos
θ
−
5
=
9
cos
θ
−
8
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
cos
2
θ
−
cos
θ
−
12
=
0
\cos ^{2} \theta-\cos \theta-12=0
cos
2
θ
−
cos
θ
−
12
=
0
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
cot
2
θ
−
5
cot
θ
+
6
=
0
\cot ^{2} \theta-5 \cot \theta+6=0
cot
2
θ
−
5
cot
θ
+
6
=
0
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
7
sin
2
θ
−
3
=
4
sin
θ
7 \sin ^{2} \theta-3=4 \sin \theta
7
sin
2
θ
−
3
=
4
sin
θ
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
sin
2
θ
−
4
sin
θ
−
5
=
0
\sin ^{2} \theta-4 \sin \theta-5=0
sin
2
θ
−
4
sin
θ
−
5
=
0
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
7
7
7
−
20
-20
−
20
. The, area of the rectangle below is
8
1
4
8 \frac{1}{4}
8
4
1
square inches. Find the perimeter. Show your work.
\newline
Width is
4
1
2
i
n
4 \frac{1}{2} \mathrm{in}
4
2
1
in
.
Get tutor help
1
2
3
...
6
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