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{:[f^(')(x)=-27e^(x)" and "],[f(6)=36-27e^(6).],[f(0)=◻]:}

f(x)=27ex and f(6)=3627e6.f(0)= \begin{array}{l}f^{\prime}(x)=-27 e^{x} \text { and } f(6)=36-27 e^{6} . \\ f(0)=\square\end{array}

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Q. f(x)=27ex and f(6)=3627e6.f(0)= \begin{array}{l}f^{\prime}(x)=-27 e^{x} \text { and } f(6)=36-27 e^{6} . \\ f(0)=\square\end{array}
  1. Find Antiderivative: To find f(0)f(0), we need to integrate the derivative f(x)=27exf'(x) = -27e^x to get the original function f(x)f(x). The antiderivative of 27ex-27e^x is 27ex-27e^x, since the derivative of exe^x is exe^x and the constant multiple rule of integration allows us to pull out the 27-27.
  2. Add Constant C: After finding the antiderivative, we add a constant C to represent the indefinite integral: f(x)=27ex+Cf(x) = -27e^x + C.
  3. Use Given Information: We are given that f(6)=3627e6f(6) = 36 - 27e^6. We can use this information to solve for the constant CC. We substitute xx with 66 in the antiderivative: f(6)=27e6+Cf(6) = -27e^6 + C.
  4. Solve for Constant C: Now we set the equation equal to the given value of f(6)f(6): 27e6+C=3627e6-27e^6 + C = 36 - 27e^6.
  5. Substitute Values: Solving for CC, we add 27e627e^6 to both sides of the equation: C=3627e6+27e6C = 36 - 27e^6 + 27e^6.
  6. Calculate Constant C: Simplifying the right side of the equation, we find that C=36C = 36, since 27e6+27e6-27e^6 + 27e^6 cancels out.
  7. Write Complete Function: Now that we have the value of CC, we can write the complete function f(x)f(x): f(x)=27ex+36f(x) = -27e^x + 36.
  8. Substitute xx with 00: To find f(0)f(0), we substitute xx with 00 in the function f(x)f(x): f(0)=27e0+36f(0) = -27e^0 + 36.
  9. Simplify Equation: Since e0e^0 is equal to 11, the equation simplifies to: f(0)=27(1)+36f(0) = -27(1) + 36.
  10. Calculate f(0)f(0): Calculating the value, we get f(0)=27+36f(0) = -27 + 36.
  11. Calculate f(0)f(0): Calculating the value, we get f(0)=27+36f(0) = -27 + 36.Finally, we find that f(0)=9f(0) = 9.

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