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Find the zeros of the function. Enter the solutions from least to greatest. g(x)=4x^(2)-484 lesser x= greater x=

Find the zeros of the function.\newlineEnter the solutions from least to greatest.\newlineg(x)=4x2−484 g(x)=4 x^{2}-484 \newlinelesser x= x= \newlinegreater x= x=

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Q. Find the zeros of the function.\newlineEnter the solutions from least to greatest.\newlineg(x)=4x2−484 g(x)=4 x^{2}-484 \newlinelesser x= x= \newlinegreater x= x=
  1. Set equation to zero: To find the zeros of the function g(x)=4x2−484g(x) = 4x^2 - 484, we need to set g(x)g(x) to zero and solve for xx.\newline0=4x2−4840 = 4x^2 - 484
  2. Isolate quadratic term: Next, we add 484484 to both sides of the equation to isolate the quadratic term.\newline4x2=4844x^2 = 484
  3. Solve for x^22: Now, we divide both sides of the equation by 44 to solve for x2x^2.\newlinex2=4844x^2 = \frac{484}{4}\newlinex2=121x^2 = 121
  4. Take square root: To find the values of xx, we take the square root of both sides. Remember that taking the square root of a number yields both a positive and a negative solution.\newlinex=±121x = \pm\sqrt{121}\newlinex=±11x = \pm11
  5. List solutions: We have two solutions for x, which are x=11x = 11 and x=−11x = -11. We need to list them from least to greatest.\newlinelesser x=−11x = -11\newlinegreater x=11x = 11

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