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What is the vertex of the parabola y−8x2=4y - 8x^2 = 4? \newline(_,_)(\_,\_)

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Find properties of a parabola from equations in general formright chevron icon

Full solution

Q. What is the vertex of the parabola y−8x2=4y - 8x^2 = 4? \newline(_,_)(\_,\_)
  1. Find Vertex x-coordinate: Now, we need to find the x-coordinate of the vertex. The vertex form of a parabola is y=a(x−h)2+ky = a(x-h)^2 + k, where (h,k)(h, k) is the vertex. Since there's no (x−h)2(x-h)^2 term here, h=0h = 0.
  2. Find Vertex y-coordinate: Next, we plug x=0x = 0 into the equation to find the y-coordinate of the vertex.y=8(0)2+4y = 8(0)^2 + 4y=4y = 4
  3. Vertex Coordinates: So, the vertex of the parabola is at (0,4)(0, 4).

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