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Find all angles, 
0^(@) <= theta < 360^(@), that satisfy the equation below, to the nearest tenth of a degree.

6sin^(2)theta-5sin theta+4=3
Answer: 
theta=

Find all angles, 0θ<360 0^{\circ} \leq \theta<360^{\circ} , that satisfy the equation below, to the nearest tenth of a degree.\newline6sin2θ5sinθ+4=3 6 \sin ^{2} \theta-5 \sin \theta+4=3 \newlineAnswer: θ= \theta=

Full solution

Q. Find all angles, 0θ<360 0^{\circ} \leq \theta<360^{\circ} , that satisfy the equation below, to the nearest tenth of a degree.\newline6sin2θ5sinθ+4=3 6 \sin ^{2} \theta-5 \sin \theta+4=3 \newlineAnswer: θ= \theta=
  1. Simplify Equation: First, we need to simplify the given equation by moving all terms to one side to set the equation to zero.\newline6sin2θ5sinθ+43=06\sin^2\theta - 5\sin \theta + 4 - 3 = 0\newline6sin2θ5sinθ+1=06\sin^2\theta - 5\sin \theta + 1 = 0
  2. Factor Quadratic: Next, we will factor the quadratic equation in terms of sin(θ)\sin(\theta). We are looking for two numbers that multiply to 6×1=66\times1=6 and add up to 5-5. The numbers that satisfy these conditions are 3-3 and 2-2. So we can write the equation as (3sin(θ)1)(2sin(θ)1)=0(3\sin(\theta) - 1)(2\sin(\theta) - 1) = 0
  3. Solve for sin(θ)\sin(\theta): Now, we will solve each factor for sin(θ)\sin(\theta). First, for 3sin(θ)1=03\sin(\theta) - 1 = 0, we get sin(θ)=13\sin(\theta) = \frac{1}{3}. Second, for 2sin(θ)1=02\sin(\theta) - 1 = 0, we get sin(θ)=12\sin(\theta) = \frac{1}{2}.
  4. Find Angles (11/33): We will find the angles for sin(θ)=13\sin(\theta) = \frac{1}{3}. Since the sine function is positive, the angles must be in the first or second quadrant. Using a calculator, we find θarcsin(13)\theta \approx \arcsin(\frac{1}{3}). Theta 19.5\approx 19.5 degrees or 18019.5=160.5180 - 19.5 = 160.5 degrees.
  5. Find Angles (1/2)(1/2): Next, we will find the angles for sin(θ)=12\sin(\theta) = \frac{1}{2}. This is a known value on the unit circle, corresponding to θ=30\theta = 30 degrees and θ=150\theta = 150 degrees.
  6. Final Angles: We have found all possible angles for the given equation within the range 0θ<3600 \leq \theta < 360 degrees.\newlineThe angles are approximately 19.519.5 degrees, 160.5160.5 degrees, 3030 degrees, and 150150 degrees.

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