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Consider the equation 
0.75*10^((w)/(3))=30
Solve the equation for 
w. Express the solution as a logarithm in base-10.

w=

◻
Approximate the value of 
w. Round your answer to the nearest thousandth.

w~~

Consider the equation \newline0.75×10(w3)=300.75\times10^{\left(\frac{w}{3}\right)}=30\newlineSolve the equation for \newlineww. Express the solution as a logarithm in base10-10.\newlinew=w=\newline\square\newlineApproximate the value of \newlineww. Round your answer to the nearest thousandth.\newlineww\approx

Full solution

Q. Consider the equation \newline0.75×10(w3)=300.75\times10^{\left(\frac{w}{3}\right)}=30\newlineSolve the equation for \newlineww. Express the solution as a logarithm in base10-10.\newlinew=w=\newline\square\newlineApproximate the value of \newlineww. Round your answer to the nearest thousandth.\newlineww\approx
  1. Isolate 10w/310^{w/3}: Isolate 10w/310^{w/3} by dividing both sides by 0.750.75: 0.7510w/3=3010w/3=300.75=40.0.75\cdot10^{w/3} = 30 \rightarrow 10^{w/3} = \frac{30}{0.75} = 40.
  2. Apply logarithm base10-10: Apply logarithm base10-10 to both sides to solve for w/3w/3: log10(10w/3)=log10(40)\log_{10}(10^{w/3}) = \log_{10}(40).
  3. Simplify using logarithm property: Simplify using the property of logarithms logb(bx)=x\log_b(b^x) = x: w3=log10(40)\frac{w}{3} = \log_{10}(40).
  4. Solve for w: Solve for w by multiplying both sides by 33: w=3×log10(40)w = 3 \times \log_{10}(40).
  5. Approximate log10(40)\log_{10}(40): Use a calculator to approximate log10(40)\log_{10}(40): log10(40)1.602\log_{10}(40) \approx 1.602.
  6. Calculate w: Calculate ww: w3×1.602=4.806w \approx 3 \times 1.602 = 4.806.

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