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Math Problems
Precalculus
Evaluate rational exponents
y
2
−
36
6
y
y
2
+
6
y
5
y
3
=
\frac{\frac{y^{2}-36}{6 y}}{\frac{y^{2}+6 y}{5 y^{3}}}=
5
y
3
y
2
+
6
y
6
y
y
2
−
36
=
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4
3
10
−
2
10
4 \frac{3}{10}-\frac{2}{10}
4
10
3
−
10
2
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4
8
4
−
4
\frac{4^{8}}{4^{-4}}
4
−
4
4
8
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−
6
-6
−
6
. Non-GDC
\newline
Let
f
(
x
)
=
2
−
3
x
5
2
x
3
,
x
∈
R
,
x
≠
0
f(x)=\frac{2-3 x^{5}}{2 x^{3}}, x \in \mathbb{R}, x \neq 0
f
(
x
)
=
2
x
3
2
−
3
x
5
,
x
∈
R
,
x
=
0
.
\newline
(a) The graph of
y
=
f
(
x
)
y=f(x)
y
=
f
(
x
)
has a local maximum at A. Find the coordinates of A.
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1 8 \longdiv { 9 , 8 7 6 }
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№
1
1
1
\newline
Сравнить
8
0
13
80^{13}
8
0
13
и
1
0
28
10^{28}
1
0
28
.
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Extension
\newline
Writs a question that could give an answer of
a
3
b
−
3
c
3
\frac{a^{3} b^{-3}}{c^{3}}
c
3
a
3
b
−
3
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1
1
1
. Hasil dari
lim
x
→
∞
x
−
2
x
x
\lim _{x \rightarrow \infty} \frac{x-2 \sqrt{x}}{\sqrt{x}}
lim
x
→
∞
x
x
−
2
x
adalah..
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8
8
8
.
11
24
−
3
8
\begin{array}{r}\frac{11}{24} \\ -\frac{3}{8} \\ \hline\end{array}
24
11
−
8
3
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4
4
4
. Perhatikan gambar berikut !
\newline
Pada gambar di atas, diketahui
∠
B
8
=
(
4
x
+
46
)
∘
\angle B 8=(4 x+46)^{\circ}
∠
B
8
=
(
4
x
+
46
)
∘
dan
∠
A
1
=
(
5
x
+
25
)
∘
\angle A 1=(5 x+25)^{\circ}
∠
A
1
=
(
5
x
+
25
)
∘
. Maka Besar sudut A
2
2
2
adalah ...
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4
4
4
- Calculer le p\'erim\`etre de ces figures
\newline
a)
\newline
b)
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2
2
2
. Salah satu merk ice cream meluncurkan produk baru yang belum pernah dibuat oleh merek yang lain. Produk tersebut benupa es krim yang berbentuk bola seperti gambar berikut
\newline
Pada kemasan tersebut tertulis neto
99
m
l
99 \mathrm{ml}
99
ml
, dan ternyata isi kemasan tersebut tidak penuh tetapi hanya sekitar
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14
−
8
6
8
14-8 \frac{6}{8}
14
−
8
8
6
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1
1
1
. Sebuah kolam ikan berbentuk balok dengan ukuran panjang
190
c
m
190 \mathrm{~cm}
190
cm
, lebar
110
c
m
110 \mathrm{~cm}
110
cm
, dan kedalaman
80
80
80
c
m
\mathrm{cm}
cm
. Jika kolam ikan tersebut terisi penuh air, volume air dalam kolam adalah . . .
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c)
1
6
−
x
=
1
64
16^{-x}=\frac{1}{64}
1
6
−
x
=
64
1
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(c)
c
2
+
c
c
d
+
d
\frac{c^{2}+c}{c d+d}
c
d
+
d
c
2
+
c
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Berapakah besar sudut AOC?
\newline
Sebuah lapangan berbentuk lingkaran dengan diameter
56
56
56
m
\mathrm{m}
m
. Di sekeliling lapangan akan dipasang lampu dengan jarak
4
m
4 \mathrm{~m}
4
m
. Berapa banyak lampu yang diperlukan?
\newline
Perhatikan gambar di bawah ini
\newline
Nilai
y
y
y
adalah ....
\newline
Jika
1
3
−
a
=
27
\frac{1}{3^{-a}}=27
3
−
a
1
=
27
, maka nilai dari a adalah ....
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Find the value of
9
−
1
4
−
1
8
9-\frac{1}{4}-\frac{1}{8}
9
−
4
1
−
8
1
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Identify the asymptotes, domain, (Lesson
8
8
8
−
3
-3
−
3
)
\newline
17
17
17
.
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(a)
705
÷
7
=
705 \div 7=
705
÷
7
=
\newline
(b)
\newline
7 \longdiv { 7 0 5 }
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16
π
\sqrt{\frac{16}{\pi}}
π
16
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(
x
2
y
−
1
/
2
)
\left(x^{2} y^{-1 / 2}\right)
(
x
2
y
−
1/2
)
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lim
n
→
∞
(
a
−
1
+
b
n
a
)
n
\lim _{n \rightarrow \infty}\left(\frac{a-1+\sqrt[n]{b}}{a}\right)^{n}
lim
n
→
∞
(
a
a
−
1
+
n
b
)
n
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16
9
1
/
2
x
−
4
(
13
x
y
)
0
\frac{169^{1 / 2} x^{-4}}{(13 x y)^{0}}
(
13
x
y
)
0
16
9
1/2
x
−
4
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7
9
−
4
5
9
\frac{7}{9}-4 \frac{5}{9}
9
7
−
4
9
5
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y
=
10
x
3
−
10
x
y=10 x^{3}-10 x
y
=
10
x
3
−
10
x
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rasional dari
a
2
a
3
a
2
6
5
2
\sqrt[2]{a^{2} \sqrt[5]{a^{3} \sqrt[6]{a^{2}}}}
2
a
2
5
a
3
6
a
2
adalah ...
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25
12
+
(
−
5
36
)
\frac{25}{12}+\left(-\frac{5}{36}\right)
12
25
+
(
−
36
5
)
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4
b
24
3
−
↓
64
3
+
b
81
3
4 b \sqrt[3]{24}-\downarrow \sqrt[3]{64}+b \sqrt[3]{81}
4
b
3
24
−
↓
3
64
+
b
3
81
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f
′
(
x
)
=
d
v
d
x
(
ln
(
x
3
+
4
x
2
)
4
x
)
f^{\prime}(x)=\frac{d v}{d x}\left(\frac{\ln \left(x^{3}+4 x^{2}\right)}{4 x}\right)
f
′
(
x
)
=
d
x
d
v
(
4
x
l
n
(
x
3
+
4
x
2
)
)
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of
−
6
24
-6 \sqrt{24}
−
6
24
?
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1
1
1
. Solve the equ
\newline
12
−
1
4
÷
8
=
12-\frac{1}{4} \div 8=
12
−
4
1
÷
8
=
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Rewrite in simplest terms:
0.4
(
5
y
+
6
z
)
+
7
z
−
0.1
(
8
z
+
10
y
)
0.4(5 y+6 z)+7 z-0.1(8 z+10 y)
0.4
(
5
y
+
6
z
)
+
7
z
−
0.1
(
8
z
+
10
y
)
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(
16
x
8
)
1
2
12
x
\frac{\left(16 x^{8}\right)^{\frac{1}{2}}}{12 x}
12
x
(
16
x
8
)
2
1
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−
25
9
+
2
5
\frac{-25}{9}+\frac{2}{5}
9
−
25
+
5
2
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4
4
4
.) The solution to
x
2
−
4
x
−
6
=
0
x^{2}-4 x-6=0
x
2
−
4
x
−
6
=
0
in simplest surd form is
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sin
(
2
arccos
(
3
7
)
)
\sin \left(2 \arccos (\frac{3}{7})\right)
sin
(
2
arccos
(
7
3
)
)
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e)
−
2
7
4
3
-27^{\frac{4}{3}}
−
2
7
3
4
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exttt{-}rac{
9
9
9
}{
40
40
40
}= exttt{-}
\newline
Convert in decinals
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Convert in decimals.
\newline
−
(
9
)
/
(
40
)
=
-(9)/(40) =
−
(
9
)
/
(
40
)
=
___
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(iii)
1
12
\frac{1}{\sqrt{12}}
12
1
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x
2
−
log
4
(
x
)
=
π
x^{2-\log _{4}(x)}=\pi
x
2
−
l
o
g
4
(
x
)
=
π
.
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Dalam babak penyisihan suatu turmamen,
20
20
20
pecatur satu sama lain bertanding satu kali. Banyak pertandingan yang terjadi adalah....
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ln
(
8
)
−
ln
(
4
)
\ln (8) - \ln (4)
ln
(
8
)
−
ln
(
4
)
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p
(
x
)
=
(
x
−
0.95
)
(
500
−
100
x
)
p(x)=(x-0.95)(500-100x)
p
(
x
)
=
(
x
−
0.95
)
(
500
−
100
x
)
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12
v
6
\sqrt{12 v^{6}}
12
v
6
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What is the solution set of
x
+
2
2
x
+
1
=
x
−
2
3
\frac{x+2}{2 x+1}=\frac{x-2}{3}
2
x
+
1
x
+
2
=
3
x
−
2
?
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Simplify the following fraction:
16
30
\frac{16}{30}
30
16
\newline
Answer:
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Find
4
x
3
\sqrt{4x^{3}}
4
x
3
at
x
=
4
x=4
x
=
4
.
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Which expression is equivalent to
9
h
+
9
h
9h + 9h
9
h
+
9
h
?
\newline
Choices:
\newline
(A)
h
+
18
h + 18
h
+
18
\newline
(B)
h
18
h^{18}
h
18
\newline
(C)
17
h
17h
17
h
\newline
(D)
18
h
18h
18
h
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