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Find
P_(3) for
f(x)=ln x centered at
c=2.(7pts)

$3$ . Find $P_{3}$ for $f(x)=\ln x$ centered at $c=2 .(7 \mathrm{pts})$

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Find values of derivatives using limits

Full solution

Q.

3

. Find

P_{3}

for

f(x)=\ln x

centered at

c=2 .(7 \mathrm{pts})

Identify Function & Expansion Point: Identify the function and the point of expansion. $\newline$ We are given the function $f(x) = \ln(x)$ and we need to find the third-degree Taylor polynomial ( $P_3$ ) centered at $c = 2$ .
Calculate First Derivative: Calculate the first derivative of $f(x)$ . The first derivative of $f(x) = \ln(x)$ is $f'(x) = \frac{1}{x}$ . We evaluate this at $x = 2$ to get $f'(2) = \frac{1}{2}$ .
Calculate Second Derivative: Calculate the second derivative of $f(x)$ . $\newline$ The second derivative of $f'(x) = \frac{1}{x}$ is $f''(x) = -\frac{1}{x^2}$ . We evaluate this at $x = 2$ to get $f''(2) = -\frac{1}{4}$ .
Calculate Third Derivative: Calculate the third derivative of $f(x)$ . The third derivative of $f''(x) = -\frac{1}{x^2}$ is $f(x) = \frac{2}{x^3}$ . We evaluate this at $x = 2$ to get $f(2) = \frac{2}{8} = \frac{1}{4}$ .
Write Taylor Polynomial Formula: Write down the formula for the third-degree Taylor polynomial. $\newline$ The third-degree Taylor polynomial is given by: $\newline$ $P_3(x) = f(c) + f'(c)(x - c) + \frac{f''(c)(x - c)^2}{2!} + \frac{f(c)(x - c)^3}{3!}$
Substitute Values: Substitute the values into the Taylor polynomial formula. $\newline$ Using the values from the previous steps, we get: $\newline$ $P_3(x) = \ln(2) + \left(\frac{1}{2}\right)(x - 2) - \left(\frac{1}{4}\right)\frac{(x - 2)^2}{2!} + \left(\frac{1}{4}\right)\frac{(x - 2)^3}{3!}$
Simplify Polynomial: Simplify the polynomial. $\newline$ $P_3(x) = \ln(2) + \left(\frac{1}{2}\right)(x - 2) - \left(\frac{1}{8}\right)(x - 2)^2 + \left(\frac{1}{24}\right)(x - 2)^3$ $\newline$ This is the third-degree Taylor polynomial for $f(x) = \ln(x)$ centered at $c = 2$ .

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