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Math Problems
Precalculus
Product property of logarithms
rewrite the following in the form
log
(
c
)
\log(c)
lo
g
(
c
)
.
log
(
2
)
+
log
(
4
)
\log(2) + \log(4)
lo
g
(
2
)
+
lo
g
(
4
)
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Which of the following is equivalent to
log
(
a
)
×
log
a
(
5
)
\log(a) \times \log_a (5)
lo
g
(
a
)
×
lo
g
a
(
5
)
?
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log
(
10
)
−
log
(
2
)
\log(10)-\log(2)
lo
g
(
10
)
−
lo
g
(
2
)
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Expand the logarithm. Assume all expressions exist and are well-defined.
\newline
Write your answer as a sum or difference of common logarithms or multiples of common logarithms. The inside of each logarithm must be a distinct constant or variable.
\newline
log
13
r
\log 13 r
lo
g
13
r
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rewrite
log
(
a
)
+
log
(
b
)
+
log
(
c
)
\log(a) +\log(b) + \log(c)
lo
g
(
a
)
+
lo
g
(
b
)
+
lo
g
(
c
)
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log
(
4
)
+
log
(
5
)
\log(4) + \log(5)
lo
g
(
4
)
+
lo
g
(
5
)
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log
(
20
)
−
log
(
5
)
\log(20) - \log(5)
lo
g
(
20
)
−
lo
g
(
5
)
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Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
\newline
2
log
(
3
)
2 \log (3)
2
lo
g
(
3
)
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log
3
7
+
log
3
8
\log _{3} 7+\log _{3} 8
lo
g
3
7
+
lo
g
3
8
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Simplify each logarithm
\newline
54
54
54
)
log
3
7
+
log
3
8
\log _{3} 7+\log _{3} 8
lo
g
3
7
+
lo
g
3
8
자
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\newline
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\newline
NEV
\newline
Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
log
(
15
)
−
log
(
3
)
\log (15)-\log (3)
lo
g
(
15
)
−
lo
g
(
3
)
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Which of the following is equivalent to
log
b
8
\log _{b} 8
lo
g
b
8
?
\newline
(
log
b
4
)
(
log
b
2
)
\left(\log _{b} 4\right)\left(\log _{b} 2\right)
(
lo
g
b
4
)
(
lo
g
b
2
)
\newline
log
b
4
+
log
b
2
\log _{b} 4+\log _{b} 2
lo
g
b
4
+
lo
g
b
2
\newline
log
b
4
+
log
b
4
\log _{b} 4+\log _{b} 4
lo
g
b
4
+
lo
g
b
4
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log
10
\log 10
lo
g
10
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Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
\newline
log
(
6
)
−
log
(
2
)
\log (6)-\log (2)
lo
g
(
6
)
−
lo
g
(
2
)
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Rewrite the following in the form
log
(
c
)
\log(c)
lo
g
(
c
)
2
log
(
5
)
2\log(5)
2
lo
g
(
5
)
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Evaluate:
log
4
(
8
−
x
)
=
log
4
(
6
)
\log_{4}(8-x)=\log_{4}(6)
lo
g
4
(
8
−
x
)
=
lo
g
4
(
6
)
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Simplify the following:
\newline
log
3
(
2
x
)
+
log
3
w
\log _{3}(2 x)+\log _{3} w
lo
g
3
(
2
x
)
+
lo
g
3
w
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log
4
x
+
log
x
(
6
4
4
)
\log _{4} x+\log _{x}\left(64^{4}\right)
lo
g
4
x
+
lo
g
x
(
6
4
4
)
\newline
Find the value of
x
x
x
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log
4
x
+
4
log
x
64
=
8
\log _{4} x+4 \log _{x} 64=8
lo
g
4
x
+
4
lo
g
x
64
=
8
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Expand
log
7
5
x
\log _{7} 5 \sqrt{x}
lo
g
7
5
x
.
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Evaluate the logarithm.
\newline
Round your answer to the nearest thousandth.
\newline
log
4
(
0.6
)
≈
\log _{4}(0.6) \approx
lo
g
4
(
0.6
)
≈
\newline
□
\square
□
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log
(
6
)
−
log
(
2
)
\log(6)-\log(2)
lo
g
(
6
)
−
lo
g
(
2
)
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log
5
5
=
x
\log _{\sqrt{5}} 5=x
lo
g
5
5
=
x
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Without the use of calculators or software establish which number is larger:
\newline
log
189
1323
\log_{189}1323
lo
g
189
1323
or
log
63
147
\log_{63}147
lo
g
63
147
.
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Evaluate the logarithm.
\newline
Round your answer to the nearest thousandth.
\newline
log
3
(
346
)
≈
\log _{3}(346) \approx
lo
g
3
(
346
)
≈
\newline
□
\square
□
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Use the laws of logarithms to solve
\newline
log
2
(
16
x
)
+
log
2
(
x
+
1
)
=
3
+
log
2
(
x
+
6
)
\log_{2}(16x)+\log_{2}(x+1)=3+\log_{2}(x+6)
lo
g
2
(
16
x
)
+
lo
g
2
(
x
+
1
)
=
3
+
lo
g
2
(
x
+
6
)
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Solve for a positive value of
x
x
x
.
\newline
log
5
(
x
)
=
2
\log _{5}(x)=2
lo
g
5
(
x
)
=
2
\newline
Answer:
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Solve for a positive value of
x
x
x
.
\newline
log
x
(
4
)
=
2
\log _{x}(4)=2
lo
g
x
(
4
)
=
2
\newline
Answer:
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Solve for a positive value of
x
x
x
.
\newline
log
3
(
729
)
=
x
\log _{3}(729)=x
lo
g
3
(
729
)
=
x
\newline
Answer:
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Solve for a positive value of
x
x
x
.
\newline
log
2
(
x
)
=
7
\log _{2}(x)=7
lo
g
2
(
x
)
=
7
\newline
Answer:
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Solve for a positive value of
x
x
x
.
\newline
log
9
(
x
)
=
3
\log _{9}(x)=3
lo
g
9
(
x
)
=
3
\newline
Answer:
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Solve for a positive value of
x
x
x
.
\newline
log
2
(
64
)
=
x
\log _{2}(64)=x
lo
g
2
(
64
)
=
x
\newline
Answer:
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Solve for a positive value of
x
x
x
.
\newline
log
8
(
64
)
=
x
\log _{8}(64)=x
lo
g
8
(
64
)
=
x
\newline
Answer:
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Solve for a positive value of
x
x
x
.
\newline
log
2
(
x
)
=
9
\log _{2}(x)=9
lo
g
2
(
x
)
=
9
\newline
Answer:
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Solve for a positive value of
x
x
x
.
\newline
log
8
(
512
)
=
x
\log _{8}(512)=x
lo
g
8
(
512
)
=
x
\newline
Answer:
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Solve for a positive value of
x
x
x
.
\newline
log
5
(
x
)
=
4
\log _{5}(x)=4
lo
g
5
(
x
)
=
4
\newline
Answer:
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Solve for a positive value of
x
x
x
.
\newline
log
x
(
216
)
=
3
\log _{x}(216)=3
lo
g
x
(
216
)
=
3
\newline
Answer:
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Expand the logarithm fully using the properties of logs. Express the final answer in terms of
log
x
\log x
lo
g
x
.
\newline
log
6
x
4
\log 6 x^{4}
lo
g
6
x
4
\newline
Answer:
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Expand the logarithm fully using the properties of logs. Express the final answer in terms of
log
x
\log x
lo
g
x
.
\newline
log
4
x
3
\log 4 x^{3}
lo
g
4
x
3
\newline
Answer:
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Expand the logarithm fully using the properties of logs. Express the final answer in terms of
log
x
\log x
lo
g
x
.
\newline
log
5
x
2
\log 5 x^{2}
lo
g
5
x
2
\newline
Answer:
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Condense the logarithm
\newline
q
log
b
−
z
log
k
q \log b-z \log k
q
lo
g
b
−
z
lo
g
k
\newline
Answer:
log
(
□
)
\log (\square)
lo
g
(
□
)
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1
1
1
)
log
2
16
\log _{2} 16
lo
g
2
16
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Solve for the exact value of
x
x
x
.
\newline
log
5
(
5
x
)
+
log
5
(
2
)
=
0
\log _{5}(5 x)+\log _{5}(2)=0
lo
g
5
(
5
x
)
+
lo
g
5
(
2
)
=
0
\newline
Answer:
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Solve for the exact value of
x
x
x
.
\newline
log
5
(
4
x
)
−
2
log
5
(
4
)
=
1
\log _{5}(4 x)-2 \log _{5}(4)=1
lo
g
5
(
4
x
)
−
2
lo
g
5
(
4
)
=
1
\newline
Answer:
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Solve the following logarithm problem for the positive solution for
x
x
x
.
\newline
log
2
x
=
−
5
\log _{2} x=-5
lo
g
2
x
=
−
5
\newline
Answer:
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Solve the following logarithm problem for the positive solution for
x
x
x
.
\newline
log
x
216
=
3
\log _{x} 216=3
lo
g
x
216
=
3
\newline
Answer:
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Solve the following logarithm problem for the positive solution for
x
x
x
.
\newline
log
6
x
=
−
3
\log _{6} x=-3
lo
g
6
x
=
−
3
\newline
Answer:
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Write the log equation as an exponential equation. You do not need to solve for
x
\mathrm{x}
x
.
\newline
log
(
2
)
=
4
x
\log (2)=4 x
lo
g
(
2
)
=
4
x
\newline
Answer:
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Write the log equation as an exponential equation. You do not need to solve for
x
\mathrm{x}
x
.
\newline
log
3
x
(
3
)
=
3
\log _{3 x}(3)=3
lo
g
3
x
(
3
)
=
3
\newline
Answer:
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Solve the following for `x`
\newline
log
(
2
x
)
−
log
(
x
−
3
)
=
1
\log(2x)-\log(x-3)=1
lo
g
(
2
x
)
−
lo
g
(
x
−
3
)
=
1
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1
2
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