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Dingane has been observing a certain stock for the last few years and he sees that it can be modeled as a function 
S(t) of time 
t (in days) using a sinusoidal expression of the form 
a*sin(b*t)+d.
On day 
t=0, the stock is at its average value of 
$3.47 per share, but 91.25 days later, its value is down to its minimum of 
$1.97.
Find 
S(t).

t should be in radians.

S(t)=

Dingane has been observing a certain stock for the last few years and he sees that it can be modeled as a function S(t) S(t) of time t t (in days) using a sinusoidal expression of the form asin(bt)+d a \cdot \sin (b \cdot t)+d .\newlineOn day t=0 t=0 , the stock is at its average value of $3.47 \$ 3.47 per share, but 9191.2525 days later, its value is down to its minimum of $1.97 \$ 1.97 .\newlineFind S(t) S(t) .\newlinet t should be in radians.\newlineS(t)= S(t)=

Full solution

Q. Dingane has been observing a certain stock for the last few years and he sees that it can be modeled as a function S(t) S(t) of time t t (in days) using a sinusoidal expression of the form asin(bt)+d a \cdot \sin (b \cdot t)+d .\newlineOn day t=0 t=0 , the stock is at its average value of $3.47 \$ 3.47 per share, but 9191.2525 days later, its value is down to its minimum of $1.97 \$ 1.97 .\newlineFind S(t) S(t) .\newlinet t should be in radians.\newlineS(t)= S(t)=
  1. Given Average Value: The stock's average value is given at t=0t=0, which is the midline of the sinusoidal function. So d=$3.47d = \$3.47.
  2. Calculate Period: Since the stock reaches its minimum value 91.2591.25 days later, this corresponds to a quarter of the sinusoidal period. Therefore, the period P=91.25×4P = 91.25 \times 4 days.
  3. Calculate b: Calculate the value of b, which is related to the period by the formula b=2πPb = \frac{2\pi}{P}. So b=2π91.25×4b = \frac{2\pi}{91.25 \times 4}.
  4. Calculate Amplitude: The amplitude aa is the difference between the average value and the minimum value. So a=$3.47$1.97a = \$3.47 - \$1.97.
  5. Calculate aa: Calculate the amplitude aa. a=($)3.47($)1.97=($)1.50a = (\$)3.47 - (\$)1.97 = (\$)1.50.
  6. Write Function S(t)S(t): Now we have all the parameters to write down the function S(t)S(t). S(t)=asin(bt)+dS(t) = a\sin(b\cdot t) + d.
  7. Substitute Values: Substitute the values of aa, bb, and dd into the function. S(t)=1.50sin(2π91.254t)+3.47S(t) = 1.50\cdot\sin\left(\frac{2\pi}{91.25 \cdot 4}\cdot t\right) + 3.47.
  8. Simplify Expression for bb: Simplify the expression for bb. b=2π(91.25×4)=2π365b = \frac{2\pi}{(91.25 \times 4)} = \frac{2\pi}{365}.
  9. Final Function S(t): Write the final function S(t). S(t)=1.50sin(2π365t)+3.47S(t) = 1.50\cdot\sin\left(\frac{2\pi}{365}\cdot t\right) + 3.47.

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