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Math Problems
Precalculus
Evaluate rational exponents
1
4
+
8
12
=
?
\frac{1}{4}+\frac{8}{12}=?
4
1
+
12
8
=
?
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Find forir rationa numlees feetwiven
2
7
\frac{2}{7}
7
2
20
20
20
8
21
\frac{8}{21}
21
8
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d
d
x
[
cos
n
−
1
x
]
\frac{d}{d x}\left[\cos ^{n-1} x\right]
d
x
d
[
cos
n
−
1
x
]
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(b)
g
(
x
)
=
e
cosh
(
ln
(
x
)
)
g(x)=e^{\cosh (\ln (x))}
g
(
x
)
=
e
c
o
s
h
(
l
n
(
x
))
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d
d
x
(
sin
2
(
x
)
)
\frac{d}{d x}\left(\sin ^{2}(x)\right)
d
x
d
(
sin
2
(
x
)
)
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x
x
+
2
+
x
+
2
\frac{x}{x+2+\sqrt{x+2}}
x
+
2
+
x
+
2
x
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4
4
4
. Определите координаты единичного вектора, сонаправленного с
\newline
*
1
1
1
point
\newline
вектором
\newline
p
ˉ
(
−
7
;
3
)
\bar{p}(-\sqrt{7} ; 3)
p
ˉ
(
−
7
;
3
)
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x
2
−
14
x
+
24
2
x
+
6
>
x
\frac{x^{2}-14 x+24}{2 x+6}>x
2
x
+
6
x
2
−
14
x
+
24
>
x
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Solve for s:
−
7
=
s
+
(
−
13
)
-7=s+\left(-13\right)
−
7
=
s
+
(
−
13
)
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−
57
=
d
6
−
72
-57=\frac{d}{6}-72
−
57
=
6
d
−
72
Find the value of
b
b
b
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y
=
ln
x
−
2
x
+
2
y=\ln \frac{x-2}{x+2}
y
=
ln
x
+
2
x
−
2
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whatever the
;
)
)
;))
;
))
person wants.
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Simplify the expression :
a
b
∗
arctan
(
cot
x
b
)
ab*\arctan\left(\frac{\cot x}{b}\right)
ab
∗
arctan
(
b
c
o
t
x
)
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Solve for
x
x
x
:
\newline
x
=
25
100
x=\sqrt{\frac{25}{100}}
x
=
100
25
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7
x
⩽
5
x
+
7
3
+
2
x
−
3
(
1
2
)
7 x \leqslant \frac{5 x+7}{3}+2 x-3\left(\frac{1}{2}\right)
7
x
⩽
3
5
x
+
7
+
2
x
−
3
(
2
1
)
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70
÷
(
6
+
2
2
)
70\div(6+2^{2})
70
÷
(
6
+
2
2
)
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likh kr khud aata h
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3
3
3
.
d
M
d
t
=
1
4
(
40
−
M
)
\frac{d M}{d t}=\frac{1}{4}(40-M)
d
t
d
M
=
4
1
(
40
−
M
)
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Evaluate:
\newline
(
8
−
6.24
)
2
(8-6.24)2
(
8
−
6.24
)
2
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−
5
x
1
3
−
10
=
−
20
-5 x^{\frac{1}{3}}-10=-20
−
5
x
3
1
−
10
=
−
20
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Factorise:
\newline
x
2
−
6
x
+
8
=
0
x^{2}-6x+8=0
x
2
−
6
x
+
8
=
0
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4
4
4
. Graph
p
(
x
)
p(x)
p
(
x
)
using the graphs of
f
(
x
)
f(x)
f
(
x
)
and
g
(
x
)
g(x)
g
(
x
)
that are shown in the graph.
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Now Learning
\newline
Exponent Rules
\newline
(
+
12
13
)
0
=
?
\left(+\frac{12}{13}\right)^{0}=?
(
+
13
12
)
0
=
?
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lim
x
→
∞
(
2
x
+
5
−
4
x
2
−
3
x
+
1
)
\lim _{x \rightarrow \infty}\left(2 x+5-\sqrt{4 x^{2}-3 x+1}\right)
lim
x
→
∞
(
2
x
+
5
−
4
x
2
−
3
x
+
1
)
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x
2
+
12
x
+
36
x^{2}+12 x+36
x
2
+
12
x
+
36
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(
1
+
sin
10
π
2
)
\left(1+\sin \frac{10 \pi}{2}\right)
(
1
+
sin
2
10
π
)
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1
+
sin
17
π
2
1+\sin \frac{17 \pi}{2}
1
+
sin
2
17
π
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sec
(
tan
−
1
4
3
)
=
1
cos
(
tan
−
1
4
3
)
\sec \left(\tan ^{-1} \frac{4}{3}\right)=\frac{1}{\cos \left(\tan ^{-1} \frac{4}{3}\right)}
sec
(
tan
−
1
3
4
)
=
c
o
s
(
t
a
n
−
1
3
4
)
1
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startl
\newline
−
8
x
18
4
x
6
\frac{-8 x^{18}}{4 x^{6}}
4
x
6
−
8
x
18
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10
10
10
.
14
u
−
9
7
u
8
=
\frac{14 u^{-9}}{7 u^{8}}=
7
u
8
14
u
−
9
=
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g
(
x
)
=
4
x
−
5
g(x)=4x-5
g
(
x
)
=
4
x
−
5
dan
(
f
∘
g
)
(
x
)
=
4
x
−
2
(f \circ g)(x)=4x-2
(
f
∘
g
)
(
x
)
=
4
x
−
2
. Tentukan
f
(
−
3
)
f(-3)
f
(
−
3
)
:...
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cos
43
=
35
x
\cos 43=\frac{35}{x}
cos
43
=
x
35
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Diketahui pecahan-pecahan seperti berikut
1
1
5
;
0
,
8
;
60
%
1 \frac{1}{5} ; 0,8 ; 60 \%
1
5
1
;
0
,
8
;
60%
, dan
7
8
\frac{7}{8}
8
7
. Urutan pecanan dari yang terbesar ke yang terkecil adalah ....
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Jumlah dua buah bilangan sama dengan
30
30
30
. Jika hasil kali kedua bilangan itu sama dengan
200
200
200
, tentukanlah bilangan tersebut!
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площадь квадрата
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x
2
−
2
1
−
2
x
>
1
\frac{x^{2}-2}{1-2 x}>1
1
−
2
x
x
2
−
2
>
1
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na jednak eksponent.
\newline
2
2
2
. Odredi vrijednost od
x
x
x
u binomu
(
(
x
)
1
log
x
+
1
+
x
12
)
6
\left((\sqrt{x})^{\frac{1}{\log x+1}}+\sqrt[12]{x}\right)^{6}
(
(
x
)
l
o
g
x
+
1
1
+
12
x
)
6
čiji je četvrti član razvoja binoma jednak
200
200
200
.
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10
10
10
)
cot
9
π
2
\cot \frac{9 \pi}{2}
cot
2
9
π
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16
16
16
. Evaluate
(
0.027
)
−
1
3
(
2
p
t
s
)
(0.027)^{-\frac{1}{3}}(2 \mathrm{pts})
(
0.027
)
−
3
1
(
2
pts
)
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Lebar persegi panjang adalah sepertiga dari panjang nya. Jika keliling persegi panjang tersebut
56
cm
56\,\text{cm}
56
cm
. Berapakah luas persegi panjang tersebut?
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Writs a question that could give an answer of
(
a
3
b
−
3
)
/
(
c
3
)
(a^{3}b^{-3})/(c^{3})
(
a
3
b
−
3
)
/
(
c
3
)
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4 \longdiv { 1 4 . 8 }
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y
2
−
36
6
y
y
2
+
6
y
5
y
3
=
\frac{\frac{y^{2}-36}{6 y}}{\frac{y^{2}+6 y}{5 y^{3}}}=
5
y
3
y
2
+
6
y
6
y
y
2
−
36
=
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4
3
10
−
2
10
4 \frac{3}{10}-\frac{2}{10}
4
10
3
−
10
2
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4
8
4
−
4
\frac{4^{8}}{4^{-4}}
4
−
4
4
8
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−
6
-6
−
6
. Non-GDC
\newline
Let
f
(
x
)
=
2
−
3
x
5
2
x
3
,
x
∈
R
,
x
≠
0
f(x)=\frac{2-3 x^{5}}{2 x^{3}}, x \in \mathbb{R}, x \neq 0
f
(
x
)
=
2
x
3
2
−
3
x
5
,
x
∈
R
,
x
=
0
.
\newline
(a) The graph of
y
=
f
(
x
)
y=f(x)
y
=
f
(
x
)
has a local maximum at A. Find the coordinates of A.
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1 8 \longdiv { 9 , 8 7 6 }
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№
1
1
1
\newline
Сравнить
8
0
13
80^{13}
8
0
13
и
1
0
28
10^{28}
1
0
28
.
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Extension
\newline
Writs a question that could give an answer of
a
3
b
−
3
c
3
\frac{a^{3} b^{-3}}{c^{3}}
c
3
a
3
b
−
3
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1
1
1
. Hasil dari
lim
x
→
∞
x
−
2
x
x
\lim _{x \rightarrow \infty} \frac{x-2 \sqrt{x}}{\sqrt{x}}
lim
x
→
∞
x
x
−
2
x
adalah..
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1
2
3
...
4
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