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Find the sum of the finite arithmetic series. n=110(7n+4)\sum_{n=1}^{10} (7n+4)\newline______

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Q. Find the sum of the finite arithmetic series. n=110(7n+4)\sum_{n=1}^{10} (7n+4)\newline______
  1. Arithmetic Series Sum Formula: To find the sum of an arithmetic series, we can use the formula Sn=n2(a1+an)S_n = \frac{n}{2} * (a_1 + a_n), where SnS_n is the sum of the first nn terms, a1a_1 is the first term, and ana_n is the nnth term. In this case, we need to find the sum of the first 1010 terms of the series where each term is given by 7n+47n+4.
  2. Find First Term: First, we need to find the first term a1a_1 by plugging n=1n=1 into the formula 7n+47n+4. This gives us a1=7(1)+4=11a_1 = 7(1) + 4 = 11.
  3. Find Tenth Term: Next, we need to find the tenth term a10a_{10} by plugging n=10n=10 into the formula 7n+47n+4. This gives us a10=7(10)+4=70+4=74a_{10} = 7(10) + 4 = 70 + 4 = 74.
  4. Calculate Sum: Now that we have the first term a1a_1 and the tenth term a10a_{10}, we can use the sum formula Sn=n2(a1+an)S_n = \frac{n}{2} * (a_1 + a_n). Plugging in the values, we get S10=102(11+74)S_{10} = \frac{10}{2} * (11 + 74).
  5. Final Result: Simplifying the expression, we get S10=5×(11+74)=5×85=425S_{10} = 5 \times (11 + 74) = 5 \times 85 = 425.

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