Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Solve for a positive value of 
x.

log_(8)(512)=x
Answer:

Solve for a positive value of x x .\newlinelog8(512)=x \log _{8}(512)=x \newlineAnswer:

Full solution

Q. Solve for a positive value of x x .\newlinelog8(512)=x \log _{8}(512)=x \newlineAnswer:
  1. Recognize Equation Form: Recognize the form of the equation.\newlineThe equation is in the form of a logarithm with base 88 and the argument is 512512. We need to find the exponent xx such that 88 raised to the power of xx equals 512512.
  2. Convert to Exponential: Convert the logarithmic equation to an exponential equation.\newlineUsing the definition of a logarithm, we can rewrite the equation log8512=x\log_{8} 512 = x as 8x=5128^{x} = 512.
  3. Find Common Base: Find a common base for 88 and 512512. Both 88 and 512512 are powers of 22. 88 is 232^3 and 512512 is 292^9. So we can rewrite the equation as (23)x=29(2^3)^x = 2^9.
  4. Simplify Left Side: Simplify the left side of the equation using the power of a power property.\newlineUsing the power of a power property (ab)c=abc(a^b)^c = a^{b*c}, we get 23x=292^{3x} = 2^9.
  5. Set Exponents Equal: Since the bases are equal, the exponents must be equal. We can now set the exponents equal to each other: 3x=93x = 9.
  6. Solve for x: Solve for x.\newlineDivide both sides of the equation by 33 to isolate x: x=93x = \frac{9}{3}.
  7. Calculate x Value: Calculate the value of x.\newlinex=93=3x = \frac{9}{3} = 3.

More problems from Product property of logarithms