Soit l’expression bool\'eenne suivante : E(x,y,z,t)=xt+x′z′t+xy′zt′+x′y′t+x′yzt+xy′z′ Aˋ l’aide d’un diagramme de Karnaugh, d\'eterminer une somme r\'eduite de cette expression. Get tutor helpNote: Attempt all questions.Question IUsepatital differentiation to evaluate fx and fy of the following functions:i. f(x,y,z)=x2sinxyzii f(x,y)=3ln(x3+y3)Question 2Wiserimplicit differentiation to find ∂x∂z and ∂v∂z,3x2yz2−xsiny+5xy=3Question 3Apply double integral to evaluate the function f(x,y)=x2y2+x over the region in the first quadrant bounded by the lines y=x,y=2x,x=1,x=2.Question 4Apply line integral to evaluate ∫(2y+x2−z2)d s over the line segment x=t,y=t2,z=1,0≤t≤1. from fy0 to fy1.Question 5γ=(t,t2,1)Solve the homogeneous differential equationx2dy−y(x+y)dx=0,y(0)=1 Get tutor help4. Let a,b,c,k be rational numbers such that k is not a perfect cube.If a+bk1/3+ck2/3 then prove that a=b=c=0.Sol. Given, a+bkis+ck2β=0Multiplying both sides by k1/3, we haveak1/3+bk2/3+ck=0. Get tutor help(b) The first snow of the season begins to fall during the night. The depth of the snow, h, increases at a constant rate through the night and the following day. At 6 am a snow plough begins to clear the road of snow. The speed, vkm/h, of the snow plough is inversely proportional to the depth of snow. (This means v=hA where A is a constant.) Let xkm be the distance the snow plough has cleared and let t be the time in hours from the beginning of the snowfall. Let t=T correspond to 6 am. (i) Explain carefully why, for t≥T, 60, where 61 is a constant. (ii) In the period from 6 am to 63 am the snow plough clears 64 of road, but it takes a further 65 hours to clear the next kilometre. At what time did it begin snowing? Get tutor help