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How does h(x)=2xh(x) = 2^x change over the interval from x=1x = 1 to x=2x = 2?\newlineChoices:\newline(A) h(x)h(x) decreases by 2%2\%\newline(B) h(x)h(x) increases by 22\newline(C) h(x)h(x) increases by 100%100\%\newline(D) h(x)h(x) increases by 2%2\%

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Q. How does h(x)=2xh(x) = 2^x change over the interval from x=1x = 1 to x=2x = 2?\newlineChoices:\newline(A) h(x)h(x) decreases by 2%2\%\newline(B) h(x)h(x) increases by 22\newline(C) h(x)h(x) increases by 100%100\%\newline(D) h(x)h(x) increases by 2%2\%
  1. Calculate h(x)h(x): Calculate h(x)h(x) when x=1x = 1.\newlineh(1)=21=2h(1) = 2^1 = 2
  2. Calculate h(x)h(x): Calculate h(x)h(x) when x=2x = 2.\newlineh(2)=22=4h(2) = 2^2 = 4
  3. Find change in h(x)h(x): Find the change in h(x)h(x) from x=1x = 1 to x=2x = 2.\newlineChange = h(2)−h(1)=4−2=2h(2) - h(1) = 4 - 2 = 2
  4. Determine percentage increase: Determine the percentage increase from h(1)h(1) to h(2)h(2).\newlinePercentage increase = (Change/h(1))×100%=(22)×100%=100%(\text{Change} / h(1)) \times 100\% = (\frac{2}{2}) \times 100\% = 100\%

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