Re-write the quadratic function below in Standard Form y=8(x-3)^(2)+1 Answer: y=

Expand and Multiply: To rewrite the quadratic function in standard form, we need to expand the squared term (x-3)² and multiply it by 8, then add 1.Expand (x-3)²: First, expand (x-3)² to get x² - 6x + 9. (x-3)² = (x-3)(x-3) = x² - 3x - 3x + 9 = x² - 6x + 9Multiply by 8: Now, multiply the expanded form by 8. 8(x² - 6x + 9) = 8x² - 48x + 72Add 1: Finally, add 1 to the result of the multiplication. y = 8x² - 48x + 72 + 1Combine Like Terms: Combine like terms to get the standard form of the quadratic function. y = 8x² - 48x + 73

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Re-write the quadratic function below in Standard Form

y=8(x-3)^(2)+1
Answer:
y=

Re-write the quadratic function below in Standard Form $\newline$ $y=8(x-3)^{2}+1$ $\newline$ Answer: $y=$

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Quadratic equation with complex roots

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Q. Re-write the quadratic function below in Standard Form

\newline

y=8(x-3)^{2}+1

\newline

Answer:

y=

Expand and Multiply: To rewrite the quadratic function in standard form, we need to expand the squared term $(x-3)^2$ and multiply it by $8$ , then add $1$ .
Expand $(x-3)^2$ : First, expand $(x-3)^2$ to get $x^2 - 6x + 9$ .
$(x-3)^2 = (x-3)(x-3) = x^2 - 3x - 3x + 9 = x^2 - 6x + 9$
Multiply by $8$ : Now, multiply the expanded form by $8$ . $\newline$ $8(x^2 - 6x + 9) = 8x^2 - 48x + 72$
Add $1$ : Finally, add $1$ to the result of the multiplication. $\newline$ $y = 8x^2 - 48x + 72 + 1$
Combine Like Terms: Combine like terms to get the standard form of the quadratic function. $\newline$ $y = 8x^2 - 48x + 73$