Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Which equation has the solution x=3 ? 8x-4=-20 6x+7=64 4x-7=5 8x-1=87

Which equation has the solution x=3 x=3 ?\newline8x−4=−20 8 x-4=-20 \newline6x+7=64 6 x+7=64 \newline4x−7=5 4 x-7=5 \newline8x−1=87 8 x-1=87

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Algebra 1right chevron icon
Evaluate recursive formulas for sequencesright chevron icon

Full solution

Q. Which equation has the solution x=3 x=3 ?\newline8x−4=−20 8 x-4=-20 \newline6x+7=64 6 x+7=64 \newline4x−7=5 4 x-7=5 \newline8x−1=87 8 x-1=87
  1. Substitute x=3x=3: Let's start by substituting x=3x=3 into the first equation 8x−4=−208x-4=-20 and see if it holds true.\newlineCalculation: 8(3)−4=24−4=208(3) - 4 = 24 - 4 = 20\newlineNow, let's compare this result with the right side of the equation.\newline20≠−2020 \neq -20
  2. Check first equation: Since the first equation does not hold true for x=3x=3, let's try the second equation 6x+7=646x+7=64.\newlineCalculation: 6(3)+7=18+7=256(3) + 7 = 18 + 7 = 25\newlineNow, let's compare this result with the right side of the equation.\newline25≠6425 \neq 64
  3. Check second equation: The second equation also does not hold true for x=3x=3, so let's try the third equation 4x−7=54x-7=5.\newlineCalculation: 4(3)−7=12−7=54(3) - 7 = 12 - 7 = 5\newlineNow, let's compare this result with the right side of the equation.\newline5=55 = 5\newlineThis equation holds true for x=3x=3.
  4. Check third equation: Since we have found an equation that holds true for x=3x=3, there is no need to check the fourth equation. However, for completeness, let's check the fourth equation 8x−1=878x-1=87.\newlineCalculation: 8(3)−1=24−1=238(3) - 1 = 24 - 1 = 23\newlineNow, let's compare this result with the right side of the equation.\newline23≠8723 \neq 87

More problems from Evaluate recursive formulas for sequences

Question
Find the sum of the finite arithmetic series. ∑n=110(7n+4)\sum_{n=1}^{10} (7n+4)\newline______
Get tutor helpright-arrow

Posted 2 months ago

Question
Type the missing number in this sequence: `55,\59,\63,\text{_____},\71,\75,\79`
Get tutor helpright-arrow

Posted 1 month ago

Question
Type the missing number in this sequence: `2, 4 8`, ______,`32`
Get tutor helpright-arrow

Posted 2 months ago

Question
What kind of sequence is this? 2,10,50,250,…2, 10, 50, 250, \ldots Choices:Choices:\newline[A]arithmetic\text{[A]arithmetic}\newline[B]geometric\text{[B]geometric}\newline[C]both\text{[C]both}\newline[D]neither\text{[D]neither}
Get tutor helpright-arrow

Posted 2 months ago

Question
What is the missing number in this pattern? 1,4,9,16,25,36,49,64,81,____1, 4, 9, 16, 25, 36, 49, 64, 81, \_\_\_\_
Get tutor helpright-arrow

Posted 1 month ago

Question
Classify the series. ∑n=012(n+2)3 \sum_{n = 0}^{12} (n + 2)^3 \newlineChoices:\newline[A]arithmetic\text{[A]arithmetic}\newline[B]geometric\text{[B]geometric}\newline[C]both\text{[C]both}\newline[D]neither\text{[D]neither}
Get tutor helpright-arrow

Posted 1 month ago

Question
Find the first three partial sums of the series.\newline1+6+11+16+21+26+⋯1 + 6 + 11 + 16 + 21 + 26 + \cdots\newlineWrite your answers as integers or fractions in simplest form.\newlineS1=S_1 = ____\newlineS2=S_2 = ____\newlineS3=S_3 = ____
Get tutor helpright-arrow

Posted 1 month ago

Question
Find the third partial sum of the series. \newline3+9+15+21+27+33+⋯3 + 9 + 15 + 21 + 27 + 33 + \cdots\newlineWrite your answer as an integer or a fraction in simplest form. \newlineS3=S_3 = ____
Get tutor helpright-arrow

Posted 1 month ago

Question
Find the first three partial sums of the series. \newline1+7+13+19+25+31+⋯1 + 7 + 13 + 19 + 25 + 31 + \cdots\newlineWrite your answers as integers or fractions in simplest form. \newlineS1=S_1 = ____\newlineS2=S_2 = ____\newlineS3=S_3 = ____
Get tutor helpright-arrow

Posted 2 months ago

Question
Does the infinite geometric series converge or diverge?\newline1+34+916+2764+⋯1 + \frac{3}{4} + \frac{9}{16} + \frac{27}{64} + \cdots\newlineChoices:\newline[A]converge\text{[A]converge}\newline[B]diverge\text{[B]diverge}
Get tutor helpright-arrow

Posted 1 month ago

View all (70)