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Write the equation of the parabola that passes through the points (6,15)(-6, -15), (1,0)(-1,0), and (7,0)(-7,0). Write your answer in the form y=a(xp)(xq)y=a(x-p)(x-q), where aa, pp, and qq are integers, decimals, or simplified fractions.

Full solution

Q. Write the equation of the parabola that passes through the points (6,15)(-6, -15), (1,0)(-1,0), and (7,0)(-7,0). Write your answer in the form y=a(xp)(xq)y=a(x-p)(x-q), where aa, pp, and qq are integers, decimals, or simplified fractions.
  1. Identify roots of parabola: Identify the values of pp and qq from the given points where the parabola crosses the x-axis, which are the roots of the parabola. Points (1,0)(-1, 0) and (7,0)(-7, 0) indicate that p=1p = -1 and q=7q = -7.
  2. Formulate standard form equation: Formulate the equation of the parabola using the standard form y=a(xp)(xq)y = a(x - p)(x - q). Substituting p=1p = -1 and q=7q = -7, we get y=a(x+1)(x+7)y = a(x + 1)(x + 7).
  3. Substitute point to find aa: Substitute the point (6,15)(-6, -15) into the equation to find the value of aa. Plugging in x=6x = -6 and y=15y = -15, we get 15=a(6+1)(6+7)-15 = a(-6 + 1)(-6 + 7).
  4. Solve for aa: Simplify and solve for aa. The equation becomes 15=a(5)(1)–15 = a(–5)(–1), which simplifies to 15=5a–15 = 5a. Solving for aa gives a=15/5=3a = –15 / 5 = –3.
  5. Write final equation: Write the final equation of the parabola using the values of aa, pp, and qq. Substituting a=3a = -3, p=1p = -1, and q=7q = -7 into y=a(xp)(xq)y = a(x - p)(x - q) gives y=3(x+1)(x+7)y = -3(x + 1)(x + 7).

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