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Math Problems
Calculus
Find indefinite integrals using the substitution
/
△
A
′
B
′
C
′
_{\triangle}A^{\prime}B^{\prime}C^{\prime}
△
A
′
B
′
C
′
is a dilation of /
△
A
B
C
_{\triangle}ABC
△
A
BC
. What is the scale factor?
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∫
x
2
−
4
2
x
d
x
\int \frac{x^{2}-4}{2 \sqrt{x}} d x
∫
2
x
x
2
−
4
d
x
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⇒
\Rightarrow
⇒
\newline
int ism
\newline
thent
\newline
Strte
\newline
ite:
\newline
Astor:
\newline
SixuE
\newline
F
\newline
Elsonter
\newline
c.
\newline
Conolitieth gemes
\newline
Test Taks
\newline
My IXL
\newline
Learning
\newline
Assessment
\newline
Analy
\newline
th grade > W.
6
6
6
Surface area of cones
5
5
5
E
6
6
6
\newline
Learn with an example
\newline
or
\newline
Watch a video
\newline
What is the surface area of this cone?
\newline
Use
π
≈
3.14
\pi \approx 3.14
π
≈
3.14
and round your answer to the nearest hundredth.
\newline
□
\square
□
square inches
\newline
Submit
\newline
Work it out
\newline
Not feeling ready yet? These can help:
\newline
Area of circles
\newline
Lesson: Surface area
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Question
8
8
8
\newline
*
1
1
1
point
\newline
The point
A
(
3
,
5
)
A(3,5)
A
(
3
,
5
)
is mapped onto
A
′
(
3
,
−
5
)
A^{\prime}(3,-5)
A
′
(
3
,
−
5
)
by a transformation represented by the matrix
T
\mathrm{T}
T
. The matrix
T
\mathrm{T}
T
could be
\newline
(
1
0
1
1
)
(
1
−
1
0
1
)
\left(\begin{array}{ll} 1 & 0 \\ 1 & 1 \end{array}\right) \quad\left(\begin{array}{cc} 1 & -1 \\ 0 & 1 \end{array}\right)
(
1
1
0
1
)
(
1
0
−
1
1
)
\newline
A
\newline
B
\newline
(
−
1
0
0
−
1
)
(
1
0
0
−
1
)
\left(\begin{array}{rr} -1 & 0 \\ 0 & -1 \end{array}\right) \quad\left(\begin{array}{rr} 1 & 0 \\ 0 & -1 \end{array}\right)
(
−
1
0
0
−
1
)
(
1
0
0
−
1
)
\newline
C
\newline
D
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Substitution by parts: blem
10
10
10
\newline
t)
\newline
ate the indefinite integral.
\newline
)
\newline
x
sin
2
(
5
x
)
d
x
=
□
+
C
x \sin ^{2}(5 x) d x=\square+C
x
sin
2
(
5
x
)
d
x
=
□
+
C
.
\newline
Hint: Integrate by parts with
u
=
x
u=x
u
=
x
.
\newline
gauss.vaniercollege.qc.ca
\newline
gauss.vaniercollege.qc.ca
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Use the graph of the function to complete the table.
\newline
\begin{tabular}{|c|c|}
\newline
\hline input & output \\
\newline
\hline
−
9
-9
−
9
&
□
\square
□
\\
\newline
\hline
−
5
-5
−
5
&
□
\square
□
\\
\newline
\hline
−
3
-3
−
3
&
−
9
-9
−
9
\\
\newline
\hline
\newline
\end{tabular}
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∫
1
x
3
ln
x
d
x
\int \frac{1}{x^{3}}\ln x \, dx
∫
x
3
1
ln
x
d
x
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Question
6
6
6
\newline
*
1
1
1
point
\newline
Δ
L
M
N
\Delta \mathrm{LMN}
Δ
LMN
, below, is rotated anti-clockwise about
L
\mathrm{L}
L
through
9
0
∘
90^{\circ}
9
0
∘
. Which of the following is its likely image?
\qquad
\newline
A
\newline
A
\newline
\qquad
\newline
C
\newline
]
′
4
M
\sqrt{]^{\prime} 4^{M}}
]
′
4
M
\newline
D
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∫
(
8
x
+
8
x
)
d
x
\int\left(\frac{8}{\sqrt{x}}+8 \sqrt{x}\right) d x
∫
(
x
8
+
8
x
)
d
x
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https://www-awa.aleks.com/alekscgi///lsl.exe/
\newline
Unproctored Placement Assessment Question
9
9
9
\newline
Use the distributive property to rem
\newline
2
a
5
(
10
a
+
4
a
4
)
2 a^{5}\left(10 a+4 a^{4}\right)
2
a
5
(
10
a
+
4
a
4
)
\newline
Simplify your answer as much as po
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∫
Γ
(
e
2
2
⋅
(
2
2
+
1
)
)
d
z
\int_{\Gamma}\left(\frac{e^{2}}{2\cdot(2^{2}+1)}\right)dz
∫
Γ
(
2
⋅
(
2
2
+
1
)
e
2
)
d
z
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∫
Γ
e
2
z
⋅
(
2
2
+
1
)
d
z
\int_{\Gamma} \frac{e^{2}}{z \cdot\left(2^{2}+1\right)} d z
∫
Γ
z
⋅
(
2
2
+
1
)
e
2
d
z
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Part A
\newline
Indicate the order of reaction consistent with each observation.
\newline
Drag the appropriate items to their respective bins.
\newline
Zero order
\newline
A plot of the concentration of the reactant versus time yields a straight line.
\newline
Course Home
\newline
The
Blank
\text{Blank}
Blank
rate of
\newline
You can determi
\newline
A
(
′
′
)
A^{('')}
A
(
′′
)
\newline
E
^
\hat{E}
E
^
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ext{ extbackslash int extbackslash sqrt extbackslash left(}x^{
2
2
2
}+
1
1
1
ext{ extbackslash right)dx not using tangent}
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∫
x
2
+
1
d
x
\int \sqrt{x^{2}+1} d x
∫
x
2
+
1
d
x
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∫
(
x
−
3
e
3
x
)
d
x
\int\left(x-3 e^{3 x}\right) d x
∫
(
x
−
3
e
3
x
)
d
x
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Perform the division.
\newline
(
10
x
15
−
15
x
12
+
25
x
9
−
45
x
6
)
÷
(
5
x
18
)
(
10
x
15
−
15
x
12
+
25
x
9
−
45
x
6
)
÷
(
5
x
18
)
=
\begin{array}{l} \left(10 x^{15}-15 x^{12}+25 x^{9}-45 x^{6}\right) \div\left(5 x^{18}\right) \\ \left(10 x^{15}-15 x^{12}+25 x^{9}-45 x^{6}\right) \div\left(5 x^{18}\right)= \end{array}
(
10
x
15
−
15
x
12
+
25
x
9
−
45
x
6
)
÷
(
5
x
18
)
(
10
x
15
−
15
x
12
+
25
x
9
−
45
x
6
)
÷
(
5
x
18
)
=
\newline
□
\square
□
(Simplify your answer. Use integers or fractions for any numbers in the expression.)
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∫
1
x
x
+
1
d
x
\int \frac{1}{x \sqrt{x+1}} d x
∫
x
x
+
1
1
d
x
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Graph the parabola.
\newline
y
=
−
3
x
2
y=-3 x^{2}
y
=
−
3
x
2
\newline
Plot five points on the parab button.
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Math
233
233
233
\newline
Name:
\newline
Open with Kami
\newline
Quiz
\newline
Question
1
1
1
. Evaluate the triple integral
\newline
∫
−
a
a
∫
−
a
2
−
x
2
a
2
−
x
2
∫
z
=
0
z
=
h
d
z
d
y
d
x
\int_{-a}^{a} \int_{-\sqrt{a^{2}-x^{2}}}^{\sqrt{a^{2}-x^{2}}} \int_{z=0}^{z=h} d z d y d x
∫
−
a
a
∫
−
a
2
−
x
2
a
2
−
x
2
∫
z
=
0
z
=
h
d
z
d
y
d
x
\newline
whère
a
a
a
and
h
h
h
are arbitrary constants.
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Unit
4
4
4
: word problen
\newline
how to find the perii
\newline
examples of simple
\newline
The side lengths in yards of a triangle and a square are shown in the diagram.
\newline
The perimeter of the triangle is equal to the perimeter of the square. What is the value of
x
x
x
?
\newline
F
−
4
-4
−
4
\newline
G
2
3
\frac{2}{3}
3
2
\newline
H
6
6
6
\newline
3
3
3
5
2
\frac{5}{2}
2
5
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PROBLEM SOLVING
\newline
2
2
2
. In circle
K
K
K
, diameter
T
W
‾
\overline{T W}
T
W
intersects chord
R
S
‾
\overline{R S}
RS
at
X
X
X
such that m \overparen{S W}=38^{\circ} and m \overparen{W R}=98^{\circ} . Which of the following represents the measure of
∠
W
X
S
\angle W X S
∠
W
XS
?
\newline
(
1
1
1
)
5
2
∘
52^{\circ}
5
2
∘
\newline
(
3
3
3
)
6
8
∘
68^{\circ}
6
8
∘
\newline
(
2
2
2
)
6
0
∘
60^{\circ}
6
0
∘
\newline
(
4
4
4
)
T
W
‾
\overline{T W}
T
W
0
0
0
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Sazah.m
\newline
hing Equivalent
\newline
quivalent expression. Then write
\newline
7
x
3
(
2
x
+
5
)
21
x
\frac{7 x}{3(2 x+5)} 21 x
3
(
2
x
+
5
)
7
x
21
x
Get tutor help
Find the area of
\newline
the curved trapezoid bounded by the lines
y
=
3
x
+
6
y=3x+6
y
=
3
x
+
6
,
y
=
0
y=0
y
=
0
,
\newline
x
=
−
1
x=-1
x
=
−
1
,
x
=
2
x=2
x
=
2
. Use integration
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∫
5
ln
(
x
2
+
3
)
x
2
+
3
d
x
\int \frac{\sqrt{5} \ln \left(x^{2}+3\right)}{x^{2}+3} d x
∫
x
2
+
3
5
l
n
(
x
2
+
3
)
d
x
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Evaluate the integral
∫
x
+
3
4
x
+
4
d
x
\int \frac{x+3}{4 x+4} d x
∫
4
x
+
4
x
+
3
d
x
.
\newline
Choose
1
1
1
answer:
\newline
(A)
1
4
x
+
ln
∣
x
+
1
∣
+
C
\frac{1}{4} x+\ln |x+1|+C
4
1
x
+
ln
∣
x
+
1∣
+
C
\newline
(B)
1
4
x
+
2
ln
∣
x
+
1
∣
+
C
\frac{1}{4} x+2 \ln |x+1|+C
4
1
x
+
2
ln
∣
x
+
1∣
+
C
\newline
(C)
1
4
x
+
ln
∣
x
+
1
∣
2
+
C
\frac{1}{4} x+\frac{\ln |x+1|}{2}+C
4
1
x
+
2
l
n
∣
x
+
1∣
+
C
\newline
(D)
1
4
x
+
ln
∣
x
+
1
∣
4
+
C
\frac{1}{4} x+\frac{\ln |x+1|}{4}+C
4
1
x
+
4
l
n
∣
x
+
1∣
+
C
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g
(
x
)
=
∫
2
x
13
1
+
t
2
d
t
g
′
(
5
)
=
\begin{array}{l}g(x)=\int_{2}^{x} \frac{13}{1+t^{2}} d t \\ g^{\prime}(5)=\end{array}
g
(
x
)
=
∫
2
x
1
+
t
2
13
d
t
g
′
(
5
)
=
Get tutor help
OPEN UP HS MATH | MATH |
\newline
Tritan Somerame
\newline
NAME
\newline
DATE
\newline
Unit
6
6
6
Quick Quiz
1
1
1
: Lessons
1
1
1
−
4
-4
−
4
\newline
For problems
1
1
1
−
6
-6
−
6
, specify a transformation or sequence of transformations that fit with the verba description or the graphs showing the pre-image and image.
\newline
1
1
1
.
\newline
Tranbstelen
\newline
2
2
2
. A circular structure underlies the transformation.
\newline
∫
B
−
5
∫
y
x
\int_{B}^{-5} \int^{y} x
∫
B
−
5
∫
y
x
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∫
8
x
1
2
x
+
1
d
x
\int 8 x \frac{1}{2 x+1} d x
∫
8
x
2
x
+
1
1
d
x
Get tutor help
Domain and Range
\newline
The function
f
(
x
)
f(x)
f
(
x
)
is defined in the graph below. Using the graph, identify the Domain and Range of
f
(
x
)
f(x)
f
(
x
)
.
\newline
Write your answer as an ordered list enclosed in curly brackets.
\newline
Domain:
\newline
Range:
Get tutor help
(
3
3
3
) Triangles
A
B
C
A B C
A
BC
and
A
′
B
′
C
′
A^{\prime} B^{\prime} C^{\prime}
A
′
B
′
C
′
\newline
are similar. Write a proportion
\newline
that represents the
\newline
relationship between sides
A
B
A B
A
B
\newline
and
A
′
B
′
A^{\prime} B^{\prime}
A
′
B
′
and sides
A
C
A C
A
C
and
\newline
A
′
C
′
A^{\prime} C^{\prime}
A
′
C
′
.
\newline
8
8
8
.
3
3
3
A
Get tutor help
Evaluate the integral.
\newline
∫
p
(
p
+
4
)
5
d
p
\int p(p+4)^{5} d p
∫
p
(
p
+
4
)
5
d
p
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∫
x
+
1
x
−
1
d
x
\int \frac{x+1}{\sqrt{x}-1} d x
∫
x
−
1
x
+
1
d
x
Get tutor help
Wed
17
A
p
r
17 \mathrm{Apr}
17
Apr
\newline
Applications of integration: Unit test
\newline
What is the average value of
h
(
x
)
=
x
3
+
7
x
2
+
3
2
x
2
−
5
x
+
4
h(x)=\frac{x^{3}+7 x^{2}+3}{2 x^{2}-5 x+4}
h
(
x
)
=
2
x
2
−
5
x
+
4
x
3
+
7
x
2
+
3
on the interval
[
−
8
,
−
2
]
[-8,-2]
[
−
8
,
−
2
]
?
\newline
Use a graphing calculator and round your answer to three decimal places.
\newline
□
\square
□
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∫
9
x
2
x
3
−
1
d
x
\int 9 x^{2} \sqrt{x^{3}-1} d x
∫
9
x
2
x
3
−
1
d
x
Get tutor help
d
8025
8025
8025
/review/content/
6
6
6
f
1
1
1
c
6
6
6
c
1
1
1
f
−
1
-1
−
1
b
45
45
45
−
3
-3
−
3
de
9
9
9
-a
9
9
9
\newline
DUE
\newline
Apr
16
16
16
\newline
(The figure is not drawn to scale.)
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8
8
8
. Simplify the expression.
\newline
(
2
x
5
y
7
x
4
y
7
)
−
2
\left(\frac{2 x^{5} y^{7}}{x^{4} y^{7}}\right)^{-2}
(
x
4
y
7
2
x
5
y
7
)
−
2
\newline
type your answer... (no spaces and no negative exponents in the simplified answer)
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∫
1
26
x
x
d
x
\int \frac{1}{26 x \sqrt{x}} d x
∫
26
x
x
1
d
x
Get tutor help
Write the sum using sigma notation.
\newline
1
+
x
+
x
2
+
x
3
+
⋯
+
x
80
1+x+x^{2}+x^{3}+\cdots+x^{80}
1
+
x
+
x
2
+
x
3
+
⋯
+
x
80
\newline
Need Help?
\newline
Read it
Get tutor help
Find the area of an isosceles right triangle with hypotenuse
6
2
6\sqrt{2}
6
2
.
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2
2
2
.
∫
12
x
5
d
x
\int \frac{12}{x^{5}} d x
∫
x
5
12
d
x
Get tutor help
Expand
(
1
2
−
2
x
)
5
\left(\frac{1}{2}-2 x\right)^{5}
(
2
1
−
2
x
)
5
in ascending powers of
x
x
x
up to the term in
x
3
x^{3}
x
3
. If the coefficient of
x
2
x^{2}
x
2
in the binomial expansion of
(
1
+
a
x
+
3
x
2
)
(
1
2
−
2
x
)
5
\left(1+a x+3 x^{2}\right)\left(\frac{1}{2}-2 x\right)^{5}
(
1
+
a
x
+
3
x
2
)
(
2
1
−
2
x
)
5
is
13
2
\frac{13}{2}
2
13
find the coefficient of
x
3
x^{3}
x
3
.
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SEDERHANAKAN EKSPRESI SOAL DIBAWAH INI MENGGUNAKAN HK. EKIVALEN
\newline
1
1
1
. \(\newlineeg(B \wedge B) \rightarrow
\newline
eg
\newline
eg A \)
\newline
2
2
2
. \(\newlineeg(
\newline
eg A \vee(B \wedge A)) \)
\newline
3
3
3
. \(\newlineeg(
\newline
eg A \vee
\newline
eg(
\newline
eg A \vee
\newline
eg B) \)
\newline
4
4
4
. \(\newlineeg(B \wedge
\newline
eg B) \vee
\newline
eg(
\newline
eg A \rightarrow B) \)
Get tutor help
1
/
10
1 / 10
1/10
\newline
0
%
0 \%
0%
\newline
LBUSD ALGEBRA
1
1
1
UNIT
3
3
3
ASSESSMENT
\newline
NEXT
\newline
Enter an expression equivalent to
(
−
2
x
2
y
2
)
(
3
x
y
3
)
\left(-2 x^{2} y^{2}\right)\left(3 x y^{3}\right)
(
−
2
x
2
y
2
)
(
3
x
y
3
)
in the form
A
x
m
y
n
A x^{m} y^{n}
A
x
m
y
n
.
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Write the coordinates of the vertices after a reflection over the line
y
=
−
x
y=-x
y
=
−
x
.
\newline
B
′
(
□
,
□
)
B^{\prime}(\square, \square)
B
′
(
□
,
□
)
\newline
C
′
(
□
,
□
)
C^{\prime}(\square, \square)
C
′
(
□
,
□
)
\newline
D
′
(
□
,
□
)
D^{\prime}(\square, \square)
D
′
(
□
,
□
)
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∫
e
x
2
2
d
x
\int e^{\frac{x^{2}}{2}} d x
∫
e
2
x
2
d
x
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Homework: If the expanded form of a certain cubed binomial is the expression below, then what is
a
+
b
\mathrm{a}+\mathrm{b}
a
+
b
?
\newline
64
m
3
+
a
m
2
n
+
b
m
n
2
−
27
n
3
64 m^{3}+a m^{2} n+b m n^{2}-27 n^{3}
64
m
3
+
a
m
2
n
+
bm
n
2
−
27
n
3
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If
I
=
∫
d
x
sin
(
x
−
a
)
sin
(
x
−
b
)
I=\int \frac{\mathrm{d}x}{\sin(x-a)\sin(x-b)}
I
=
∫
s
i
n
(
x
−
a
)
s
i
n
(
x
−
b
)
d
x
, then
\newline
I
I
I
is given by
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\newline
The value of
\newline
∫
e
x
(
x
2
+
4
x
+
4
(
x
+
4
)
2
)
d
x
\int e^{x}\left(\frac{x^{2}+4x+4}{(x+4)^{2}}\right)dx
∫
e
x
(
(
x
+
4
)
2
x
2
+
4
x
+
4
)
d
x
is
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