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Complete the point-slope equation of the line through (-5,4) and (1,6).
Use exact numbers.
y-6=◻

Complete the point-slope equation of the line through $(-5,4)$ and $(1,6)$ . $\newline$ Use exact numbers. $\newline$ $y-6= \square$ $\newline$

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Find the roots of factored polynomials

Full solution

Q. Complete the point-slope equation of the line through

(-5,4)

and

(1,6)

.

\newline

Use exact numbers.

\newline

y-6= \square

\newline

Calculate Slope: To find the point-slope form of the equation of a line, we first need to calculate the slope of the line using the two given points $(-5,4)$ and $(1,6)$ . The slope $m$ is given by the formula $m = \frac{y_2 - y_1}{x_2 - x_1}$ , where $(x_1, y_1)$ and $(x_2, y_2)$ are the coordinates of the two points.
Substitute Coordinates: Substitute the coordinates of the points into the slope formula: $m = \frac{6 - 4}{1 - (-5)} = \frac{2}{1 + 5} = \frac{2}{6} = \frac{1}{3}$ .
Write Point-Slope Form: Now that we have the slope, we can use one of the points and the slope to write the point-slope form of the equation. The point-slope form is $y - y_1 = m(x - x_1)$ , where $m$ is the slope and $(x_1, y_1)$ is a point on the line. We can use either of the two points, but let's use the point $(1,6)$ for this example.
Substitute Slope and Point: Substitute the slope and the coordinates of the point $(1,6)$ into the point-slope form: $y - 6 = \frac{1}{3}(x - 1)$ .

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