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Algebra 2right chevron icon

Interpret confidence intervals for population means

Use the sample data and confidence level given below to complete parts (a) through (d).\newlineIn a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 26712671 subjects randomly selected from an online group involved with ears. 11581158 surveys were returned. Construct a 99% 99 \% confidence interval for the proportion of returned surveys.\newline国 Click the icon to view a table of z scores.\newlinea) Find the best point estimate of the population proportion p p .\newline□ \square \newline(Round to three decimal places as needed.)\newlineb) Identify the value of the margin of error E E .\newlineE= E= \newline(Round to three decimal places as needed.)\newlinec) Construct the confidence interval.\newline□ \square \newline(Round to three decimal places as needed.)
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Grace conducted a study to show how many hours her dog sleeps after having one or two hours of exercise. She set up a two-way table in four different ways. Which table will best represent Grace's data?\newline> 66 Hours of Sleep\newline11 Hour of Exercise\newlineTotal\newline< 66 Hours of Sleep\newline\newline22 Hours of Exercise\newline\newlineTotal\newline\newline\newline22 Hours of Exercise\newline< 66 Hours of Sleep\newlineTotal\newline11 Hour of Exercise\newline\newline\newline> 66 Hours of Sleep\newline\newlineTotal\newline\newline\newline11 Hours of Exercise\newline< 66 Hours of Sleep\newlineTotal\newline22 Hour of Exercise\newline\newline\newline> 66 Hours of Sleep\newline\newlineTotal\newline\newline\newline> 66 Hours of Sleep\newline< 66 Hours of Sleep\newlineTotal\newline11 Hour of Exercise\newline\newline22 Hours of Exercise\newline\newlineTotal
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A research assistant selected 7575 undergraduate students at random from the list of all students enrolled in the psychology-degree program at a large university. She asked each of the 7575 students, extbackslash{}“How many minutes per day do you typically spend reading? extbackslash{}” The mean reading time in the sample was 8989 minutes, and the margin of error for this estimate was 4.284.28 minutes. Another research assistant intends to replicate the survey and will attempt to get a smaller margin of error. Which of the following samples will most likely result in a smaller margin of error for the estimated mean time students in the psychology-degree program read per day?\newlineA) 4040 undergraduate psychology-degree program students selected at random\newlineB) 4040 undergraduate students selected at random from all degree programs at the university\newlineC) 300300 undergraduate psychology-degree program students selected at random\newlineD) 300300 undergraduate students selected at random from all degree programs at the university
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Find the average distance of each data value in the set from the mean.\newline11. Numbers of marbles in a bag: 25,42,61,33,45,50,34,42 25,42,61,33,45,50,34,42 \newline22. Square footages of homes: 2052,1250,2200,1856,1442 2052,1250,2200,1856,1442 \newlineFind and interpret the mean absolute deviation of the data. Round your answer to the nearest tenth, if necessary.\newline33. Numbers of Squares in a\newline44.\newline\begin{tabular}{|c|c|c|c|}\newline\hline \multicolumn{44}{|c|}{\begin{tabular}{c} \newlineNumbers of Desks in a \\\newlineClassroom\newline\end{tabular}} \\\newline\hline 2525 & 2525 & 2525 & 2525 \\\newline\hline 2525 & 2525 & 2525 & 2525 \\\newline\hline\newline\end{tabular}\newline55.\newline\begin{tabular}{|c|c|l|l|}\newline\hline \multicolumn{44}{|c|}{\begin{tabular}{c} \newlineHeights of Bleachers \\\newline(feet)\newline\end{tabular}} \\\newline\hline 110110 & 105105.44 & 9797.88 & 100100 \\\newline\hline 9898.66 & 112112.55 & 104104.66 & 9999.11 \\\newline\hline\newline\end{tabular}\newline66.\newline\begin{tabular}{|l|l|l|l|}\newline\hline \multicolumn{44}{|c|}{\begin{tabular}{c} \newlineWeights of Wrestlers \\\newline(pounds)\newline\end{tabular}} \\\newline\hline 131131.44 & 130130.77 & 131131.22 & 131131.88 \\\newline\hline 130130.66 & 131131.99 & 130130.11 & 129129.55 \\\newline\hline\newline\end{tabular}\newline77. The data shows the prices of five shirts and five pairs of pants.\newlineShirts: $15,$21,$18,$19,$24 \$ 15, \$ 21, \$ 18, \$ 19, \$ 24 \newlinePants: $25,$32,$40,$36,$29 \$ 25, \$ 32, \$ 40, \$ 36, \$ 29 \newlineFind the MAD of each data set. Then compare their variations.\newline88. Add or subtract the MAD from the mean in the data set in Exercise 55 .\newlinea. What percent of the values are within one MAD of the mean?\newlineb. What percent of the values are within two MADs of the mean?\newlinec. Which values are more than twice the MAD from the mean?\newlined. Find the range and interquartile range for the data set. Use these values to give a possible explanation for the answer to part (b).
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in africa\newlineAn arborist is marking different trees in the Kakamega Forest in Kenya, Africa, with colored ribbons around the trunks. Fill in the chart below to find out how much ribbon is needed for each type of tree.\newline\begin{tabular}{|c|c|c|c|c|c|}\newline\hline \begin{tabular}{c} \newlineRIBBON COLOR \& \\\newlineTREE TYPE\newline\end{tabular} & \begin{tabular}{c} \newlineLENGTH OF \\\newlineEACHRIBBON\newline\end{tabular} & \begin{tabular}{c} \newlineNUMBER OF \\\newlineTREES T00 \\\newlineBEMARKED\newline\end{tabular} & \begin{tabular}{c} \newlineTOTAL LENGTH \\\newlineOF RIBBON \\\newlineUSED\newline\end{tabular} & \begin{tabular}{c} \newlineRIBBON COST \\\newlinePER METER\newline\end{tabular} & TOTAL COST \\\newline\hline \begin{tabular}{c} \newlineRed - \\\newlineCeltis\newline\end{tabular} & 651/2 cm 651 / 2 \mathrm{~cm} & 55 & & $9 \$ 9 & \\\newline\hline \begin{tabular}{c} \newlineOrange - \\\newlineTrema\newline\end{tabular} & 541/4 cm 541 / 4 \mathrm{~cm} & 44 & & $10 \$ 10 & \\\newline\hline \begin{tabular}{c} \newlineGreen - \\\newlineAntiaris\newline\end{tabular} & 481/2 cm 481 / 2 \mathrm{~cm} & 22 & & $8 \$ 8 & \\\newline\hline \begin{tabular}{c} \newlineBlue - \\\newlineCroton\newline\end{tabular} & 601/2 cm 601 / 2 \mathrm{~cm} & 33 & & $14 \$ 14 & \\\newline\hline \begin{tabular}{c} \newlinePink - \\\newlineZanthoxylum\newline\end{tabular} & 321/4 cm 321 / 4 \mathrm{~cm} & 55 & & $7 \$ 7 & \\\newline\hline\newline\end{tabular}\newlineTOTAL COST OF RIBBON:
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44. Baby walkers are seats hanging from frames that allow babies to sit upright with their legs dangling and feet touching the floor. Walkers have wheels on their legs that allow the infant to propel the walker around the house long before he or she can walk or even crawl. Typically, babies use walkers between the ages of 44 months and 1111 months.\newlineBecause most walkers have tray tables in front that block babies' views of their feet, child psychologists have begun to question whether walkers affect infants' cognitive development. One study compared mental skills of a random sample of those who used walkers with a random sample of those who never used walkers. Mental skill scores averaged 113113 for 5454 babies who used walkers (standard deviation of 1212) and 123123 for 5555 babies who did not use walkers (standard deviation of 1515).\newline(a) Is there evidence that the mean mental skill score of babies who use walkers is different from the mean mental skill score of babies who do not use walkers? Explain your answer.
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Sweet Treats candy company wants to introduce a new flavor of jelly bean. They have three choices: Mango, Papaya, or Coconut. They decide to do a survey to determine which flavor their customers prefer. A random sample of 100100 Sweet Treats customers tried a free sample of all three flavors. The data showed that 55% 55 \% preferred Mango, 20% 20 \% preferred Papaya, and 25% 25 \% preferred Coconut.\newlineBased on this data, which of the following conclusions are valid?\newlineChoose 11 answer:\newline(A) 55% 55 \% of customers in this sample prefer Mango, but we cannot conclude anything about the population.\newline(B) About 55% 55 \% of all Sweet Treats customers prefer Mango.\newline(C) About 55% 55 \% of all adults prefer mango.
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In a poll of 1414,697697 randomly selected adults in the United States, those polled spent an average of $95 \$ 95 per day in November of last year, as compared with $91 \$ 91 per day in November two years ago. The estimates had a margin of error of $4 \$ 4 at the 95% 95 \% confidence level. Which of the following is a reasonable claim to make based on this sample?\newlineChoose 11 answer:\newline(A) All adults in the United States spent between $91 \$ 91 and $99 \$ 99 daily last November.\newline(B) 95% 95 \% of adults in the United States spent between $91 \$ 91 and $99 \$ 99 daily last November.\newline(C) It is plausible that average daily spending of adults in the United States remained the same in November of last year as it was in November two years ago.\newline(D) Between 91% 91 \% and $91 \$ 91 00 of adults in the United States spent $4 \$ 4 more daily last November than in November two years ago.
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An engineering student randomly sampled the train arrival times at a nearby train station. Based on the results, the student estimates that 92% 92 \% of the trains arrived within 22 minutes of their scheduled arrival times. The margin of error for this estimation is 3% 3 \% . Which of the following is the most appropriate conclusion about all train arrival times at the station, based on the given estimate and margin of error?\newlineChoose 11 answer:\newline(A) It is plausible that 89% 89 \% and 95% 95 \% of all trains arrive within 22 minutes of their scheduled arrival times.\newline(B) Exactly 92% 92 \% of all trains arrive within 55 minutes of their scheduled arrival times.\newline(C) The student is 3% 3 \% sure that most trains arrive within 22 minutes of their scheduled arrival times.\newline(D) The student is 97% 97 \% sure that exactly 92% 92 \% of all trains arrive within 22 minutes of their scheduled arrival times.
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11. Allowance for Uncollectible Accounts\newline22. Copyrights\newline33. Land\newline44. Merchandise Inventory\newline55. Amortization\newline66. Petty Cash\newline77. Accumulated Depreciation-Equipment\newline88. Office Equipment\newline99. Accounts Payable\newline1010. Buildings\newline1111. Delivery Equipment\newline1212. Patents\newline1313. Income Summary\newline1414. Transportation In\newline1515. Supplies\newline1616. Prepaid Insurance\newlineGroup 22\newlineConsider the following information about a plant asset for questions 1919 , and write the correct amounts on your answer sheet. The comp calendar year end.\newline\begin{tabular}{|l|r|}\newline\hline Original Cost & $75,000 \$ 75,000 \\\newline\hline Disposal Value & $6,000 \$ 6,000 \\\newline\hline Date Purchased & 01−01−15 01-01-15 \\\newline\hline Estimated Useful Life & 55 years \\\newline\hline Depreciation Method & ? ? \\\newline\hline Accumulated Depreciation as of 1212−31-31−17-17 & 5858,800800 \\\newline\hline Asset Sold Date & 12−31−18 12-31-18 \\\newline\hline Asset Sold for & $10,000 \$ 10,000 \\\newline\hline\newline\end{tabular}\newline1717. What is the amount of depreciation expense for the year 2018? 2018 ? \newline88. What is the amount of gain or loss on the sale of the asset?\newline99. For this question only, consider that the asset was not sold. What is th amount of depreciation expense for the year 20192019 ?
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The quiz scores for the students in two math dasses are recorded. The line plats below show the 99 scores for each dass.\newlineComplete the fallowing.\newline(a) The mean for Class A is 1313 points, and the mean for Class B is 55 points. Find the distance between the means of Class A and Class B.\newlineDistance between the means: □ \square point(s)\newline(b) Find the mean absolute deviation (MAD) for each class.\newlineMAD for Class A: □ \square point(s)\newlineMAD for Class B: □ \square point(s)\newline(c) Fill in the blank below to express the distance between the means as a multiple of the MAD of either data set.\newlineDistance between the means =∏ =\prod times the MAD\newline(d) Look at the degree of averlap between the data sets.\newlineAlso look at your answer from part (c).\newlineThen select the best chaice belaw.\newlineThere is a complete overlap and the distance between the means is 00 .\newlineThere is a complete overlap and the distance between the means is greater than 55 times the MAD.\newlineThere is some averlap and the distance between the means is between 11 times the MAD and 55 times the MAD.\newlineThere is some overlap and the distance between the means is between 00 and 11 times the MAD.\newlineThere is no owerlap and the distance between the means is greater than 55 times the MAD.\newlineThere is no overlap and the distance between the means is between 11 times the MAD and 55 times the MAD.
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A cell phone company is thinking about opening a store in Millersburg. To help the company make a decision, its marketing department conducted a survey about cell phone ownership in the city. A total of 875875 randomly chosen Millersburg households participated in the survey. From the survey results, market researchers at the phone company calculated a 95%95\% confidence interval of for the mean number of cell phones owned by households in Millersburg.\newlineIs the following conclusion valid?\newlineIf 100100 more surveys are conducted (each using a sample with members chosen randomly and independently), it is expected that exactly 100100 of them will each produce a 95%95\% confidence interval that contains its sample mean.\newlineChoices:\newline(A)yes\newline(B)no\newline
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11. In a survey of 20352035 workers, 73% 73 \% reported working out 33 or more days a week. What is the margin of error? What is the interval that is likely to contain the exact percent of all people who work out 33 or more days a week? Show all work.
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uestion 66 of 88\newlinePrevious question\newline0/1 0 / 1 \newlineurrent Attempt in Progress\newlineIncorrect.\newlineAverage Penalty Minutes in the NHL An interval estimate was constructed for mean penalty minutes given to NHL players in a seas using data from players on the Ottawa Senators as our sample. Some percentiles from a bootstrap distribution of 50005000 sample mean are shown below.\newline\begin{tabular}{ccccccccccc}\newline\hline & 0.5% 0.5 \% & 1.0% 1.0 \% & 2.0% 2.0 \% & 2.5% 2.5 \% & 5.0% 5.0 \% & 95.0% 95.0 \% & 97.5% 97.5 \% & 98.0% 98.0 \% & 99.0% 99.0 \% & 0.5% 0.5 \% 00 \\\newline\hline Percentile & 1313.77 & 1414.33 & 1515.33 & 1515.66 & 1616.99 & 3232.88 & 3434.44 & 3535.00 & 3636.77 & 3737.88 \\\newline\hline\newline\end{tabular}\newlineUse this information to find a 0.5% 0.5 \% 11 confidence interval for the mean penalty minutes of NHL players. Assume that the players on this team are a reasonable sample from the population of all players.\newlineEnter the exact answers.\newlineThe 0.5% 0.5 \% 11 confidence interval is 0.5% 0.5 \% 33 to 0.5% 0.5 \% 33 2525.2525\newlineeTextbook and Media\newlineHint
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A child psychologist believes that children perform better on tests when they are given perceived freedom of choice. To test this belief, the psychologist carried out an experiment in which third graders were randomly assigned to two groups, A and B. Each child was given the same simple logic test. However, in group B, each child was given the freedom to choose a text booklet from many with various drawings on the covers. The performance of each child was rated as Very Good, Good, and Fair. The results are summarized in the table provided. Test, at the 55\% level of significance, whether there is sufficient evidence in the data to support the psychologist's belief.\newline\begin{tabular}{|l|l|l|l|}\newline\hline \multicolumn{22}{c}{} & \multicolumn{22}{c|}{ Group } \\\newline\hline \multicolumn{22}{|c|}{ A } & B \\\newline\hline \multirow{22}{*}{\begin{tabular}{l} \newlinePerformanc\newline\end{tabular}} & Very Good & 3232 & 2929 \\\newline\cline { 22 - 44 } & Good & 5555 & 5151 \\\newline\cline { 22 - 44 } & Fair & 1010 & 1313 \\\newline\hline\newline\end{tabular}
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