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{:[f^(')(x)=12e^(x)" and "],[f(4)=-16+12e^(4).],[f(0)=]:}

f′(x)=12ex and f(4)=−16+12e4.f(0)= \begin{array}{l}f^{\prime}(x)=12 e^{x} \text { and } f(4)=-16+12 e^{4} . \\ f(0)=\end{array}

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Find higher derivatives of rational and radical functionsright chevron icon

Full solution

Q. f′(x)=12ex and f(4)=−16+12e4.f(0)= \begin{array}{l}f^{\prime}(x)=12 e^{x} \text { and } f(4)=-16+12 e^{4} . \\ f(0)=\end{array}
  1. Given value for f(44): To find f(4)f(4), we are directly given the value in the problem statement. There's no calculation needed for f(4)f(4).\newlinef(4)=−16+12e4f(4) = -16 + 12e^4
  2. Issue with f(00) calculation: To find f(0)f(0), we need to understand that the value is directly given in the problem statement, but it seems there was a mistake in the problem statement as it did not provide a complete expression for f(0)f(0). Without the complete information, we cannot calculate f(0)f(0).

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