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Solve the following logarithm problem for the positive solution for 
x.

log_(2)x=-5
Answer:

Solve the following logarithm problem for the positive solution for x x .\newlinelog2x=5 \log _{2} x=-5 \newlineAnswer:

Full solution

Q. Solve the following logarithm problem for the positive solution for x x .\newlinelog2x=5 \log _{2} x=-5 \newlineAnswer:
  1. Understand Problem: Understand the problem and the logarithmic equation.\newlineWe need to find the value of xx such that log2(x)=5\log_2(x) = -5. This means we are looking for the number xx that, when 22 is raised to the power of 5-5, equals xx.
  2. Convert to Exponential: Convert the logarithmic equation to an exponential equation.\newlineUsing the definition of a logarithm, we can rewrite the equation log2(x)=5\log_2(x) = -5 as an exponential equation: 25=x2^{-5} = x.
  3. Calculate Value: Calculate the value of 22 raised to the power of 5-5. 252^{-5} is the same as 1/(25)1/(2^5). Since 25=322^5 = 32, we have 1/321/32 as the value for xx.
  4. Verify Solution: Verify that the solution is positive.\newlineSince 132\frac{1}{32} is a positive number, we have found the positive solution for xx.

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