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(3-91 i)+(67)= Express your answer in the form (a+bi).

(3−91i)+(67)= (3-91 i)+(67)= \newlineExpress your answer in the form (a+bi) (a+b i) .

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Full solution

Q. (3−91i)+(67)= (3-91 i)+(67)= \newlineExpress your answer in the form (a+bi) (a+b i) .
  1. Add Real Parts: Add the real parts of the complex numbers.\newlineThe real part of (3−91i)(3-91i) is 33, and the real part of 6767 is 6767. Adding these together gives us:\newline3+67=703 + 67 = 70
  2. Add Imaginary Parts: Add the imaginary parts of the complex numbers.\newlineThe imaginary part of (3−91i)(3-91i) is −91i-91i, and since 6767 has no imaginary part, we can consider it as 0i0i. Adding these together gives us:\newline−91i+0i=−91i-91i + 0i = -91i
  3. Combine Results: Combine the results from Step 11 and Step 22 to express the sum in the form (a+bi)(a+bi).\newlineFrom Step 11, we have the real part a=70a = 70.\newlineFrom Step 22, we have the imaginary part b=−91ib = -91i.\newlineTherefore, the sum is:\newline(70)+(−91i)=70−91i(70) + (-91i) = 70 - 91i

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