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Complete the point-slope equation of the line through
(-9,6) and
(-7,-8).
Use exact numbers.

y-6=

◻

Complete the point-slope equation of the line through $(-9,6)$ and $(-7,-8)$ . $\newline$ Use exact numbers. $\newline$ $y-6=$ $\newline$ $\square$

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Find the roots of factored polynomials

Full solution

Q. Complete the point-slope equation of the line through

(-9,6)

and

(-7,-8)

.

\newline

Use exact numbers.

\newline

y-6=

\newline

\square

Calculate the Slope: To find the point-slope form of the equation of the line, we first need to calculate the slope of the line using the two given points $(-9, 6)$ and $(-7, -8)$ . The slope $m$ is given by the formula $m = \frac{y_2 - y_1}{x_2 - x_1}$ , where $(x_1, y_1)$ and $(x_2, y_2)$ are the coordinates of the two points. $\newline$ Let's calculate the slope: $\newline$ $m = \frac{-8 - 6}{-7 - (-9)}$ $\newline$ $m = \frac{-14}{2}$ $\newline$ $m = -7$
Write Point-Slope Form: Now that we have the slope, we can use one of the points and the slope to write the point-slope form of the equation. The point-slope form is given by $y - y_1 = m(x - x_1)$ , where $m$ is the slope and $(x_1, y_1)$ is a point on the line. $\newline$ Let's use the point $(-9, 6)$ and the slope $-7$ to write the equation: $\newline$ $y - 6 = -7(x - (-9))$ $\newline$ $y - 6 = -7(x + 9)$

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