Resources
Testimonials
Plans
Sign in
Sign up
Resources
Testimonials
Plans
Home
Math Problems
Algebra 2
Csc, sec, and cot of special angles
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
cot
2
θ
−
1
=
0
\cot ^{2} \theta-1=0
cot
2
θ
−
1
=
0
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
9
cot
2
θ
−
1
=
0
9 \cot ^{2} \theta-1=0
9
cot
2
θ
−
1
=
0
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
cos
2
θ
−
2
cos
θ
=
0
\cos ^{2} \theta-2 \cos \theta=0
cos
2
θ
−
2
cos
θ
=
0
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
4
cos
2
θ
−
9
=
0
4 \cos ^{2} \theta-9=0
4
cos
2
θ
−
9
=
0
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
6
tan
2
θ
=
13
tan
θ
+
8
6 \tan ^{2} \theta=13 \tan \theta+8
6
tan
2
θ
=
13
tan
θ
+
8
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
9
sin
2
θ
+
sin
θ
=
−
2
sin
θ
+
2
9 \sin ^{2} \theta+\sin \theta=-2 \sin \theta+2
9
sin
2
θ
+
sin
θ
=
−
2
sin
θ
+
2
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
−
4
sin
2
θ
−
6
sin
θ
+
4
=
−
9
sin
θ
+
3
-4 \sin ^{2} \theta-6 \sin \theta+4=-9 \sin \theta+3
−
4
sin
2
θ
−
6
sin
θ
+
4
=
−
9
sin
θ
+
3
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
4
cos
2
θ
+
17
cos
θ
+
7
=
5
cos
θ
+
2
4 \cos ^{2} \theta+17 \cos \theta+7=5 \cos \theta+2
4
cos
2
θ
+
17
cos
θ
+
7
=
5
cos
θ
+
2
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
−
7
sin
2
θ
−
4
sin
θ
+
2
=
−
1
-7 \sin ^{2} \theta-4 \sin \theta+2=-1
−
7
sin
2
θ
−
4
sin
θ
+
2
=
−
1
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
9
tan
2
θ
+
19
tan
θ
=
−
2
9 \tan ^{2} \theta+19 \tan \theta=-2
9
tan
2
θ
+
19
tan
θ
=
−
2
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
4
tan
2
θ
+
3
tan
θ
−
1
=
3
tan
θ
4 \tan ^{2} \theta+3 \tan \theta-1=3 \tan \theta
4
tan
2
θ
+
3
tan
θ
−
1
=
3
tan
θ
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
8
sin
2
θ
−
11
sin
θ
−
6
=
−
9
sin
θ
−
3
8 \sin ^{2} \theta-11 \sin \theta-6=-9 \sin \theta-3
8
sin
2
θ
−
11
sin
θ
−
6
=
−
9
sin
θ
−
3
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
−
6
tan
2
θ
−
16
tan
θ
=
−
9
tan
θ
+
2
-6 \tan ^{2} \theta-16 \tan \theta=-9 \tan \theta+2
−
6
tan
2
θ
−
16
tan
θ
=
−
9
tan
θ
+
2
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
2
sin
2
θ
−
2
sin
θ
=
−
3
sin
θ
+
1
2 \sin ^{2} \theta-2 \sin \theta=-3 \sin \theta+1
2
sin
2
θ
−
2
sin
θ
=
−
3
sin
θ
+
1
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
9
cos
2
θ
+
3
cos
θ
=
8
cos
θ
+
4
9 \cos ^{2} \theta+3 \cos \theta=8 \cos \theta+4
9
cos
2
θ
+
3
cos
θ
=
8
cos
θ
+
4
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
−
5
tan
2
θ
−
3
tan
θ
+
6
=
−
5
tan
θ
+
3
-5 \tan ^{2} \theta-3 \tan \theta+6=-5 \tan \theta+3
−
5
tan
2
θ
−
3
tan
θ
+
6
=
−
5
tan
θ
+
3
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
Find all angles,
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
, that satisfy the equation below, to the nearest tenth of a degree.
\newline
−
5
sin
2
θ
−
3
=
2
sin
θ
−
6
-5 \sin ^{2} \theta-3=2 \sin \theta-6
−
5
sin
2
θ
−
3
=
2
sin
θ
−
6
\newline
Answer:
θ
=
\theta=
θ
=
Get tutor help
(
5
x
2
−
4
)
1
/
4
=
x
\left(5 x^{2}-4\right)^{1 / 4}=x
(
5
x
2
−
4
)
1/4
=
x
Get tutor help
Divide the polynomials.
\newline
Your answer should be a polynomial.
\newline
3
x
5
−
x
x
=
\frac{3 x^{5}-x}{x}=
x
3
x
5
−
x
=
Get tutor help
Write
(
3
+
2
i
)
2
(3+2 i)^{2}
(
3
+
2
i
)
2
in simplest
a
+
b
i
a+b i
a
+
bi
form.
\newline
Answer:
Get tutor help
Write
(
1
−
3
i
)
3
(1-3 i)^{3}
(
1
−
3
i
)
3
in simplest
a
+
b
i
a+b i
a
+
bi
form.
\newline
Answer:
Get tutor help
Write
(
1
−
10
i
)
2
(1-10 i)^{2}
(
1
−
10
i
)
2
in simplest
a
+
b
i
a+b i
a
+
bi
form.
\newline
Answer:
Get tutor help
Write
(
9
−
2
i
)
2
(9-2 i)^{2}
(
9
−
2
i
)
2
in simplest
a
+
b
i
a+b i
a
+
bi
form.
\newline
Answer:
Get tutor help
Write
(
2
+
3
i
)
3
(2+3 i)^{3}
(
2
+
3
i
)
3
in simplest
a
+
b
i
a+b i
a
+
bi
form.
\newline
Answer:
Get tutor help
y
=
−
(
x
+
3
)
2
+
5
y=-(x+3)^2+5
y
=
−
(
x
+
3
)
2
+
5
y
=
x
+
6
y=x+6
y
=
x
+
6
Get tutor help
What is the value of the expression below when
w
=
3
w=3
w
=
3
?
\newline
3
w
2
−
8
w
+
7
3 w^{2}-8 w+7
3
w
2
−
8
w
+
7
\newline
Answer:
Get tutor help
Решите уравнение
tg
x
=
3
/
3
\operatorname{tg} x=\sqrt{3} / 3
tg
x
=
3
/3
:
Get tutor help
Evaluate. Write your answer as a whole number or as a simplified fraction.
\newline
5
6
5
3
=
\frac{5^{6}}{5^{3}}=
5
3
5
6
=
Get tutor help
Using implicit differentiation, find
d
y
d
x
\frac{d y}{d x}
d
x
d
y
.
\newline
y
cos
(
2
x
−
4
y
)
=
−
2
x
y
−
4
y \cos (2 x-4 y)=-2 x y-4
y
cos
(
2
x
−
4
y
)
=
−
2
x
y
−
4
Get tutor help
Using implicit differentiation, find
d
y
d
x
\frac{d y}{d x}
d
x
d
y
.
\newline
−
2
x
3
y
4
−
x
y
2
=
x
+
3
-2 x^{3} y^{4}-x y^{2}=x+3
−
2
x
3
y
4
−
x
y
2
=
x
+
3
Get tutor help
75
y
z
2
=
\sqrt{75 y z^{2}}=
75
y
z
2
=
Get tutor help
∫
1
+
cos
x
d
x
=
\int \sqrt{1+\cos x} d x=
∫
1
+
cos
x
d
x
=
Get tutor help
c)
Sin
4
5
∘
=
cos
.
?
\operatorname{Sin} 45^{\circ}=\cos . ?
Sin
4
5
∘
=
cos
.
?
Get tutor help
\begin{aligned}6x+2y&=3\6x+y &= 3\end{aligned}
Get tutor help
Use la calculadora gráfica de ALEKS para resolver la ecuaclón.
\newline
e
2
x
=
x
+
2
e^{2 x}=x+2
e
2
x
=
x
+
2
\newline
Redondear a la centésima más cercana.
\newline
SI hay más de una solución, sepárelas con comas.
\newline
x
=
x=
x
=
Get tutor help
Reduce
\newline
(
a
+
b
)
2
(a+b)^{2}
(
a
+
b
)
2
Get tutor help
b
(
n
)
=
−
1
(
2
)
n
−
1
b(n) = -1 \left(2\right)^{n - 1}
b
(
n
)
=
−
1
(
2
)
n
−
1
Get tutor help
Rewrite using a positive exponent.
\newline
n
−
5
n^{-5}
n
−
5
\newline
n
−
5
=
n^{-5} =
n
−
5
=
Get tutor help
Distribute to create an equivalent expression with the fewest symbols possible.
(
1
−
2
g
+
4
h
)
⋅
5
=
( 1 -2g +4h)\cdot 5 =
(
1
−
2
g
+
4
h
)
⋅
5
=
Get tutor help
Evaluate
∑
m
≥
1
arctan
(
1
m
)
=
\sum_{m \geq 1}\arctan\left(\frac{1}{\sqrt{m}}\right)=
∑
m
≥
1
arctan
(
m
1
)
=
Get tutor help
Find
d
y
d
x
:
y
=
csc
(
2
x
4
+
6
)
\frac{dy}{dx}: y=\csc(2x^{4}+6)
d
x
d
y
:
y
=
csc
(
2
x
4
+
6
)
Get tutor help
[
arctan
e
x
]
0
∞
\left[\arctan e^{x}\right]_{0}^{\infty}
[
arctan
e
x
]
0
∞
=
Get tutor help
y
≥
−
1
y
≤
4
x
+
1
\begin{aligned} y &\geq -1 \ y &\leq 4x+1 \end{aligned}
y
≥
−
1
y
≤
4
x
+
1
Get tutor help
ESTRELLA SANTANA CEPEDA
\newline
ESTREUA SANTANA CEPEDA
\newline
WWW-awt.aleks.com/alekscgi/x/lsl.exe/
10
10
10
.
\newline
Funciones exponenciales y logaritmicas
\newline
Resolver una ecuaci\u00f3n exponencial usando logaritmos:
\newline
Resolver para
\newline
X
X
X
.
\newline
5
(
x
−
9
)
=
1
2
(
10
x
)
5^{(x-9)}=12^{(10x)}
5
(
x
−
9
)
=
1
2
(
10
x
)
\newline
Redondear la respuesta a la mil\u00e9sima m\u00e1s cercana. No redondar los c\u00e1lculos intermedios.
\newline
x
=
x=
x
=
Get tutor help
x
+
3
y
=
2
4
x
−
3
y
=
23
\begin{aligned} x+3y&=2 \ 4x-3y&=23 \end{aligned}
x
+
3
y
=
2
4
x
−
3
y
=
23
Get tutor help
2
x
+
3
y
=
−
8
3
y
2
−
8
y
=
2
x
+
10
\begin{aligned} 2x+3y&=-8\ 3y^2-8y&=2x+10 \end{aligned}
2
x
+
3
y
=
−
8
3
y
2
−
8
y
=
2
x
+
10
Get tutor help
Find an angle
θ
\theta
θ
coterminal to
−
94
2
∘
-942^{\circ}
−
94
2
∘
, where
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
.
\newline
Answer:
Get tutor help
Find an angle
θ
\theta
θ
coterminal to
69
8
∘
698^{\circ}
69
8
∘
, where
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
.
\newline
Answer:
Get tutor help
Find an angle
θ
\theta
θ
coterminal to
111
9
∘
1119^{\circ}
111
9
∘
, where
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
.
\newline
Answer:
Get tutor help
Find an angle
θ
\theta
θ
coterminal to
79
2
∘
792^{\circ}
79
2
∘
, where
0
∘
≤
θ
<
36
0
∘
0^{\circ} \leq \theta<360^{\circ}
0
∘
≤
θ
<
36
0
∘
.
\newline
Answer:
Get tutor help
Previous
1
...
2
3
4
...
5
Next