Resources
Testimonials
Plans
Sign in
Sign up
Resources
Testimonials
Plans
Home
Math Problems
Algebra 2
Quadratic equation with complex roots
Find the zeros of the quadratic function using the square root method. What are the
x
x
x
-intercepts of the graph of the function?
\newline
g
(
x
)
=
(
x
−
3
)
2
−
1
g(x)=(x-3)^{2}-1
g
(
x
)
=
(
x
−
3
)
2
−
1
Get tutor help
Find the zeros of the following quadratic function using the square root method. What are the x-intercepts of the graph of the function?
\newline
f
(
x
)
=
x
2
−
50
f(x)=x^{2}-50
f
(
x
)
=
x
2
−
50
Get tutor help
Write the quadratic equation in standard form:
\newline
x
+
3
=
−
3
x
2
x+3=-3 x^{2}
x
+
3
=
−
3
x
2
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
−
4
x
2
+
x
+
24
=
4
-4 x^{2}+x+24=4
−
4
x
2
+
x
+
24
=
4
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
−
x
2
−
x
=
11
-x^{2}-x=11
−
x
2
−
x
=
11
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
3
x
2
−
x
−
16
=
4
3 x^{2}-x-16=4
3
x
2
−
x
−
16
=
4
\newline
Answer:
Get tutor help
Solve the equation by factoring:
\newline
3
x
3
−
9
x
2
−
12
x
=
0
3 x^{3}-9 x^{2}-12 x=0
3
x
3
−
9
x
2
−
12
x
=
0
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve the equation by factoring:
\newline
8
x
+
7
x
2
−
x
3
=
0
8 x+7 x^{2}-x^{3}=0
8
x
+
7
x
2
−
x
3
=
0
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve the equation by factoring:
\newline
x
3
−
2
x
2
−
48
x
=
0
x^{3}-2 x^{2}-48 x=0
x
3
−
2
x
2
−
48
x
=
0
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve the equation by factoring:
\newline
x
3
−
9
x
2
+
18
x
=
0
x^{3}-9 x^{2}+18 x=0
x
3
−
9
x
2
+
18
x
=
0
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve the equation by factoring:
\newline
x
3
−
8
x
2
−
9
x
=
0
x^{3}-8 x^{2}-9 x=0
x
3
−
8
x
2
−
9
x
=
0
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve the equation by factoring:
\newline
x
3
−
11
x
2
+
10
x
=
0
x^{3}-11 x^{2}+10 x=0
x
3
−
11
x
2
+
10
x
=
0
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve the equation by factoring:
\newline
8
x
+
6
x
2
−
2
x
3
=
0
8 x+6 x^{2}-2 x^{3}=0
8
x
+
6
x
2
−
2
x
3
=
0
\newline
Answer:
x
=
x=
x
=
Get tutor help
Write the quadratic equation in standard form:
\newline
8
x
−
19
=
5
x
2
8 x-19=5 x^{2}
8
x
−
19
=
5
x
2
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
x
2
+
1
=
8
x
x^{2}+1=8 x
x
2
+
1
=
8
x
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
6
x
−
9
=
−
5
x
2
6 x-9=-5 x^{2}
6
x
−
9
=
−
5
x
2
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
−
x
2
−
8
x
−
15
=
4
x
2
-x^{2}-8 x-15=4 x^{2}
−
x
2
−
8
x
−
15
=
4
x
2
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
7
x
+
3
=
3
x
2
7 x+3=3 x^{2}
7
x
+
3
=
3
x
2
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
−
x
2
+
x
+
10
=
−
3
x
2
-x^{2}+x+10=-3 x^{2}
−
x
2
+
x
+
10
=
−
3
x
2
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
−
4
x
+
19
=
4
x
2
-4 x+19=4 x^{2}
−
4
x
+
19
=
4
x
2
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
x
2
−
3
x
+
5
=
−
4
x
2
x^{2}-3 x+5=-4 x^{2}
x
2
−
3
x
+
5
=
−
4
x
2
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
5
x
2
−
5
x
−
14
=
x
5 x^{2}-5 x-14=x
5
x
2
−
5
x
−
14
=
x
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
−
4
x
2
−
6
x
=
−
6
-4 x^{2}-6 x=-6
−
4
x
2
−
6
x
=
−
6
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
2
x
2
−
3
x
−
13
=
−
2
2 x^{2}-3 x-13=-2
2
x
2
−
3
x
−
13
=
−
2
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
6
x
2
+
7
x
−
9
=
4
x
2
6 x^{2}+7 x-9=4 x^{2}
6
x
2
+
7
x
−
9
=
4
x
2
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
4
x
+
3
=
x
2
4 x+3=x^{2}
4
x
+
3
=
x
2
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
3
x
2
−
5
x
=
−
5
3 x^{2}-5 x=-5
3
x
2
−
5
x
=
−
5
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
5
x
2
+
4
x
−
16
=
−
4
5 x^{2}+4 x-16=-4
5
x
2
+
4
x
−
16
=
−
4
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
−
x
2
−
6
=
−
6
x
-x^{2}-6=-6 x
−
x
2
−
6
=
−
6
x
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
−
3
x
2
−
9
x
+
4
=
−
3
x
-3 x^{2}-9 x+4=-3 x
−
3
x
2
−
9
x
+
4
=
−
3
x
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
4
x
2
+
6
x
−
5
=
5
4 x^{2}+6 x-5=5
4
x
2
+
6
x
−
5
=
5
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
−
7
x
+
17
=
−
3
x
2
-7 x+17=-3 x^{2}
−
7
x
+
17
=
−
3
x
2
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
−
2
x
2
−
8
x
+
10
=
−
5
x
2
-2 x^{2}-8 x+10=-5 x^{2}
−
2
x
2
−
8
x
+
10
=
−
5
x
2
\newline
Answer:
Get tutor help
Write the quadratic equation in standard form:
\newline
2
x
2
+
2
=
7
x
2 x^{2}+2=7 x
2
x
2
+
2
=
7
x
\newline
Answer:
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
4
(
x
−
4
)
2
−
7
y=4(x-4)^{2}-7
y
=
4
(
x
−
4
)
2
−
7
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
−
2
(
x
+
4
)
2
+
4
y=-2(x+4)^{2}+4
y
=
−
2
(
x
+
4
)
2
+
4
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
7
(
x
−
2
)
2
+
2
y=7(x-2)^{2}+2
y
=
7
(
x
−
2
)
2
+
2
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
8
(
x
−
3
)
2
+
1
y=8(x-3)^{2}+1
y
=
8
(
x
−
3
)
2
+
1
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
−
9
(
x
+
3
)
2
−
4
y=-9(x+3)^{2}-4
y
=
−
9
(
x
+
3
)
2
−
4
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
4
(
x
−
1
)
2
+
4
y=4(x-1)^{2}+4
y
=
4
(
x
−
1
)
2
+
4
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
3
(
x
+
5
)
2
−
1
y=3(x+5)^{2}-1
y
=
3
(
x
+
5
)
2
−
1
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
−
9
(
x
−
3
)
2
+
3
y=-9(x-3)^{2}+3
y
=
−
9
(
x
−
3
)
2
+
3
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
−
(
x
−
5
)
2
+
6
y=-(x-5)^{2}+6
y
=
−
(
x
−
5
)
2
+
6
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
−
8
(
x
+
1
)
2
+
9
y=-8(x+1)^{2}+9
y
=
−
8
(
x
+
1
)
2
+
9
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
−
6
(
x
−
1
)
2
−
6
y=-6(x-1)^{2}-6
y
=
−
6
(
x
−
1
)
2
−
6
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
−
4
(
x
+
2
)
2
−
4
y=-4(x+2)^{2}-4
y
=
−
4
(
x
+
2
)
2
−
4
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
3
(
x
+
1
)
2
−
4
y=3(x+1)^{2}-4
y
=
3
(
x
+
1
)
2
−
4
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
4
(
x
+
3
)
2
+
6
y=4(x+3)^{2}+6
y
=
4
(
x
+
3
)
2
+
6
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
9
(
x
+
1
)
2
+
6
y=9(x+1)^{2}+6
y
=
9
(
x
+
1
)
2
+
6
\newline
Answer:
y
=
y=
y
=
Get tutor help
Re-write the quadratic function below in Standard Form
\newline
y
=
7
(
x
+
2
)
2
+
8
y=7(x+2)^{2}+8
y
=
7
(
x
+
2
)
2
+
8
\newline
Answer:
y
=
y=
y
=
Get tutor help
Previous
1
2
3
Next