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Math Problems
Calculus
Find values of derivatives using limits
statses
u
u
u
have to write in that way
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How are the solutions to the inequality
−
3
x
≥
18
-3x \geq 18
−
3
x
≥
18
different from the solutions to
−
3
x
>
18
-3x > 18
−
3
x
>
18
? Explain your reasoning.
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The coefficient of
n
2
n^2
n
2
of the expanded form of
(
5
n
2
−
4
n
−
3
)
2
(5n^2 - 4n - 3)^2
(
5
n
2
−
4
n
−
3
)
2
is
−
14
-14
−
14
.
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x
−
5
y
=
−
15
x-5 y=-15
x
−
5
y
=
−
15
\newline
Complete the missing value in the solution to the equation.
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7
7
7
. Write
>
,
<
>,<
>
,
<
, or
=
=
=
in the circle tc the statement true.
\newline
(
368
×
19
)
−
24
(368 \times 19)-24
(
368
×
19
)
−
24
\newline
\qquad
(
368
×
19
)
(368 \times 19)
(
368
×
19
)
\newline
14
14
14
\newline
\qquad
8
8
8
. Insert parentheses to make the statement true.
\newline
7
+
6
×
14
−
9
=
37
7+6 \times 14-9=37
7
+
6
×
14
−
9
=
37
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\begin{aligned} 3x-4y&=10 \newline 2x-4y&=6 \end{aligned}If
x
x
x
satisfies the given system of equations, what is the value of
x
x
x
?
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Solve for
u
u
u
.
\newline
−
3
=
2
u
-3=\frac{2}{u}
−
3
=
u
2
\newline
Simplify your answer as much as possible.
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In the diagram,
△
J
L
M
∼
△
Q
S
T
\triangle J L M \sim \triangle Q S T
△
J
L
M
∼
△
QST
. Find the value of
x
x
x
. Write your answer as a decimal, if necessan
\newline
x
=
1.5
x=1.5
x
=
1.5
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ue of
x
x
x
in the equation below.
\newline
x
3
=
10
\frac{x}{3}=10
3
x
=
10
\newline
Attempt
1
1
1
out of
2
2
2
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Use the relationship you determined to write an equation to help you solve for
X
X
X
.
\newline
(
6
x
−
18
)
+
(
6
x
)
=
90
(6 x-18)+(6 x)=90
(
6
x
−
18
)
+
(
6
x
)
=
90
\newline
Cómbine Like Terms
\newline
6
x
−
18
+
6
x
=
90
6 x-18+6 x=90
6
x
−
18
+
6
x
=
90
\newline
Enter the result.
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the derivative of the function using th
\newline
16
16
16
.
g
(
x
)
=
−
3
g(x)=-3
g
(
x
)
=
−
3
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Graph the solution to
−
2
x
−
5
≤
−
7
-2 x-5 \leq-7
−
2
x
−
5
≤
−
7
.
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Solve the system of equations.
\newline
7
y
+
10
x
−
8
=
0
2
y
−
5
x
−
18
=
0
\begin{aligned} &7y+10x - 8=0 \\\\ & 2 y-5x-18=0 \end{aligned}
7
y
+
10
x
−
8
=
0
2
y
−
5
x
−
18
=
0
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gradient of
y
=
4
x
2
−
6
x
−
5
y=4x^2-6x-5
y
=
4
x
2
−
6
x
−
5
at
x
=
1.5
x=1.5
x
=
1.5
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f
(
x
)
=
x
−
1
f(x) = \sqrt{x} - 1
f
(
x
)
=
x
−
1
If the index is even, determine at least
3
3
3
points, including the key point. If the index is odd, determine at least
5
5
5
points.
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\begin{aligned}-6.4x&=4y+2.1\ky+3.2x&=5.8\end{aligned}
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0.7
a
−
0.8
b
=
−
0.1
a
−
1.4
=
−
6
(
b
−
0.1
)
\begin{aligned} 0.7 a - 0.8b &= -0.1\ a - 1.4 &= -6(b - 0.1) \end{aligned}
0.7
a
−
0.8
b
=
−
0.1
a
−
1.4
=
−
6
(
b
−
0.1
)
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Let
R
R
R
be the region bounded by the curves
y
=
x
2
y = x^2
y
=
x
2
,
x
=
0
x = 0
x
=
0
, and
y
=
6
y = 6
y
=
6
. What is the volume of the solid generated by rotating
R
R
R
about the
y
y
y
-axis?
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Find the derivative of
f
(
x
)
=
3
x
f(x)=3x
f
(
x
)
=
3
x
at
x
=
2
x=2
x
=
2
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3
3
3
. Find
P
3
P_{3}
P
3
for
f
(
x
)
=
ln
x
f(x)=\ln x
f
(
x
)
=
ln
x
centered at
c
=
2.
(
7
p
t
s
)
c=2 .(7 \mathrm{pts})
c
=
2.
(
7
pts
)
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Solve the equation. Check your solution.
\newline
4
x
−
8
+
2
x
=
−
32
4 x-8+2 x=-32
4
x
−
8
+
2
x
=
−
32
\newline
The solution set is (Simplify your answer)
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Find the derivative of
\newline
f
(
x
)
=
3
x
f(x)=3x
f
(
x
)
=
3
x
at
\newline
x
=
2
x=2
x
=
2
Solution:
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What is the value of
d
d
x
(
x
−
3
)
\frac{d}{d x}\left(x^{-3}\right)
d
x
d
(
x
−
3
)
at
x
=
3
x=3
x
=
3
?
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What is the value of
d
d
x
(
1
x
)
\frac{d}{d x}\left(\frac{1}{x}\right)
d
x
d
(
x
1
)
at
x
=
6
x=6
x
=
6
?
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What is the value of
d
d
x
(
x
)
\frac{d}{d x}(\sqrt{x})
d
x
d
(
x
)
at
x
=
9
x=9
x
=
9
?
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