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Write the equation in vertex form for the parabola with vertex (0,0)(0,0) and focus (0,6)(0,6).\newlineSimplify any fractions.\newline______

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Q. Write the equation in vertex form for the parabola with vertex (0,0)(0,0) and focus (0,6)(0,6).\newlineSimplify any fractions.\newline______
  1. Identify Vertex Form: Identify the vertex form of a parabola.\newlineVertex form: y=a(xh)2+ky = a(x-h)^2+k
  2. Determine Parabola Direction: Given vertex (0,0)(0,0) and focus (0,6)(0,6), determine the direction of the parabola.\newlineSince the focus is above the vertex, the parabola opens upwards.
  3. Calculate Distance for 'a': Calculate the distance between the vertex and the focus to find the value of 'a'.\newlineDistance = 60=6|6 - 0| = 6\newlineThe distance is the same as 14a\frac{1}{4a}, so 14a=6\frac{1}{4a} = 6.
  4. Solve for 'a': Solve for 'a'.\newlinea=14×6a = \frac{1}{4 \times 6}\newlinea=124a = \frac{1}{24}
  5. Substitute Values into Equation: Substitute the values of aa, hh, and kk into the vertex form equation.h=0h = 0, k=0k = 0, and a=124a = \frac{1}{24}.y=(124)(x0)2+0y = \left(\frac{1}{24}\right)(x-0)^2+0y=(124)x2y = \left(\frac{1}{24}\right)x^2

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