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{:[{[g(1)=50],[g(n)=8-g(n-1)]:}],[g(2)=◻]:}

{g(1)=50g(n)=8g(n1)g(2)= \begin{array}{l}\left\{\begin{array}{l}g(1)=50 \\ g(n)=8-g(n-1)\end{array}\right. \\ g(2)=\square\end{array}

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Q. {g(1)=50g(n)=8g(n1)g(2)= \begin{array}{l}\left\{\begin{array}{l}g(1)=50 \\ g(n)=8-g(n-1)\end{array}\right. \\ g(2)=\square\end{array}
  1. Initial condition and recursive formula: We have the initial condition and the recursive formula:\newlineg(11) = 5050\newlineg(n) = 88 - g(n - 11)\newlineTo find g(22), we need to use the recursive formula with n = 22.
  2. Substituting n=2 n = 2 into the recursive formula: Substitute n=2 n = 2 into the recursive formula:\newlineg(2)=8g(21) g(2) = 8 - g(2 - 1) \newlineg(2)=8g(1) g(2) = 8 - g(1) \newlineNow we can use the initial condition g(1)=50 g(1) = 50 to find g(2) g(2) .
  3. Using the initial condition to find g(2)g(2): Substitute g(1)=50g(1) = 50 into the equation:\newlineg(2)=850g(2) = 8 - 50\newlineg(2)=42g(2) = -42
  4. Finding the value of g(22): We have found the value of g(22):
    g(22) = 42-42

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