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{:[{[h(1)=-10],[h(2)=-2],[h(n)=h(n-2)*h(n-1)]:}],[h(3)=]:}

{h(1)=−10h(2)=−2h(n)=h(n−2)⋅h(n−1)h(3)= \begin{array}{l}\left\{\begin{array}{l}h(1)=-10 \\ h(2)=-2 \\ h(n)=h(n-2) \cdot h(n-1)\end{array}\right. \\ h(3)=\end{array}

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Q. {h(1)=−10h(2)=−2h(n)=h(n−2)⋅h(n−1)h(3)= \begin{array}{l}\left\{\begin{array}{l}h(1)=-10 \\ h(2)=-2 \\ h(n)=h(n-2) \cdot h(n-1)\end{array}\right. \\ h(3)=\end{array}
  1. Given initial conditions: We are given the initial conditions h(1)=−10h(1) = -10 and h(2)=−2h(2) = -2, and the recursive formula h(n)=h(n−2)⋅h(n−1)h(n) = h(n-2) \cdot h(n-1). To find h(3)h(3), we need to use the values of h(1)h(1) and h(2)h(2).\newlineCalculation: h(3)=h(1)⋅h(2)=(−10)⋅(−2)=20h(3) = h(1) \cdot h(2) = (-10) \cdot (-2) = 20

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