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Find all angles, 
0^(@) <= theta < 360^(@), that satisfy the equation below, to the nearest tenth of a degree.

7sin^(2)theta-3=4sin theta
Answer: 
theta=

Find all angles, 0θ<360 0^{\circ} \leq \theta<360^{\circ} , that satisfy the equation below, to the nearest tenth of a degree.\newline7sin2θ3=4sinθ 7 \sin ^{2} \theta-3=4 \sin \theta \newlineAnswer: θ= \theta=

Full solution

Q. Find all angles, 0θ<360 0^{\circ} \leq \theta<360^{\circ} , that satisfy the equation below, to the nearest tenth of a degree.\newline7sin2θ3=4sinθ 7 \sin ^{2} \theta-3=4 \sin \theta \newlineAnswer: θ= \theta=
  1. Rewrite Equation: Rewrite the given equation in a standard quadratic form.\newlineWe have the equation 7sin2(θ)3=4sin(θ)7\sin^2(\theta) - 3 = 4\sin(\theta). To solve for θ\theta, we need to rearrange the equation into a standard quadratic form, ax2+bx+c=0ax^2 + bx + c = 0, where xx is sin(θ)\sin(\theta).\newline7sin2(θ)4sin(θ)3=07\sin^2(\theta) - 4\sin(\theta) - 3 = 0
  2. Factor Quadratic: Factor the quadratic equation.\newlineWe need to factor the quadratic equation 7sin2(θ)4sin(θ)3=07\sin^2(\theta) - 4\sin(\theta) - 3 = 0. This can be done by looking for two numbers that multiply to give 21-21 (7×37 \times -3) and add to give 4-4. These numbers are 7-7 and 33.\newline(7sin(θ)+3)(sin(θ)1)=0(7\sin(\theta) + 3)(\sin(\theta) - 1) = 0
  3. Solve Factors: Solve each factor for sin(θ)\sin(\theta). We now have two factors that can be set to zero to solve for sin(θ)\sin(\theta): 7sin(θ)+3=07\sin(\theta) + 3 = 0 or sin(θ)1=0\sin(\theta) - 1 = 0 Solving each equation for sin(θ)\sin(\theta) gives us: sin(θ)=37\sin(\theta) = -\frac{3}{7} or sin(θ)=1\sin(\theta) = 1
  4. Find sin(θ)=37\sin(\theta) = -\frac{3}{7}: Find the angles that correspond to sin(θ)=37\sin(\theta) = -\frac{3}{7}.\newlineSince sin(θ)=37\sin(\theta) = -\frac{3}{7} does not correspond to a special angle, we will use a calculator to find the value of θ\theta. We need to find the reference angle first and then determine the angles in the third and fourth quadrants where sine is negative.\newlineReference angle = arcsin(37)25.4\arcsin\left(\frac{3}{7}\right) \approx 25.4 degrees\newlineAngles in the third and fourth quadrants: 180+25.4=205.4180 + 25.4 = 205.4 degrees and 36025.4=334.6360 - 25.4 = 334.6 degrees
  5. Find sin(θ)=1\sin(\theta) = 1: Find the angles that correspond to sin(θ)=1\sin(\theta) = 1. The angle where sin(θ)=1\sin(\theta) = 1 is a special angle, and we know that sine reaches its maximum value of 11 at θ=90\theta = 90 degrees.
  6. Compile Solutions: Compile all solutions.\newlineThe angles that satisfy the original equation are approximately 205.4205.4 degrees, 334.6334.6 degrees, and 9090 degrees.

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