Resources
Testimonials
Plans
Sign in
Sign up
Resources
Testimonials
Plans
Home
Math Problems
Algebra 1
Evaluate recursive formulas for sequences
y
=
m
x
+
b
y=mx+b
y
=
m
x
+
b
Get tutor help
Question
4
4
4
\newline
Find
C
E
CE
CE
.
\newline
F
F
F
25
25
25
\newline
H
H
H
27
27
27
\newline
G
G
G
26
26
26
\newline
J
J
J
28
28
28
\newline
a.
F
F
F
\newline
b.
G
G
G
\newline
c.
H
H
H
\newline
d.
J
J
J
\newline
Question
5
5
5
Get tutor help
The product of a number,
x
x
x
, and
0
0
0
.
28
28
28
is
13
13
13
.
44
44
44
. Which equation match
\newline
ChatPDF
\newline
Vision
\newline
Full Page Invite \& Earn
\newline
x
÷
13.44
=
0.28
x \div 13.44=0.28
x
÷
13.44
=
0.28
\newline
0.28
x
=
13.44
0.28 x=13.44
0.28
x
=
13.44
\newline
0.28
÷
x
=
13.44
0.28 \div x=13.44
0.28
÷
x
=
13.44
Get tutor help
Find values for
p
p
p
and
q
q
q
so that the equation has infinitely many solutions.
−
7
x
+
p
=
q
x
+
1
-7x + p = qx + 1
−
7
x
+
p
=
q
x
+
1
\newline
p
=
p =
p
=
____
\newline
q
=
q =
q
=
____
Get tutor help
Find values for
p
p
p
and
q
q
q
so that the equation has infinitely many solutions.
2
x
+
p
=
q
x
−
16
2x + p = qx - 16
2
x
+
p
=
q
x
−
16
\newline
p
=
p =
p
=
____
\newline
q
=
q =
q
=
____
Get tutor help
У вас просят в долг
Р
=
200000
Р = 200000
Р
=
200000
и обещают возвращать по
А
=
31000
А = 31000
А
=
31000
в течение
N
=
8
N = 8
N
=
8
лет. У вас есть другой способ использования этих денег: положить их в банк под
7
%
7\%
7%
годовых и каждый год снимать
А
=
31000
А = 31000
А
=
31000
. Какая финансовая операция будет более выгодна для вас? Расчеты провести для простой и сложной процентных ставок.
Get tutor help
9
9
9
.
4
4
4
−
9
-9
−
9
.
6
6
6
Quiz Review
\newline
Name:
\newline
Calculate the Surface Area AND Volume of the following WATCH VIDEO
\newline
S
A
=
S A=
S
A
=
\newline
S
A
=
S A=
S
A
=
Get tutor help
What is the value of
v
v
v
?
\newline
v
=
v=
v
=
\newline
Submit
Get tutor help
584
584
584
\newline
Chapter
7
7
7
Rational Expressions and Equations
\newline
23
23
23
. Andrew is on a low-carbohydrate diet. If his diet book tells him that an
8
8
8
-oz serving of pineapple contains
19.2
g
19.2 \mathrm{~g}
19.2
g
of carbohydrate, how many grams of carbohydrate does a
5
5
5
-oz serving contain?
Get tutor help
Which equations represent a proportional relationship? Select all that apply.
\newline
A)
y
=
0.5
x
+
10
y=0.5 x+10
y
=
0.5
x
+
10
\newline
B)
y
=
3
x
−
5
y=3 x-5
y
=
3
x
−
5
\newline
C)
y
=
x
+
1
y=x+1
y
=
x
+
1
\newline
D)
y
=
17.5
x
y=17.5 x
y
=
17.5
x
\newline
E)
y
=
5
x
−
1
y=5 x-1
y
=
5
x
−
1
\newline
F)
y
=
100
x
y=100 x
y
=
100
x
Get tutor help
已知三角形
A
B
C
ABC
A
BC
中，
A
C
=
8
AC=8
A
C
=
8
,
A
B
=
41
AB=\sqrt{41}
A
B
=
41
,
B
C
BC
BC
边上的高
A
G
=
5
AG=5
A
G
=
5
,
D
D
D
为线段
A
C
AC
A
C
上的动点, 在
B
C
BC
BC
上截取
C
E
=
A
D
CE=AD
CE
=
A
D
, 连接
A
E
AE
A
E
,
A
C
=
8
AC=8
A
C
=
8
0
0
0
, 则
A
C
=
8
AC=8
A
C
=
8
1
1
1
的最小值为
Get tutor help
Look at the diagram.
\newline
Which equation can be used to solve for
x
x
x
?
\newline
15
x
+
75
=
180
15 x+75=180
15
x
+
75
=
180
\newline
10
x
+
80
=
180
10 x+80=180
10
x
+
80
=
180
\newline
15
x
=
75
15 x=75
15
x
=
75
\newline
10
x
+
5
=
75
10 x+5=75
10
x
+
5
=
75
\newline
Solve for
x
x
x
.
\newline
x
=
x=
x
=
Get tutor help
Solve the following equation for
x
x
x
. Express your answer in the simplest form.
\newline
5
(
4
x
+
6
)
=
20
x
+
30
5(4 x+6)=20 x+30
5
(
4
x
+
6
)
=
20
x
+
30
\newline
Get tutor help
Solve the following equation for
x
x
x
. Express your answer in the simplest form.
\newline
−
2
(
3
x
+
8
)
=
−
28
x
−
35
-2(3 x+8)=-28 x-35
−
2
(
3
x
+
8
)
=
−
28
x
−
35
\newline
Get tutor help
x
+
y
=
15
x+y=15
x
+
y
=
15
\newline
x
+
y
=
25
x+y=25
x
+
y
=
25
Get tutor help
1
1
1
)
R
1
=
200
R
2
=
100
R
3
=
100
R 1=200 R 2=100 R 3=100
R
1
=
200
R
2
=
100
R
3
=
100
y
V
1
=
10
V
V 1=10 V
V
1
=
10
V
\newline
R
1
1
1
\newline
2
2
2
)
R
1
=
200
R
2
=
330
R
3
=
420
V
1
=
9
V
\mathrm{R} 1=200 \mathrm{R} 2=330 \mathrm{R} 3=420 \mathrm{~V} 1=9 \mathrm{~V}
R
1
=
200
R
2
=
330
R
3
=
420
V
1
=
9
V
\newline
R
4
4
4
\newline
3
3
3
)
V
=
12
V
V=12 V
V
=
12
V
\newline
4
4
4
)
V
1
=
120
V
V 1=120 \mathrm{~V}
V
1
=
120
V
Get tutor help
M
=
2
N
=
P
4
=
Q
+
8
=
R
2
>
0
M = 2N = \frac{P}{4} = Q + 8 = \frac{R}{2} > 0
M
=
2
N
=
4
P
=
Q
+
8
=
2
R
>
0
Based on the statement above, which variable has the greatest value?
\newline
A.
M
M
M
\newline
B.
P
P
P
\newline
C.
Q
Q
Q
\newline
D.
R
R
R
Get tutor help
7
x
+
10
y
=
36
7 x+10 y=36
7
x
+
10
y
=
36
\newline
y
=
2
x
+
9
y=2 x+9
y
=
2
x
+
9
\newline
x
=
x=
x
=
\newline
y
=
y=
y
=
Get tutor help
Solve for
A
A
A
.
10
+
A
=
50
10+A=50
10
+
A
=
50
Get tutor help
Solve for a. You must write your answer in fully simplified form.
\newline
12
a
=
18
12 a=18
12
a
=
18
\newline
Answer:
a
=
a=
a
=
Get tutor help
Solve for b. You must write your answer in fully simplified form.
\newline
9
=
−
2
b
9=-2 b
9
=
−
2
b
\newline
Answer:
b
=
b=
b
=
Get tutor help
Solve for
t
t
t
. You must write your answer in fully simplified form.
\newline
16
=
14
t
16=14 t
16
=
14
t
\newline
Answer:
t
=
t=
t
=
Get tutor help
Solve for
t
t
t
. You must write your answer in fully simplified form.
\newline
−
10
=
−
10
t
-10=-10 t
−
10
=
−
10
t
\newline
Answer:
t
=
t=
t
=
Get tutor help
Which equation has the solution
x
=
3
x=3
x
=
3
?
\newline
8
x
−
4
=
−
20
8 x-4=-20
8
x
−
4
=
−
20
\newline
6
x
+
7
=
64
6 x+7=64
6
x
+
7
=
64
\newline
4
x
−
7
=
5
4 x-7=5
4
x
−
7
=
5
\newline
8
x
−
1
=
87
8 x-1=87
8
x
−
1
=
87
Get tutor help
Myra is
5
5
5
years younger than her sister Talat. Myra wants to write an equation for her own age
(
m
)
(m)
(
m
)
given Talat's age
(
t
)
(t)
(
t
)
.
\newline
How should Myra write her equation?
\newline
Choose
1
1
1
answer:
\newline
(A)
t
=
m
+
5
t=m+5
t
=
m
+
5
\newline
(B)
t
−
m
=
5
t-m=5
t
−
m
=
5
\newline
(C)
m
=
t
−
5
m=t-5
m
=
t
−
5
Get tutor help
Solve for
x
x
x
.
\newline
Enter the solutions from least to greatest.
\newline
−
2
x
2
−
9
=
−
107
-2 x^{2}-9=-107
−
2
x
2
−
9
=
−
107
\newline
lesser
x
=
x=
x
=
\newline
greater
x
=
x=
x
=
Get tutor help
Solve for
x
x
x
.
\newline
Enter the solutions from least to greatest.
\newline
2
x
2
−
5
=
13
2 x^{2}-5=13
2
x
2
−
5
=
13
\newline
lesser
x
=
x=
x
=
\newline
greater
x
=
x=
x
=
Get tutor help
Find the zeros of the function.
\newline
Enter the solutions from least to greatest.
\newline
g
(
x
)
=
4
x
2
−
484
g(x)=4 x^{2}-484
g
(
x
)
=
4
x
2
−
484
\newline
lesser
x
=
x=
x
=
\newline
greater
x
=
x=
x
=
Get tutor help
Solve for
x
x
x
.
\newline
Enter the solutions from least to greatest.
\newline
−
x
2
−
8
=
−
33
-x^{2}-8=-33
−
x
2
−
8
=
−
33
\newline
lesser
x
=
x=
x
=
\newline
greater
x
=
x=
x
=
Get tutor help
Solve for
x
x
x
.
\newline
Enter the solutions from least to greatest.
\newline
3
x
2
+
4
=
436
3 x^{2}+4=436
3
x
2
+
4
=
436
\newline
lesser
x
=
x=
x
=
\newline
greater
x
=
x=
x
=
Get tutor help
Solve for
x
x
x
.
\newline
Enter the solutions from least to greatest.
\newline
5
x
2
+
3
=
83
5 x^{2}+3=83
5
x
2
+
3
=
83
\newline
lesser
x
=
x=
x
=
\newline
greater
x
=
x=
x
=
Get tutor help
Solve for
x
x
x
.
\newline
Enter the solutions from least to greatest.
\newline
6
x
2
+
1
=
487
6 x^{2}+1=487
6
x
2
+
1
=
487
\newline
lesser
x
=
x=
x
=
\newline
greater
x
=
x=
x
=
Get tutor help
Find the zeros of the function.
\newline
Enter the solutions from least to greatest.
\newline
f
(
x
)
=
8
x
2
−
800
f(x)=8 x^{2}-800
f
(
x
)
=
8
x
2
−
800
\newline
lesser
x
=
x=
x
=
\newline
greater
x
=
x=
x
=
Get tutor help
Find the zeros of the function.
\newline
Enter the solutions from least to greatest.
\newline
f
(
x
)
=
−
3
x
2
+
75
f(x)=-3 x^{2}+75
f
(
x
)
=
−
3
x
2
+
75
\newline
lesser
x
=
x=
x
=
\newline
greater
x
=
x=
x
=
Get tutor help
Solve for
x
x
x
.
\newline
Enter the solutions from least to greatest.
\newline
−
4
x
2
−
7
=
−
11
-4 x^{2}-7=-11
−
4
x
2
−
7
=
−
11
\newline
lesser
x
=
x=
x
=
\newline
greater
x
=
x=
x
=
Get tutor help
{
f
(
1
)
=
−
16
f
(
n
)
=
−
29
−
f
(
n
−
1
)
f
(
2
)
=
□
\begin{array}{l}\left\{\begin{array}{l}f(1)=-16 \\ f(n)=-29-f(n-1)\end{array}\right. \\ f(2)=\square\end{array}
{
f
(
1
)
=
−
16
f
(
n
)
=
−
29
−
f
(
n
−
1
)
f
(
2
)
=
□
Get tutor help
{
g
(
1
)
=
−
5
g
(
2
)
=
3
g
(
n
)
=
g
(
n
−
2
)
+
g
(
n
−
1
)
g
(
3
)
=
□
\begin{array}{l}\left\{\begin{array}{l}g(1)=-5 \\ g(2)=3 \\ g(n)=g(n-2)+g(n-1)\end{array}\right. \\ g(3)=\square\end{array}
⎩
⎨
⎧
g
(
1
)
=
−
5
g
(
2
)
=
3
g
(
n
)
=
g
(
n
−
2
)
+
g
(
n
−
1
)
g
(
3
)
=
□
Get tutor help
{
g
(
1
)
=
4
g
(
2
)
=
−
3
g
(
n
)
=
g
(
n
−
2
)
⋅
g
(
n
−
1
)
g
(
3
)
=
\begin{array}{l}\left\{\begin{array}{l}g(1)=4 \\ g(2)=-3 \\ g(n)=g(n-2) \cdot g(n-1)\end{array}\right. \\ g(3)=\end{array}
⎩
⎨
⎧
g
(
1
)
=
4
g
(
2
)
=
−
3
g
(
n
)
=
g
(
n
−
2
)
⋅
g
(
n
−
1
)
g
(
3
)
=
Get tutor help
{
h
(
1
)
=
−
2
h
(
2
)
=
1
h
(
n
)
=
h
(
n
−
2
)
+
h
(
n
−
1
)
h
(
3
)
=
\begin{array}{l}\left\{\begin{array}{l}h(1)=-2 \\ h(2)=1 \\ h(n)=h(n-2)+h(n-1)\end{array}\right. \\ h(3)=\end{array}
⎩
⎨
⎧
h
(
1
)
=
−
2
h
(
2
)
=
1
h
(
n
)
=
h
(
n
−
2
)
+
h
(
n
−
1
)
h
(
3
)
=
Get tutor help
{
f
(
1
)
=
25
f
(
n
)
=
f
(
n
−
1
)
⋅
(
−
1
5
)
\left\{\begin{array}{l}f(1)=25 \\ f(n)=f(n-1) \cdot\left(-\frac{1}{5}\right)\end{array}\right.
{
f
(
1
)
=
25
f
(
n
)
=
f
(
n
−
1
)
⋅
(
−
5
1
)
\newline
f
(
3
)
=
f(3)=
f
(
3
)
=
Get tutor help
{
h
(
1
)
=
−
10
h
(
2
)
=
−
2
h
(
n
)
=
h
(
n
−
2
)
⋅
h
(
n
−
1
)
h
(
3
)
=
\begin{array}{l}\left\{\begin{array}{l}h(1)=-10 \\ h(2)=-2 \\ h(n)=h(n-2) \cdot h(n-1)\end{array}\right. \\ h(3)=\end{array}
⎩
⎨
⎧
h
(
1
)
=
−
10
h
(
2
)
=
−
2
h
(
n
)
=
h
(
n
−
2
)
⋅
h
(
n
−
1
)
h
(
3
)
=
Get tutor help
{
h
(
1
)
=
9
h
(
n
)
=
h
(
n
−
1
)
⋅
1
9
h
(
3
)
=
□
\begin{array}{l}\left\{\begin{array}{l}h(1)=9 \\ h(n)=h(n-1) \cdot \frac{1}{9}\end{array}\right. \\ h(3)=\square\end{array}
{
h
(
1
)
=
9
h
(
n
)
=
h
(
n
−
1
)
⋅
9
1
h
(
3
)
=
□
Get tutor help
{
f
(
1
)
=
−
7
f
(
n
)
=
f
(
n
−
1
)
+
3.5
f
(
3
)
=
□
\begin{array}{l}\left\{\begin{array}{l}f(1)=-7 \\ f(n)=f(n-1)+3.5\end{array}\right. \\ f(3)=\square\end{array}
{
f
(
1
)
=
−
7
f
(
n
)
=
f
(
n
−
1
)
+
3.5
f
(
3
)
=
□
Get tutor help
{
g
(
1
)
=
50
g
(
n
)
=
8
−
g
(
n
−
1
)
g
(
2
)
=
□
\begin{array}{l}\left\{\begin{array}{l}g(1)=50 \\ g(n)=8-g(n-1)\end{array}\right. \\ g(2)=\square\end{array}
{
g
(
1
)
=
50
g
(
n
)
=
8
−
g
(
n
−
1
)
g
(
2
)
=
□
Get tutor help
{
h
(
1
)
=
−
35
h
(
n
)
=
h
(
n
−
1
)
⋅
2
h
(
3
)
=
\begin{array}{l}\left\{\begin{array}{l}h(1)=-35 \\ h(n)=h(n-1) \cdot 2\end{array}\right. \\ h(3)=\end{array}
{
h
(
1
)
=
−
35
h
(
n
)
=
h
(
n
−
1
)
⋅
2
h
(
3
)
=
Get tutor help
{
f
(
1
)
=
1
f
(
2
)
=
2
f
(
n
)
=
f
(
n
−
2
)
+
f
(
n
−
1
)
f
(
3
)
=
□
\begin{array}{l}\left\{\begin{array}{l}f(1)=1 \\ f(2)=2 \\ f(n)=f(n-2)+f(n-1)\end{array}\right. \\ f(3)=\square\end{array}
⎩
⎨
⎧
f
(
1
)
=
1
f
(
2
)
=
2
f
(
n
)
=
f
(
n
−
2
)
+
f
(
n
−
1
)
f
(
3
)
=
□
Get tutor help
{
g
(
1
)
=
0
g
(
n
)
=
g
(
n
−
1
)
+
n
g
(
2
)
=
□
\begin{array}{l}\left\{\begin{array}{l}g(1)=0 \\ g(n)=g(n-1)+n\end{array}\right. \\ g(2)=\square\end{array}
{
g
(
1
)
=
0
g
(
n
)
=
g
(
n
−
1
)
+
n
g
(
2
)
=
□
Get tutor help
{
f
(
1
)
=
15
f
(
n
)
=
f
(
n
−
1
)
⋅
n
f
(
2
)
=
□
\begin{array}{l}\left\{\begin{array}{l}f(1)=15 \\ f(n)=f(n-1) \cdot n\end{array}\right. \\ f(2)=\square\end{array}
{
f
(
1
)
=
15
f
(
n
)
=
f
(
n
−
1
)
⋅
n
f
(
2
)
=
□
Get tutor help
{
f
(
1
)
=
−
6
f
(
2
)
=
−
4
f
(
n
)
=
f
(
n
−
2
)
+
f
(
n
−
1
)
f
(
3
)
=
\begin{array}{l}\left\{\begin{array}{l}f(1)=-6 \\ f(2)=-4 \\ f(n)=f(n-2)+f(n-1)\end{array}\right. \\ f(3)=\end{array}
⎩
⎨
⎧
f
(
1
)
=
−
6
f
(
2
)
=
−
4
f
(
n
)
=
f
(
n
−
2
)
+
f
(
n
−
1
)
f
(
3
)
=
Get tutor help
{
g
(
1
)
=
4
g
(
n
)
=
g
(
n
−
1
)
⋅
(
−
3
)
g
(
3
)
=
□
\begin{array}{l}\left\{\begin{array}{l}g(1)=4 \\ g(n)=g(n-1) \cdot(-3)\end{array}\right. \\ g(3)=\square\end{array}
{
g
(
1
)
=
4
g
(
n
)
=
g
(
n
−
1
)
⋅
(
−
3
)
g
(
3
)
=
□
Get tutor help
1
2
Next
