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(-33-2i)-(50+9i)= Express your answer in the form (a+bi).

(−33−2i)−(50+9i)= (-33-2 i)-(50+9 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .

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Full solution

Q. (−33−2i)−(50+9i)= (-33-2 i)-(50+9 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .
  1. Problem and Preparation: Write down the problem and prepare to subtract the complex numbers.\newline(−33−2i)−(50+9i)(-33-2i) - (50+9i)\newlineWe will subtract the real parts and the imaginary parts separately.
  2. Subtracting Real Parts: Subtract the real parts.\newlineThe real part of the first complex number is −33-33 and the real part of the second complex number is 5050.\newlineSo, we calculate −33−50-33 - 50.\newline−33−50=−83-33 - 50 = -83
  3. Subtracting Imaginary Parts: Subtract the imaginary parts.\newlineThe imaginary part of the first complex number is −2i-2i and the imaginary part of the second complex number is 9i9i.\newlineSo, we calculate −2i−9i-2i - 9i.\newline−2i−9i=−11i-2i - 9i = -11i
  4. Combining Results: Combine the results of the real and imaginary parts.\newlineWe combine the results from Step 22 and Step 33 to get the final answer.\newline−83−11i-83 - 11i\newlineThis is the simplified form of the complex number after subtraction.

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