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Find the zeros of the function. Enter the solutions from least to greatest. f(x)=-3x^(2)+75 lesser x= greater x=

Find the zeros of the function.\newlineEnter the solutions from least to greatest.\newlinef(x)=−3x2+75 f(x)=-3 x^{2}+75 \newlinelesser x= x= \newlinegreater x= x=

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Q. Find the zeros of the function.\newlineEnter the solutions from least to greatest.\newlinef(x)=−3x2+75 f(x)=-3 x^{2}+75 \newlinelesser x= x= \newlinegreater x= x=
  1. Move constant term: Now, we will move the constant term to the other side of the equation by adding 3x23x^2 to both sides.\newline0+3x2=−3x2+75+3x20 + 3x^2 = -3x^2 + 75 + 3x^2\newline3x2=753x^2 = 75
  2. Divide to isolate x2x^2: Next, we will divide both sides of the equation by 33 to isolate x2x^2.\newline3x23=753 \frac{3x^2}{3} = \frac{75}{3} \newlinex2=25x^2 = 25
  3. Take square root: To find the values of xx, we take the square root of both sides. Remember that taking the square root of a number yields both a positive and a negative solution.\newlinex=±25x = \pm\sqrt{25}\newlinex=±5x = \pm5
  4. Find solutions for x: We have found two solutions for x. The lesser value is −5-5 and the greater value is 55.\newlinelesser x = −5-5\newlinegreater x = 55

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