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Re-write the quadratic function below in Standard Form

y=7(x-2)^(2)+2
Answer: 
y=

Re-write the quadratic function below in Standard Form\newliney=7(x2)2+2 y=7(x-2)^{2}+2 \newlineAnswer: y= y=

Full solution

Q. Re-write the quadratic function below in Standard Form\newliney=7(x2)2+2 y=7(x-2)^{2}+2 \newlineAnswer: y= y=
  1. Expand Squared Term: Expand the squared term (x2)2(x-2)^2.(x2)2=(x2)(x2)=x24x+4(x-2)^2 = (x-2)(x-2) = x^2 - 4x + 4
  2. Multiply by Coefficient: Multiply the expanded term by the coefficient 77.7(x24x+4)=7x228x+287(x^2 - 4x + 4) = 7x^2 - 28x + 28
  3. Add Constant Term: Add the constant term 22 to the expression.7x228x+28+2=7x228x+307x^2 - 28x + 28 + 2 = 7x^2 - 28x + 30
  4. Write in Standard Form: Write the final expression in standard form.\newliney=7x228x+30y = 7x^2 - 28x + 30

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