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Solve for a positive value of 
x.

log_(2)(64)=x
Answer:

Solve for a positive value of x x .\newlinelog2(64)=x \log _{2}(64)=x \newlineAnswer:

Full solution

Q. Solve for a positive value of x x .\newlinelog2(64)=x \log _{2}(64)=x \newlineAnswer:
  1. Recognize Base and Value: Recognize the base of the logarithm and the value inside the logarithm.\newlineWe have log2(64)=x\log_2(64) = x, where the base of the logarithm is 22 and the value inside the logarithm is 6464.
  2. Convert to Exponential: Convert the logarithmic equation into an exponential equation.\newlineThe logarithmic equation log2(64)=x\log_2(64) = x means 22 raised to the power xx equals 6464.\newlineSo, we write it as 2x=642^x = 64.
  3. Find Power of 22: Find a power of 22 that equals 6464. We know that 26=642^6 = 64 because 2×2×2×2×2×2=642 \times 2 \times 2 \times 2 \times 2 \times 2 = 64.
  4. Set Exponent Equal: Set the exponent equal to xx. Since 2x=642^x = 64 and 26=642^6 = 64, we can conclude that x=6x = 6.

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