Resources
Testimonials
Plans
Sign in
Sign up
Resources
Testimonials
Plans
Home
Math Problems
Algebra 2
Csc, sec, and cot of special angles
Heron's Formula: Unit test
\newline
The area of the triangle with sides
11
c
m
,
9
c
m
11 \mathrm{~cm}, 9 \mathrm{~cm}
11
cm
,
9
cm
and
12
c
m
12 \mathrm{~cm}
12
cm
is of the form
y
35
c
m
2
y \sqrt{35} \mathrm{~cm}^{2}
y
35
cm
2
.
\newline
Find the value of
y
y
y
.
\newline
□
\square
□
Get tutor help
Heron's Formula: Unit test
\newline
The area of the triangle with sides
11
c
m
,
9
c
m
11 \mathrm{~cm}, 9 \mathrm{~cm}
11
cm
,
9
cm
and
12
c
m
12 \mathrm{~cm}
12
cm
is of the form
y
35
c
m
2
y \sqrt{35} \mathrm{~cm}^{2}
y
35
cm
2
.
\newline
Find the value of
y
y
y
.
\newline
□
\square
□
Get tutor help
Heron's Formula: Unit test
\newline
The area of the triangle with sides
11
c
m
,
9
c
m
11 \mathrm{~cm}, 9 \mathrm{~cm}
11
cm
,
9
cm
and
12
c
m
12 \mathrm{~cm}
12
cm
is of the form
y
35
c
m
2
y \sqrt{35} \mathrm{~cm}^{2}
y
35
cm
2
.
\newline
Find the value of
y
y
y
.
\newline
□
\square
□
Get tutor help
Heron's Formula: Unit test
\newline
The area of the triangle with sides
6
c
m
,
8
c
m
6 \mathrm{~cm}, 8 \mathrm{~cm}
6
cm
,
8
cm
and
4
c
m
4 \mathrm{~cm}
4
cm
is of the form
c
15
c
m
2
c \sqrt{15} \mathrm{~cm}^{2}
c
15
cm
2
.
\newline
Find the value of
c
c
c
.
\newline
□
\square
□
Get tutor help
square root of
11
11
11
simplified
Get tutor help
x
=
3
x
\sqrt{x}=\sqrt{3 x}
x
=
3
x
\newline
What is the solution to the given equation?
\newline
□
\square
□
Get tutor help
lim
(
x
,
y
)
→
(
4
,
−
5
)
e
4
x
2
+
1
y
2
=
\lim _{(x, y) \rightarrow(4,-5)} e^{\sqrt{4 x^{2}+1 y^{2}}}=
lim
(
x
,
y
)
→
(
4
,
−
5
)
e
4
x
2
+
1
y
2
=
Get tutor help
(
4
7
)
2
=
\left(\dfrac{4}{7}\right)^2=
(
7
4
)
2
=
Get tutor help
(
1
9
−
2
)
2
=
\left(\dfrac{1}{9-2}\right) ^2=
(
9
−
2
1
)
2
=
Get tutor help
Considere la regi\'on
E
E
E
, del primer cuadrante, limitada por las rectas de ecuaciones:
z
=
9
−
x
2
z = 9 - x^2
z
=
9
−
x
2
;
y
=
4
y = 4
y
=
4
. a. Grafique la regi\'on
E
E
E
y descr\'ibala en forma ordenada. b. Plantee la integral doble que permite hallar el \'area de la regi\'on
E
E
E
.
Get tutor help
Sclesaikan key burikut dan netoda PERT:
\newline
Tentukan:
\newline
a.
t
e
×
σ
2
t_{e} \times \sigma^{2}
t
e
×
σ
2
masing
Get tutor help
Khan Academy
\newline
Express the radical using th Express your answer in simpli
\newline
±
−
81
=
±
\pm \sqrt{-81}= \pm
±
−
81
=
±
Get tutor help
5
−
5
5
8
=
\dfrac{5^{-5}}{5^{8}}=
5
8
5
−
5
=
Get tutor help
Simplify. Remove all perfect squares from inside the square root. Assume
a
a
a
is positive.
108
a
6
=
\sqrt{108a^6}=
108
a
6
=
Get tutor help
2
2
2
. Westley puede usar la computadora de su casa
295
295
295
minutos cada semana. Cinco días de la semana usa la computadora
30
30
30
minutos por día. Piensa que aún tiene
265
265
265
minutos para usar la computadora el sábado y el domingo.
Get tutor help
Evaluate. Write your answer in simplified, rationalized forms. Do not round.
\newline
sin
90
0
∘
\sin 900^\circ
sin
90
0
∘
\newline
cos
90
0
∘
\cos 900^\circ
cos
90
0
∘
\newline
tan
90
0
∘
\tan 900^\circ
tan
90
0
∘
Get tutor help
108
a
6
=
\sqrt{108a^6}=
108
a
6
=
Get tutor help
d
d
x
(
2
x
+
3
(
x
−
4
)
2
)
=
\frac{d}{dx}\left(\frac{2x+3}{(x-4)^{2}}\right)=
d
x
d
(
(
x
−
4
)
2
2
x
+
3
)
=
Get tutor help
12
t
=
4
v
−
3
−
6
t
=
4
v
+
6
\begin{aligned} 12t &= 4v - 3 \ -6t &= 4v + 6 \end{aligned}
12
t
=
4
v
−
3
−
6
t
=
4
v
+
6
Get tutor help
Simplify the expression using the order of operations.
90
÷
(
10
−
7
)
2
=
90\div(10-7)^2 =
90
÷
(
10
−
7
)
2
=
90
÷
2
=
90\div 2 =
90
÷
2
=
90
÷
=
90\div =
90
÷
=
Get tutor help
Simplify.
\newline
Remove all perfect squares from inside the square roots. Assume
\newline
x
x
x
and
\newline
z
z
z
are positive.
\newline
72
x
3
z
3
=
□
\sqrt{72x^{3}z^{3}}=\square
72
x
3
z
3
=
□
Get tutor help
(
sin
x
+
sinh
x
)
d
x
(\sin x+\sinh x) d x
(
sin
x
+
sinh
x
)
d
x
=
Get tutor help
If
x
2
−
y
2
=
x
+
y
x^{2}-y^{2}=x+y
x
2
−
y
2
=
x
+
y
, then
x
−
y
=
x-y=
x
−
y
=
Get tutor help
If
x
2
−
a
=
(
x
−
3
)
(
x
+
3
)
x^{2}-a=(x-3)(x+3)
x
2
−
a
=
(
x
−
3
)
(
x
+
3
)
, then
a
=
a=
a
=
Get tutor help
e
2
+
3
i
e^2+3i
e
2
+
3
i
can be written in the form of
a
+
b
i
a+bi
a
+
bi
Get tutor help
27
÷
3
2
×
3
2
×
2
−
3
=
27 \div 3^{2} \times 3^{2} \times 2-3=
27
÷
3
2
×
3
2
×
2
−
3
=
Get tutor help
Given
\newline
5
5
5
. that
△
A
B
C
≅
△
D
E
F
\triangle A B C \cong \triangle D E F
△
A
BC
≅
△
D
EF
. If
m
A
B
‾
=
2
x
+
5
m \overline{A B}=2 x+5
m
A
B
=
2
x
+
5
,
m
D
E
‾
=
3
(
6
+
y
)
m \overline{D E}=3(6+y)
m
D
E
=
3
(
6
+
y
)
,
m
E
F
‾
=
1
+
y
m \overline{E F}=1+y
m
EF
=
1
+
y
and
m
B
C
‾
=
3
y
−
x
m \overline{B C}=3 y-x
m
BC
=
3
y
−
x
what is the lenght of
m
E
F
‾
\overline{m E F}
m
EF
?
Get tutor help
Richard makes a number
7
7
7
by cutting out a rectangle and a parallelogram.
\newline
Find the area of the number
7
7
7
.
\newline
Area
=
=
=
□
\square
□
c
m
2
\mathrm{cm}^{2}
cm
2
Get tutor help
Evaluate. Write your answer as a whole number or as a simplified fraction.
\newline
2
9
2
7
=
\frac{2^{9}}{2^{7}}=
2
7
2
9
=
Get tutor help
Managed favorites
\newline
New folder
\newline
Whole Numbers and Integers
\newline
Multiplicative property of equally with integers
\newline
Solve for
y
y
y
.
\newline
−
y
5
=
−
30
-\frac{y}{5}=-30
−
5
y
=
−
30
\newline
Simplify your answer as much as possible.
\newline
y
=
y=
y
=
Get tutor help
. Find the perimeter in yards of a rectangle that is
18
y
d
.
1
f
t
18 \mathrm{yd} .1 \mathrm{ft}
18
yd
.1
ft
. by
27
y
d
27 \mathrm{yd}
27
yd
Reduce
36
100
\frac{36}{100}
100
36
to lowect terme
Get tutor help
Q
(
x
,
y
)
=
x
0
,
2
y
0
,
9
Q(x, y) = x^{0,2}y^{0,9}
Q
(
x
,
y
)
=
x
0
,
2
y
0
,
9
a) Essa fun\c{c}\~ao de produ\c{c}\~ao possui rendimentos crescentes, constantes ou decrescente de escala? Por qu\^e?
Get tutor help
19
19
19
.
(
8
+
12
)
(
48
+
18
)
=
(\sqrt{8}+\sqrt{12})(\sqrt{48}+\sqrt{18})=
(
8
+
12
)
(
48
+
18
)
=
Get tutor help
oblems.
\newline
7
7
7
.
−
19
+
(
7
+
4
)
3
=
-19+(7+4)^{3}=
−
19
+
(
7
+
4
)
3
=
Get tutor help
Simplifying the Expression:
2
π
J
(
1
+
(
e
−
J
3
)
)
=
2\pi J\left(1+\left(\frac{e^{-J}}{3}\right)\right)=
2
π
J
(
1
+
(
3
e
−
J
)
)
=
Get tutor help
2
π
/
1
+
e
−
J
2
=
2 \pi / 1+\frac{e^{-J}}{2}=
2
π
/1
+
2
e
−
J
=
Get tutor help
u
−
4
=
−
u
+
34
u-4=\sqrt{-u+34}
u
−
4
=
−
u
+
34
Get tutor help
Find the following trigonometric values.
\newline
Express your answers exactly.
\newline
cos
(
22
5
∘
)
=
\cos \left(225^{\circ}\right)=
cos
(
22
5
∘
)
=
\newline
□
\square
□
\newline
sin
(
22
5
∘
)
=
\sin \left(225^{\circ}\right)=
sin
(
22
5
∘
)
=
\newline
□
\square
□
Get tutor help
(i)
f
(
t
)
=
1
+
t
1
−
t
f(t)=\frac{1+\sqrt{t}}{1-\sqrt{t}}
f
(
t
)
=
1
−
t
1
+
t
Get tutor help
1
1
1
.
1
−
sin
2
θ
1
+
cos
θ
=
cos
θ
1-\frac{\sin ^{2} \theta}{1+\cos \theta}=\cos \theta
1
−
1
+
c
o
s
θ
s
i
n
2
θ
=
cos
θ
Get tutor help
d
y
d
x
=
1
x
\frac{d y}{d x}=\frac{1}{x}
d
x
d
y
=
x
1
and
y
(
e
)
=
−
2
y(e)=-2
y
(
e
)
=
−
2
.
\newline
y
(
e
3
)
=
y\left(e^{3}\right)=
y
(
e
3
)
=
Get tutor help
Let
y
=
x
e
x
y=\sqrt{x} e^{x}
y
=
x
e
x
.
\newline
d
y
d
x
=
\frac{d y}{d x}=
d
x
d
y
=
Get tutor help
d
d
x
[
cos
(
x
)
x
2
]
=
\frac{d}{d x}\left[\cos (x) x^{2}\right]=
d
x
d
[
cos
(
x
)
x
2
]
=
Get tutor help
d
d
x
(
e
x
cos
(
x
)
)
=
\frac{d}{d x}\left(e^{x} \cos (x)\right)=
d
x
d
(
e
x
cos
(
x
)
)
=
Get tutor help
If
2
a
=
2
4
9
2^{a}=\sqrt[9]{2^{4}}
2
a
=
9
2
4
, what is the value of
a
a
a
?
\newline
◻
Get tutor help
1
0
∘
,
∠
M
B
A
=
2
0
∘
,
∠
M
A
C
=
1
0
∘
10^{\circ}, \angle M B A=20^{\circ}, \angle M A C=10^{\circ}
1
0
∘
,
∠
MB
A
=
2
0
∘
,
∠
M
A
C
=
1
0
∘
si
∠
M
C
A
=
3
0
∘
\angle M C A=30^{\circ}
∠
MC
A
=
3
0
∘
. Denonstrati el triungtial ARC este inowert.
Get tutor help
Di sebuah toples terdapat
65
65
65
permen dengan rincian:
\newline
•
15
15
15
permen cokelat,
\newline
•
7
7
7
permen stroberi,
\newline
•
10
10
10
permen vanila,
\newline
•
8
8
8
permen jeruk,
\newline
•
10
10
10
permen kopi,
\newline
•
15
15
15
permen karamel.
\newline
Semua permen memiliki bungkus yang sama dan identik. Anda diminta untuk mengambil sejumlah permen dengan syarat setidaknya Anda memperoleh tiga permen dengan rasa yang sama (contohnya, Anda mungkin memperoleh:
3
3
3
permen cokelat; atau
3
3
3
permen stroberi; dan lain-lain). Paling sedikit, berapa banyak permen yang harus Anda ambil jika pengambilan dilakukan secara acak?
Get tutor help
arccos
(
θ
)
=
(
−
17
38
×
3
)
\arccos (\theta)=\left(\frac{-17}{\sqrt{38} \times 3}\right)
arccos
(
θ
)
=
(
38
×
3
−
17
)
Get tutor help
cot
x
+
sin
x
1
+
cos
x
=
csc
x
:
\cot x+\frac{\sin x}{1+\cos x}=\csc x:
cot
x
+
1
+
c
o
s
x
s
i
n
x
=
csc
x
:
Get tutor help
Evaluate. Write your answer as a whole number or as a simplified fraction.
\newline
3
7
3
5
=
\frac{3^{7}}{3^{5}}=
3
5
3
7
=
Get tutor help
1
2
3
...
5
Next