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Factorise:
x^(2)-6x+8=0

Factorise: $\newline$ $x^{2}-6x+8=0$

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Evaluate rational exponents

Full solution

Q. Factorise:

\newline

x^{2}-6x+8=0

Identify Equation Type: Identify the type of equation and strategy for solving. $\newline$ We have a quadratic equation in the standard form $ax^2 + bx + c = 0$ , where $a = 1$ , $b = -6$ , and $c = 8$ . We'll use the factoring method to solve it.
Factorize Quadratic Expression: Factorize the quadratic expression. $\newline$ We need two numbers that multiply to $8$ $(a*c)$ and add up to $-6$ $(b)$ . The numbers $-2$ and $-4$ work because $-2 \times -4 = 8$ and $-2 + -4 = -6$ . $\newline$ So, $x^2 - 6x + 8 = (x - 2)(x - 4)$ .
Solve for x: Solve for x by setting each factor equal to zero. $\newline$ $1$ . $x - 2 = 0 \rightarrow x = 2$ $\newline$ $2$ . $x - 4 = 0 \rightarrow x = 4$

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f(x)=\frac{6 x+5}{2-\sqrt{14+5 x}}

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We want to find

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What happens when we use direct substitution?

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1

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(A) The limit exists, and we found it!

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(B) The limit doesn't exist (probably an asymptote).

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(C) The result is indeterminate.

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