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If
f(1)=4 and
f(n)=f(n-1)+3 then find the value of
f(5).
Answer:

If $f(1)=4$ and $f(n)=f(n-1)+3$ then find the value of $f(5)$ . $\newline$ Answer:

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Find the roots of factored polynomials

Full solution

Q. If

f(1)=4

and

f(n)=f(n-1)+3

then find the value of

f(5)

.

\newline

Answer:

Base Case: We are given that $f(1) = 4$ . This is our base case.
Recursive Formula: We are also given a recursive formula: $f(n) = f(n-1) + 3$ . This means that to find $f(n)$ , we need to know the value of $f(n-1)$ and then add $3$ to it.
Finding $f(2)$ : To find $f(2)$ , we use the recursive formula with $n=2$ : $f(2) = f(2-1) + 3 = f(1) + 3$ . We know that $f(1) = 4$ , so $f(2) = 4 + 3 = 7$ .
Finding $f(3)$ : To find $f(3)$ , we use the recursive formula with $n=3$ : $f(3) = f(3-1) + 3 = f(2) + 3$ . We found that $f(2) = 7$ , so $f(3) = 7 + 3 = 10$ .
Finding $f(4)$ : To find $f(4)$ , we use the recursive formula with $n=4$ : $f(4) = f(4-1) + 3 = f(3) + 3$ . We found that $f(3) = 10$ , so $f(4) = 10 + 3 = 13$ .
Finding $f(5)$ : To find $f(5)$ , we use the recursive formula with $n=5$ : $f(5) = f(5-1) + 3 = f(4) + 3$ . We found that $f(4) = 13$ , so $f(5) = 13 + 3 = 16$ .

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