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What is the vertex of the parabola y=−4(x−2)2+2y = -4(x - 2)^2 + 2??\newline(_,_)(\_,\_)

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Q. What is the vertex of the parabola y=−4(x−2)2+2y = -4(x - 2)^2 + 2??\newline(_,_)(\_,\_)
  1. Identify vertex form: Identify the vertex form of a parabola.\newlineThe vertex form of a parabola is y=a(x−h)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Compare given equation: Compare the given equation y=−4(x−2)2+2y = -4(x - 2)^2 + 2 with the vertex form to find the values of hh and kk. The given equation is already in vertex form, so we can directly read off the values of hh and kk. h=2h = 2 and k=2k = 2
  3. Find values of hh and kk: Write the vertex of the parabola using the values of hh and kk. The vertex of the parabola is (h,k)(h, k), which is (2,2)(2, 2) in this case.

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