Resources
Testimonials
Plans
Sign in
Sign up
Resources
Testimonials
Plans
Home
Math Problems
Calculus
Find higher derivatives of rational and radical functions
f
′
(
x
)
=
−
5
e
x
and
f
(
3
)
=
22
−
5
e
3
.
f
(
0
)
=
□
\begin{array}{l}f^{\prime}(x)=-5 e^{x} \text { and } f(3)=22-5 e^{3} . \\ f(0)=\square\end{array}
f
′
(
x
)
=
−
5
e
x
and
f
(
3
)
=
22
−
5
e
3
.
f
(
0
)
=
□
Get tutor help
f
′
(
x
)
=
−
27
e
x
and
f
(
6
)
=
36
−
27
e
6
.
f
(
0
)
=
□
\begin{array}{l}f^{\prime}(x)=-27 e^{x} \text { and } f(6)=36-27 e^{6} . \\ f(0)=\square\end{array}
f
′
(
x
)
=
−
27
e
x
and
f
(
6
)
=
36
−
27
e
6
.
f
(
0
)
=
□
Get tutor help
f
′
(
x
)
=
12
x
2
−
6
x
+
2
and
f
(
−
1
)
=
3.
f
(
2
)
=
\begin{array}{l}f^{\prime}(x)=12 x^{2}-6 x+2 \text { and } f(-1)=3 . \\ f(2)=\end{array}
f
′
(
x
)
=
12
x
2
−
6
x
+
2
and
f
(
−
1
)
=
3.
f
(
2
)
=
Get tutor help
f
′
(
x
)
=
5
e
x
and
f
(
7
)
=
40
+
5
e
7
.
f
(
0
)
=
□
\begin{array}{l}f^{\prime}(x)=5 e^{x} \text { and } f(7)=40+5 e^{7} . \\ f(0)=\square\end{array}
f
′
(
x
)
=
5
e
x
and
f
(
7
)
=
40
+
5
e
7
.
f
(
0
)
=
□
Get tutor help
f
′
(
x
)
=
12
e
x
and
f
(
4
)
=
−
16
+
12
e
4
.
f
(
0
)
=
\begin{array}{l}f^{\prime}(x)=12 e^{x} \text { and } f(4)=-16+12 e^{4} . \\ f(0)=\end{array}
f
′
(
x
)
=
12
e
x
and
f
(
4
)
=
−
16
+
12
e
4
.
f
(
0
)
=
Get tutor help
f
(
x
)
=
x
11
f
′
(
x
)
=
\begin{array}{l}f(x)=x^{11} \\ f^{\prime}(x)=\end{array}
f
(
x
)
=
x
11
f
′
(
x
)
=
Get tutor help
Find
d
2
d
x
2
[
2
sin
(
−
4
x
−
3
)
]
\frac{d^{2}}{d x^{2}}[2 \sin (-4 x-3)]
d
x
2
d
2
[
2
sin
(
−
4
x
−
3
)]
.
Get tutor help
h
(
x
)
=
(
5
−
6
x
)
5
h
′
(
x
)
=
?
\begin{aligned} h(x) & =(5-6 x)^{5} \\ h^{\prime}(x) & =? \end{aligned}
h
(
x
)
h
′
(
x
)
=
(
5
−
6
x
)
5
=
?
\newline
Choose
1
1
1
answer:
\newline
(A)
−
6
x
5
+
5
x
4
(
5
−
6
x
)
-6 x^{5}+5 x^{4}(5-6 x)
−
6
x
5
+
5
x
4
(
5
−
6
x
)
\newline
(B)
−
30
(
5
−
6
x
)
4
-30(5-6 x)^{4}
−
30
(
5
−
6
x
)
4
\newline
(C)
(
−
6
)
5
(-6)^{5}
(
−
6
)
5
\newline
(D)
5
(
5
−
6
x
)
4
5(5-6 x)^{4}
5
(
5
−
6
x
)
4
Get tutor help
Previous
1
2